# Tips And Tricks And Shortcuts For Quadratic Equations

## Unlocking Tips, Tricks, and Shortcuts for Quick Solutions

Explore an invaluable resource for effortlessly tackling quadratic equations with finesse. Our comprehensive guide unveils a treasure trove of proven strategies, smart shortcuts, and expert tips that will elevate your quadratic equation-solving prowess.

### Tips and shortcuts to solve the Quadratic Equation questions

• In order to find the sign of roots we use sign given in the equation.
Sign of coefficient ‘x’ Sign of coefficient ‘y’ Sign of roots
+ + –          –
+ –          +
+ +         +
+         –

For example: x2 + 3x – 4 = 0

The factors are 4 and 1

Now will find the sign of roots. According to the table, if sign given in the equation is + and – then their sign of roots is – and +. Therefore, the roots of the equation are -4 and 1

### Type 1: Tricks and Shortcuts for Quadratic Questions

• When one equation has positive roots and other has negative, or equations has same sign roots, then compare the roots and find the relation between them.

Question 1:

Find the correct option given below by solving the following equation  x2 – 7x + 10 = 0 and y2 + 8y + 15 = 0

Options:

A. x < y B. x > y C. x ≤ y D. x ≥ y E. cannot be determined

Solution:     x2 – 7x + 10 = 0…. (1)

Roots of first equation are 5 and 2

Using the table above, we will find the sign of roots. If sign given in the equation is – and + then their sign of roots is + and +

Therefore, the roots of the equation are 5 and 2

Now, y2 + 8y + 15 = 0 ……. (2)

Roots of second equation are 3 and 5

If sign given in the equation is + and + then their sign of roots is – and –

Therefore, the roots of the equation are -3 and – 2

Now, here roots are +x1, + x2, – y1, and – y2

This clearly shows that X roots are positive and Y roots are negative. So, x> y

Correct option: B

### Type 2: Tips and Tricks To Solve Quadratic Equations Questions

• When roots of the equation are positive and negative and we cannot find the relation between them.

Question 2:

Find the correct option given below by solving the following equation 6x2 + 11x – 35 = 0 and  6y2 + 5y – 6 = 0

Options:

A. x < y B. x > y C. x ≤ y D. x ≥ y E. cannot be determined

Solution:     6x2 + 11x – 35 = 0…. (1)

Roots of first equation are 3.5 and 1.66

Using the table above, we will find the sign of roots. If sign given in the equation is + and – then their sign of roots is – and +

Therefore, the roots of the equation are – 3.5 and 1.66

Now, 6y2 + 5y – 6 = 0 ……. (2)

Roots of second equation are 1.5 and 0.66

If sign given in the equation is + and – then their sign of roots is – and +

Therefore, the roots of the equation are – 1.5 and 0.66

Now, here roots are -x1, + x2, – y1, and + y2

It means x2> – y1 and –x1< + y2

So, we cannot determine which roots are greater.

Correct option: E

### Type 3: Tips and Tricks and Shortcuts for Quadratic Questions

• When we can find a equation where x is a variable and a, b, and c represent constants and D, i.e., Discriminant.

The discriminant is the part of the quadratic formula underneath the square root symbol: b²-4ac. Question 3:

Find the Discriminant and roots of the following equation: 3x2 − 5x − 7 = 0.

Solution:

Let us find Discriminant, D = $\sqrt{B^{2}-4AC}$

D = $\sqrt{(-5)^{2}-4(3)(-7)}$

D = 109

Therefore, $x = \frac{-b \pm \sqrt{}D}{2a}$

x = $\frac{5 \pm \sqrt{}109}{6}$

x = $\frac{5 \pm 10.44}{6}$

x =$\frac{15.44}{6} => x = 2.57$, and

x = $\frac{-5.44}{6} => x = – 0.90$

So the two roots are 2.57 and -0.90

### Some more Questions:

Question 4:

Which method is used to solve quadratic equations that cannot be easily factored or involve complex coefficients?

A) Factoring

C) Completing the Square

D) Estimation

Explanation:

The correct answer is option B. The quadratic formula is a universal method used to solve any quadratic equation, regardless of its coefficients or factorability. It provides precise solutions by directly calculating the roots.

Question 5:

For the quadratic equation 3x² + 6x – 9 = 0, what are the roots?

A) x = 1

B) x = -1

C) x = -3

D) x = 3

Explanation:

The correct answer is option C. Divide the entire equation by 3 to simplify it: x² + 2x – 3 = 0. This equation can be factored as (x – 1)(x + 3) = 0. Setting each factor to zero gives x – 1 = 0 and x + 3 = 0. Solving for “x” in both equations yields x = 1 and x = -3. Therefore, the roots are x = -3 and x = 1.

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