DXC Technology Placement Papers 2019-20

Get here DXC Technology Placement papers with solutions for your recruitment test. You will get

  • DXC  Technology curriculum pattern with Most repeated questions of similar pattern of DXC Technology and
  • DXC Technology sample question papers that were asked in DXC Technologies Previous year paper.

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DXC Placement Papers 2018-19

Difficulty Level

Sections

4

Time

60mins

Adaptive/Non Adaptive

No

Negative Marking

No

Applicant: 150000

Job opening: 10000/ year

Curriculum

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DXC Technologies Placement Selection Process

Sapient Nitro written test paper and latest curriculum are available that will help you in Sapient online exam 2019.

  • Quants
    • Number of Questions - 15 Questions
    • Time - 15 mins
  • English
    • Number of Questions - 15 Questions
    • Time - 15 mins
  • Logical
    • Number of Questions - 15 Questions
    • Time - 15mins
  • Technical/Computer Programming
    • Number of Questions - 15 Question
    • Time - 15mins

DXC Technology has four written sections :

  • Written Rounds(Quantitative +Verbal+Logical Reasoning+Computer Programming)
  • Technical Round
  • HR Round

All Branches – English Usage + Analytical Reasoning + Numerical Reasoning

  • Ques – 15 each
  • Total Time – 45 mins + 25 mins(WET)

Written English Test (WET) – Essay type question. Need to Write an article in 25 mins.

Branch Specific – English Usage + Analytical Reasoning + Numerical Reasoning + Domain Module (20 min)

  • Ques – 15 each/20 for Domain Module
  • Total time – 45 mins+ 25 mins(WET) +20 mins (Domain Module)

DXC Technology Placement Paper with Latest Solutions

DXC Syllabus No. Of Questions Time Difficulty Cut Off
Quants 15 15 Medium 80 percentile
Logical 15 15 Hard 80 percentile
English 15 15 Medium 80 percentile
Computer Programming 15 15 Hard 75 percentile
DXC latest placement paper

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To know more about Logical

DXC Technology QUESTIONS WITH ANSWERS LOGICAL REASONING

Difficulty Level: Easy - high
Importance: Moderate
Suggested time to solve: 55secs - 1min 20secs

dxc previous year paper with solutions

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To know more about Verbal

DXC Technology MOST REPEATED QUESTION PAPERS VERBAL ENGLISH

Difficulty Level: Easy-Medium
Importance: High
Suggested time to solve: 40secs - 1min 30secs

dxc previous year paper with solutions

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To know more about Technical

DXC Technology Latest Questions Paper 2019 COMPUTER PROGRAMMING

  • C/C++/Java Concepts
  • Computer Fundamentals
  • Operating Systems
  • Data Structures
  • DBMS

Difficulty Level: Medium
Importance: Easy - High
Suggested time to solve: 40secs - 60secs

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DXC Technology questions answers

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DXC Quants Dashboard

Difficulty Level: Med-High
Importance: Medium
Suggested time to solve: 1min each

Question #1

What would be the ratio of milk and water in a final mixture formed by mixing milk and water that are present in three vessels of capacity 1l, 2l, and 3l respectively and in the ratios 5:1, 3:2 and 4:3 respectively?

  • A

    747:443

    747:443 14.29%
  • B

    747:443

    747:443 28.57%
  • C

    787:473

    787:473 42.86%
  • D

    747:473

    747:473 14.29%
  • PrepInsta Explanation

Solve this type of questions by taking 2 at a time. Take the first 2 vessels,
In 1st, fraction of milk = 56
In 2nd, fraction of milk = 35
Therefore,
CAT Question - Ratio and Proportion 13
=> 3/5−xx−5/6 = 12
=> 65 - 2x = x - 56
=> 65 + 56 = 3x
=> x = 6190 (And the volume of mixture after mixing = 1 + 2 = 3 l)
Therefore,
CAT Question - Ratio and Proportion 13-2
=> 4/7−xx−61/90 = 33
=> 4/7 - x = x + 6190
=> 4/7 + 6190 = 2x
=> 2x = 787/630 => x = 787/1260
Therefore, Milk : Water = 787/(1260−787) = 787/473

Question #2

Solve :(x–4)(x+3)/(x+4)(x+5) > 0?

  • A

    x ∊ (-∞,-1] ∪ [√3, 3)

    x ∊ (-∞,-1] ∪ [√3, 3) 12.5%
  • B

    x ∊ (-∞,-3] ∪ [√3, ∞)

    x ∊ (-∞,-3] ∪ [√3, ∞) 12.5%
  • C

    x ∊ (-4,-3) ∪ (4, ∞)

    x ∊ (-4,-3) ∪ (4, ∞) 62.5%
  • D

    x ∊ (-8,-3] ∪ [2, ∞)

    x ∊ (-8,-3] ∪ [2, ∞) 12.5%
  • PrepInsta Explanation

(x–4)(x+3)/(x+4)(x+5) > 0
Consider this as ab > 0
Here both a > 0 & b > 0 or a < 0 & b < 0

Case 1: (x – 4) (x + 3) > 0 & (x + 4) ( x +5) > 0
x > 4 , x > -3, x > -4 , x > -5
Combining all we get x > 4

Case 2: (x – 4)(x + 3) < 0 & (x + 4) ( x +5) < 0
x < 4, x < -3, x < -4, x < -5
Combining all x < -5
Hence range is (-∞,-5) ∪ (4, ∞)

Question #3

Pipe A, B and C are kept open and together fill a tank in t minutes. Pipe A is kept open throughout, pipe B is kept open for the first 10 minutes and then closed. Two minutes after pipe B is closed, pipe C is opened and is kept open till the tank is full. Each pipe fills an equal share of the tank. Furthermore, it is known that if pipe A and B are kept open continuously, the tank would be filled completely in t minutes. How long will it take C alone to fill the tank ?

  • A

    18

    18 40%
  • B

    36

    36 20%
  • C

    27

    27 20%
  • D

    24

    24 20%
  • PrepInsta Explanation

A is kept open for all t minutes and fills one-third the tank. Or, A should be able to fill the entire tank in \'3t\' minutes.
A and B together can fill the tank completely in t minutes. A alone can fill it in 3t minutes.
A and B together can fill 1t of the tank in a minute. A alone can fill 13t of the tank in a minute. So, in a minute, B can fill 1t - 13t = 23t. Or, B takes 3t2 minutes to fill an entire tank.
To fill one-third the tank, B will take t2 minutes. B is kept open for t - 10 minutes.
t2 = t - 10, t = 20 minutes.
A takes 60 minutes to fill the entire tank, B takes 30 minutes to fill the entire tank. A is kept open for all 20 minutes. B is kept open for 10 minutes.
C, which is kept open for 8 minutes also fills one-third the tank. Or, C alone can fill the tank in 24 minutes.

Question #4

Find the area of the region that comprises all points that satisfy the two conditions x2 + y2 + 6x + 8y ≤ 0 and 4x ≥ 3y?

  • A

    25π

    25π 20%
  • B

    25π/4

    25π/4 20%
  • C

    25π/2

    25π/2 40%
  • D

    None of these

    None of these 20%
  • PrepInsta Explanation

x2 + y2 + 6x + 8y < 0
x2 + 6x + 9 – 9 + y2 + 8y + 16 – 16 < 0
(x + 3)2 + (y + 4)2 < 25

This represents a circular region with centre (–3, –4) and radius 5 units. Substituting x = y = 0, we also see that the inequation is satisfied. This means that the circle also passes through the origin. To find out the intercepts that the circle cuts off with the axes, substitute x = 0 to find out the y–intercept and y = 0 to find out x–intercept. Thus x–intercept = –6 and y–intercept = –8.

CAT : Geometry: Coordinate Geometry Circle

Now, the line 4x = 3y passes through the point (–3, –4). Or this line is the diameter of the circle. The area we are looking for is the area of a semicircle.
Required area = 25π/2

Question #5

How many pairs of positive integers x, y exist such that HCF (x, y) + LCM (x, y) = 91?

  • A

    10

    10 16.67%
  • B

    8

    8 33.33%
  • C

    7

    7 33.33%
  • D

    6

    6 16.67%
  • PrepInsta Explanation

Let us x = h * a; y = h * b
a and b are co-prime. So, LCM of (x, y) = h * a * b

So, in essence h + h * a * b = 91. Or h(ab + 1) = 91
Now, 91 can be written as 1 * 91 or 7 * 13
Or, we can have HCF as 1, LCM as 90 -
There are 4 pairs of numbers like this (2, 45), (9, 10), (1, 90) and (5, 18)

We can have HCF as 7, ab + 1 = 13 => ab = 12 => 1 * 12 or 4 * 3

Or, the pairs of numbers are (7, 84) or (21, 28)

The third option is when HCF = 13, ab + 1 = 7 => ab = 6
Or (a, b) can be either (1, 6) or (2, 3)
The pairs possible are (13, 78) and (26, 39)
There are totally 8 options possible - (2, 45), (9, 10), (1, 90), (5, 18), (7, 84), (21, 28), (13, 78) and (26, 39).
8 Pairs.

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Question #1

Directions for Ques 1 to 2:

Six techies- A,B,C,D,E,F attended a Tech-conference in Mumbai. Each of them was working in differnt companies Microsoft, Yahoo, Google, FB, Cisco, TCS in any order and each of them attended the conference on a different day among- Monday, Tuesday, Wednesday, Thrusday, Friday, Saturday not necessarily in the same order. The following information is also given:

  1. A attended the con ferenceon Monday and the person who works in Microsoft  attended the conference on Saturday.

  2. B and D attended the conference on the consecutive days.

  3. Exactly one person attended the conference between E and C and C was working in Google.

  4. F was working in Yahoo.

  5. C attended the conference on the next day of FB employee.

  6. The person who was working in Cisco attended the conference on Friday.

Which of the following person was working in TCS?

 

  • A

    B

    B 33.33%
  • B

    C

    C 33.33%
  • C

    D

    D 16.67%
  • D

    E

    E 16.67%
  • PrepInsta Explanation

Monday        A

Tuesday        E/C

Wednesday   F         Yahoo

Thrusday      C/E

Friday           B/D      Cisco

Saturday       D/B     Microsoft

From Statement 5:

Day        Person     Company

Monday      A                   FB

Tuesday      C               Google

Wednesday F               Yahoo

Thrusday     E                TCS

Friday         B/D            Cisco

Saturday     D/B        Microsoft

Question #2

Which of the following person attended the conference on Friday?

  • A

    E

    E 20%
  • B

    D

    D 20%
  • C

    B

    B 20%
  • D

    Cannot be determined

    Cannot be determined 40%
  • PrepInsta Explanation

Monday        A

Tuesday        E/C

Wednesday   F         Yahoo

Thrusday      C/E

Friday           B/D      Cisco

Saturday       D/B     Microsoft

From Statement 5:

Day        Person     Company

Monday      A                   FB

Tuesday      C               Google

Wednesday F               Yahoo

Thrusday     E                TCS

Friday         B/D            Cisco

Saturday     D/B        Microsoft

Question #3

Direction for Ques 3 to 6:

A quiz has three rounds of two questions each. In the first round, each correct answer carries 20 points;each incorrect answers carries a penalty of 10. If both the questions are answered correctly, a bonus of 10 points is awarded. In the second round, each correct and incorrect answer carries the same number of points as in the first round. However, an additional penalty of 10 points is awarded if both the questions were answered incorrectly. In the third round,  each correct answer is awarded with 40 marks and an incorrect one carries a penalty of 20 points.

In how many ways can a score of 40 be achieved in the quiz?

  • A

    4

    4 25%
  • B

    2

    2 25%
  • C

    1

    1 25%
  • D

    3

    3 25%
  • PrepInsta Explanation

Solution:

40 can be scored by:


  1. 50-30+20=40

  2. 10+10+20=40


Hence 2 is the correct answer.

Question #4

What is the probability of scoring 100 in the quiz?

  • A

    2/9

    2/9 25%
  • B

    4/27

    4/27 25%
  • C

    2/27

    2/27 25%
  • D

    1/9

    1/9 25%
  • PrepInsta Explanation

There are 3x3x3=27 possible scores. Out of these 3 there are only 2 ways of scoring 100. Hence 2/27 is the answer.

Question #5

If two answers are incorrect, the minimum possible score is:

  • A

    50

    50 40%
  • B

    70

    70 20%
  • C

    60

    60 20%
  • D

    80

    80 20%
  • PrepInsta Explanation

The maximum penalty for 2 incorrect answers would occur when they happen in the last round. Hence the score would be 50+50-40=60

Question #6

If only two answers were correct, what is the probability that the score would be 20?

  • A

    1/3

    1/3 50%
  • B

    1/6

    1/6 25%
  • C

    2/3

    2/3 25%
  • PrepInsta Explanation

There are only two ways of scoring 20 that is 50+10-40 or 10+50-40. In both the cases there are three right answers. Hence the required probability is zero.

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Question #1

Choose the word which close to opposite of the word:

BLASPHEMOUS

  • A

    irreligious

    irreligious 42.86%
  • B

    inferior

    inferior 14.29%
  • C

    reverent

    reverent 14.29%
  • D

    blarney

    blarney 28.57%
  • PrepInsta Explanation

Currently there is no PrepInsta Explanation.

Question #2

INSIPID : PIQUANT : :

  • A

    tasty : bland

    tasty : bland 20%
  • B

    relish : spice

    relish : spice 20%
  • C

    sweet : dessert

    sweet : dessert 40%
  • D

    flat : spicy

    flat : spicy 20%
  • PrepInsta Explanation

Solution: Relation of opposites

Question #3

Fill in the blanks:

......... and ecstasy are two sides of a puzzle called life.

  • A

    pain

    pain 16.67%
  • B

    penury

    penury 16.67%
  • C

    agony

    agony 16.67%
  • D

    anguish

    anguish 16.67%
  • E

    elation

    elation 33.33%
  • PrepInsta Explanation

Currently there is no PrepInsta Explanation.

Question #4

The first line [A] and the last line [f] of each question are fixed. Arrange the other four lines in a logical sequence:

A. But Obama, while acknowledging that Detroit's auto majors would see the move as an added burden on an ailing industry in the short term, made clear that the way forward wa to embrace green technology.

B. Such that political commitment to fight climate change seems lacking in India. Attempts to set fuel emission standards have been stymied by inter-agency squabbling on exactly how much norms should be set.

C. It was only with the recent intervention of the Prime Minister's Office that a consensus was reached.

D. Fuel economy regulations will go some way in reducing India's import bill since we import 78 per cent of our oil.

E. In doing so, he has sent a clear signal that his administration is preparedto act on climate change even in the face of opposition from interest groups such as the car industry.

F. The government should follow Obama's example and act quickly to fight climate change and cut oil imports.

  • A

    DEBC

    DEBC 16.67%
  • B

    EBDC

    EBDC 33.33%
  • C

    EBCD

    EBCD 16.67%
  • D

    DBCE

    DBCE 16.67%
  • E

    ECDB

    ECDB 16.67%
  • PrepInsta Explanation

Currently there is no PrepInsta Explanation.

Question #5

Choose the correct sequence:

(I)I'm no different.

(II)When I was diagnosed with breast cancer, some years ago, Ihad surgery several times,  and also chemotherapy and radiotherapy.

(III)Today now that I have recovered fully, I thank them all to have bee there for me and have saved my life. If it were not because of them I would have not been writing this.

(IV)The sheer number of individual professionals I encountered was huge- maybe 100, over the years.

(V) When you have undergone intensive NHS treatment, it's routine to feel greatful to the NHS staff who saved your life.

  • A

    V I II IV III

    V I II IV III 20%
  • B

    I II III IV V

    I II III IV V 20%
  • C

    II I III V IV

    II I III V IV 40%
  • D

    None of these

    None of these 20%
  • PrepInsta Explanation

Currently there is no PrepInsta Explanation.

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DXC Technology Latest Questions Paper 2019 COMPUTER PROGRAMMING

  • C/C++/Java Concepts
  • Computer Fundamentals
  • Operating Systems
  • Data Structures
  • DBMS

Difficulty Level: Medium
Importance: Easy - High
Suggested time to solve: 40secs - 60secs

 

Q- Given an array arr[] of N non-negative integers representing height of blocks at index i as Ai where the width of each block is 1. Compute how much water can be trapped in between blocks after raining.
Structure is like below:
|  |
|_|
We can trap 2 units of water in the middle gap.

Bars of Input {3,0,0,2,0,4}

Total Trapped Water= 3+3+1+3= 10

Input:
The first line of input contains an integer T denoting the number of test cases. The description of T test cases follows. Each test case contains an integer N denoting the size of the array, followed by N space separated numbers to be stored in array.

Output:
Output the total unit of water trapped in between the blocks.

Constraints:
1 <= T <= 100
3 <= N <= 107
0 <= Ai <= 108

Example:
Input:
2
4
7 4 0 9
3
6 9 9

Output:
10
0

Explanation:
Testcase 1: Water trapped by block of height 4 is 3 units, block of height 0 is 7 units. So, total unit of water trapped is 10 units.

Solution :

int maxi(int arr[],int ind,int n){
int max=arr[ind];
for(int i=ind+1;i<n;i++){
if(arr[i]>max) max=arr[i];
}
return max;
}
int main() {
//code
int t; cin>>t;
while(t--){
int n; cin>>n; int arr[n];
for(int i=0;i<n;i++) cin>>arr[i];
if(n<2){
cout<<0<<endl;
continue;
}
int lmax=arr[0],rmax=maxi(arr,1,n),sum=0;
for(int i=1;i<n;i++){
if(arr[i]>lmax) lmax=arr[i];
if(arr[i]==rmax and i<n-1)
rmax=maxi(arr,i+1,n);
int h=min(lmax,rmax);
sum+=max(h-arr[i],0);
}
cout<<sum<<endl;
}
return 0;
}

 

Question #1

Convert the following Infix expression to Postfix form using a stack
x + y * z + (p * q + r) * s, Follow usual precedence rule and assume that the expression is legal.

  • A

    xyz*+pq*r+s*+

    xyz*+pq*r+s*+ 25%
  • B

    xyz*+pq*r+s+*

    xyz*+pq*r+s+* 25%
  • C

    xyz+*pq*r+s*+

    xyz+*pq*r+s*+ 25%
  • D

    xyzp+**qr+s*+

    xyzp+**qr+s*+ 25%
  • PrepInsta Explanation

Explanation: The Infix Expression is x + y * z + (p * q + r) * s.
(x y z ) + (p * q + r) * s. ‘+’, ‘*’ are present in stack.
(x y z * + p q * r) * s. ‘+’ is present in stack.
x y z * + p q * r + s * +. Thus Postfix Expression is x y z * + p q * r + s * +.

Question #2

Making the push operation costly, select the code snippet which implements the same.(let q1 and q2 be two queues)

  • A

    public void push(int x) { if(empty()) { q1.offer(x); } else{ if(q1.size()>0) { q2.offer(x); int size = q1.size(); while(size>0) { q2.offer(q1.poll()); size--; } } else if(q2.size()>0) { q1.offer(x); int size = q2.size(); while(size>0) { q1.offer(q2.poll()); size--; } } } }

    public void push(int x) { if(empty()) { q1.offer(x); } else{ if(q1.size()>0) { q2.offer(x); int size = q1.size(); while(size>0) { q2.offer(q1.poll()); size--; } } else if(q2.size()>0) { q1.offer(x); int size = q2.size(); while(size>0) { q1.offer(q2.poll()); size--; } } } } 40%
  • B

    public void push(int x) { if(empty()) { q1.offer(x); } else { if(q1.size()>0) { q1.offer(x); int size = q1.size(); while(size>0) { q2.offer(q1.poll()); size--; } } else if(q2.size()>0) { q2.offer(x); int size = q2.size(); while(size>0) { q1.offer(q2.poll()); size--; } } } }

    public void push(int x) { if(empty()) { q1.offer(x); } else { if(q1.size()>0) { q1.offer(x); int size = q1.size(); while(size>0) { q2.offer(q1.poll()); size--; } } else if(q2.size()>0) { q2.offer(x); int size = q2.size(); while(size>0) { q1.offer(q2.poll()); size--; } } } } 20%
  • C

    public void push(int x) { if(empty()) { q1.offer(x); } else { if(q1.size()>0) { q2.offer(x); int size = q1.size(); while(size>0) { q1.offer(q2.poll()); size--; } } else if(q2.size()>0) { q1.offer(x); int size = q2.size(); while(size>0) { q2.offer(q1.poll()); size--; } } } }

    public void push(int x) { if(empty()) { q1.offer(x); } else { if(q1.size()>0) { q2.offer(x); int size = q1.size(); while(size>0) { q1.offer(q2.poll()); size--; } } else if(q2.size()>0) { q1.offer(x); int size = q2.size(); while(size>0) { q2.offer(q1.poll()); size--; } } } } 20%
  • D

    public void push(int x) { if(empty()) { q1.offer(x); } else { if(q1.size()>0) { q2.offer(x); int size = q1.size(); while(size>0) { q2.offer(q2.poll()); size--; } } else if(q2.size()>0) { q1.offer(x); int size = q2.size(); while(size>0) { q2.offer(q1.poll()); size--; } } } }

    public void push(int x) { if(empty()) { q1.offer(x); } else { if(q1.size()>0) { q2.offer(x); int size = q1.size(); while(size>0) { q2.offer(q2.poll()); size--; } } else if(q2.size()>0) { q1.offer(x); int size = q2.size(); while(size>0) { q2.offer(q1.poll()); size--; } } } } 20%
  • PrepInsta Explanation

Explanation: Stack follows LIFO principle, hence a new item added must be the first one to exit, but queue follows FIFO principle, so when a new item is entered into the queue, it will be at the rear end of the queue. If the queue is initially empty, then just add the new element, otherwise add the new element to the second queue and dequeue all the elements from the second queue and enqueue it to the first one, in this way, the new element added will be always in front of the queue. Since two queues are needed to realize this push operation, it is considered to be costlier.

Question #3

Which of the following is not an application of priority queue?

  • A

    Huffman codes

    Huffman codes 20%
  • B

    Interrupt handling in the operating system

    Interrupt handling in the operating system 20%
  • C

    Undo operation in text editors

    Undo operation in text editors 40%
  • D

    Bayesian spam filter

    Bayesian spam filter 20%
  • PrepInsta Explanation

Explanation: Undo operation is achieved using a stack.

Question #4

What is a memory efficient double linked list?

  • A

    Each node has only one pointer to traverse the list back and forth

    Each node has only one pointer to traverse the list back and forth 25%
  • B

    The list has breakpoints for faster traversal

    The list has breakpoints for faster traversal 25%
  • C

    An auxiliary singly linked list acts as a helper list to traverse through the doubly linked list

    An auxiliary singly linked list acts as a helper list to traverse through the doubly linked list 25%
  • D

    A doubly linked list that uses bitwise AND operator for storing addresses

    A doubly linked list that uses bitwise AND operator for storing addresses 25%
  • PrepInsta Explanation

Explanation: Memory efficient doubly linked list has only one pointer to traverse the list back and forth. The implementation is based on pointer difference. It uses bitwise XOR operator to store the front and rear pointer addresses. Instead of storing actual memory address, every node store the XOR address of previous and next nodes.

Question #5

Which of the below diagram is following AVL tree property?
i.data-structure-questions-answers-avl-tree-q3
ii.data-structure-questions-answers-avl-tree-q3a

  • A

    only i

    only i 25%
  • B

    only i and ii

    only i and ii 25%
  • C

    only ii

    only ii 25%
  • D

    i is not a binary search tree

    i is not a binary search tree 25%
  • PrepInsta Explanation

Explanation: The property of AVL tree is it is height balanced tree with difference of atmost 1 between left and right subtrees. All AVL trees are binary search tree.

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Interview Preparation

dxc technology questions answers 2019

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DXC Technologies Placement Selection Process

DXC Technology has four written sections :

  • Written Rounds
    • Quantitative
    • Verbal
    • Logical Reasoning
    • Computer Programming
  • Technical Round
  • HR Round

Interview Experience

DXC recent year placement paper

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about interview experience

Student Details

  • Name: Sam
  • College:  Amity college
  • Type of Interview: On-Campus

Student Interview

Recently DXC Technology, one of the renowned IT companies visited our college for an on-campus interview. The eligibility criteria for this drive was:

Eligibility criterion:

  1. BE/B.Tech (All Streams)
  2. MCA/MSc (Comp Science)
  3. Minimum 65% in BE/B.Tech
  4. Minimum 60% in 10th and 12th

Since I fulfilled this criterion, so I was eligible to participate in the interview. The selection process had three rounds.

  1. Group Discussion
  2. Technical Interview
  3. HR Interview

Round 1- Written Test

For the first round I referred to some of the previous year papers for practice. The pattern of the test was as follows:

  1. Quantitative:  This section included questions on HCF and LCM, Divisibility, probability speed, and distance, Algebra, equations, progression, profit and loss, ratio and percentage, averages, geometry, probability, Clocks and calendars, Geometry, Coordinate geometry, etc.
  2. Logical reasoning: This section included questions on topics: Coding, Directional Sense, seating arrangement, visual reasoning, blood relations, flowcharts, statement, and conclusion, Data Sufficiency, etc.
  3. Computer programming: This section had questions on Data Types, Iteration, Recursion, Decision, Trees, Graphs, Queues, Hash Tables, Heaps, Searching and Sorting, Polymorphism, Encapsulation, Complexity Theory, Searching and sorting, etc.
  4. Logical: This section had questions on Contextual vocabulary, Synonyms, Antonyms, Jumbled up sentences, Prepositions, and Conjunctions.

Tenses and articles etc.

Round 2-Group Discussion

Next was the Group discussion round. All the students who cleared the test successfully were qualified for the Group discussion round. For this round, all the participants were divided into groups, and each group was given a topic. The topics were related to everyday activities and events prevalent around society. My group got the topic “How is IT industry influencing the economy?”.

In this round, we were being judged for our general knowledge, confidence, convincing ability, and communication skills. This round also went well. The list was out within an hour, and I was selected for the next round as well.

Round 3- Technical Interview

This was more of a resume round where I was asked all the technical questions on the previous projects that I had done in my final term internship and the one that was mentioned in my resume. The interviewer also asked me the below-mentioned questions:

  1. Explain SDLC?
  2. List the different storage class specifiers in C?
  3. What is the necessity & advantages of OOPS?
  4. Write the programming code to swap two numbers without using the third variable?
  5. What is networking?
  6. What was your role in your major project?

Mainly, he was checking the details written on my resume. I answered all the questions correctly, and fortunately passed this round as well.

Round 4- HR Interview or Face to Face Interview Round

It was the most comfortable and most relaxed round of all the above. It was more of a cake walk for me. Here the interviewer asked me some personal questions like,

  1. What are your future plans?
  2. What are your strengths professionally?
  3. Tell us about an accomplishment you are most proud of
  4. Do you want to pursue higher education?

Moreover, the interviewer was testing my fundamental knowledge and communication skills. I answered all the raised questions in a polite, clear and confident way. This helped me to clear this round as well.

A Week later I got an email from the company that I got selected for the Job. Hence my interview ended on a happy note.

DXC Technology recent placement paper

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Interview Experience

DXC Technology latest interview experience is available here.We have collected an interview experience of various students.DXC Technology Experience of every candidate has given here and you can get all the idea of the interview questions asked in the DXCTechnology.

We have set of the interview list. The list is given below :

Analytics

Total No of Questions - 60

Quants - 15

Logical - 15

Verbal - 15

Computer Programming - 15

overall Time - 60 min

Quants Time - 15 min

Logical Time - 15 min

Verbal Time - 15 min

Computer Programming Time - 15 min

75%

% of people clearing the written round

60%

% of people clearing the interview

20%

% of people joining the company

Quants

Cut off

Diffculty

Importance

Logical

Cut off

Diffculty

Importance

Verbal

Cut off

Difficulty

Importance

Computer Programming

Cut off

Difffculty

Importance

DXC PLACEMENT PAPERS SECTION NUMBER OF QUESTIONS SECTIONAL TIME DIFFICULTY IMPORTANCE
Aptitude 15 15 Medium Medium
Logical Reasoning 15 15 High Medium
Verbal English 15 15 Medium High
Computer Programming 15 15 Medium Very High

DXC Technology Placement Paper Based FAQ”s

What is the selection process for DXC Technologies ?

The selection process of the company consists of four rounds. These rounds are as follows:

  • Written Exam
  • Group Discussion
  • Technical Interview
  • HR Interview

Does DXC Technology hire through oncampus or offcampus ?

Yes, it is hire through offcampus generally . But sometimes it is also hiring through oncampus .

From where you have to study for preparation of DXC online written pattern ?

You can get all the preparation material of DXC from PrepInsta . It is provided the best and important topics of each and every section precisely .

What skills are required in DXC Technologies for computer programming ?

Skills like NET ,C, JAVA, C++ are required to get eligible in DXC Technologies.

Comments

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2 comments on “DXC Placement Papers and Previous Papers 2019-20”


  • mahesh

    This page is very good as it gives all the required information to me for the DXC

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  • omkar

    what platform is used in dxc for online written test ???? cocubes or amcat???

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