DXC Technology Aptitude Test Papers and Questions & Answers 2025

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DXC Technology Aptitude Test Questions and Answers 2025

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DXC Aptitude Exam Analysis

  • Number of Questions - 16 Question
  • Time - 16 mins
  • Type of Question: 16 MCQ
  • Mandatory for All

DXC Quants Sectional Analysis

DXC Preparation Section

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1. Article A was sold at 20% profit and Article B was sold at 60% profit. The selling price of Article B was 150% more than that of Article A. Cost price of Article B is what percent more than that of Article A?

87.5%

87.5%

44.07%

86.5%

86.5%

29.55%

23.5%

23.5%

15.21%

None

None

11.17%

Solution: (SP(A))/(CP(A)) = 120/100____________ (1)

(SP(B))/(CP(B)) = 160/100____________ (2)

(SP(B))/(sp(A)) = 250/100____________

Given (1)/ (2) =(CP(B))/(CP(A)) x100/250 = 120/100 x 100/160 =(CP(B))/(CP(A)) = 15/8 = (CP(B)-CP(A))/(CP(A)) x100 =(15-8)/8 x 100 =87.5%

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

2. How many pairs of integers (x, y) exist such that the product of x, y and HCF (x, y) = 1080?

8

8

27.52%

7

7

19.46%

9

9

33.47%

12

12

19.56%

We need to find ordered pairs (x, y) such that xy * HCF(x, y) = 1080.
Let x = ha and y = hb where h = HCF(x, y) => HCF(a, b) = 1.
So h3(ab) = 1080 = (23)(33)(5).
We need to write 1080 as a product of a perfect cube and another number.

Four cases:
1. h = 1, ab = 1080 and b are co-prime. We gave 4 pairs of 8 ordered pairs (1, 1080), (8, 135), (27, 40) and (5, 216). (Essentially we are finding co-prime a,b such that a*b = 1080).

2. h = 2, We need to find number of ways of writing (33) * (5) as a product of two co-prime numbers. This can be done in two ways - 1 and (33) * (5) , (33) and (5)
number of pairs = 2, number of ordered pairs = 4

3. h = 3, number of pairs = 2, number of ordered pairs = 4

4. h = 6, number of pairs = 1, number of ordered pairs = 2

Hence total pairs of (x, y) = 9, total number of ordered pairs = 18.
The pairs are (1, 1080), (8, 135), (27, 40), (5, 216), (2, 270), (10, 54), (3, 120), (24, 15) and (6, 30).

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

3. A prime number p greater than 100 leaves a remainder q on division by 28. How many values can q take?

8

8

20.45%

12

12

49.8%

9

9

17.53%

15

15

12.22%

q can be 1.
If q =2, number would be of the form 28n + 2 which is a multiple of 2.

Similarly, when q = 4, number would be of the form 28n + 4 which is again a multiple of 2. Any number of the form 28n + an even number will be a multiple of 2.

When q = 7, number would be of the form 28n + 7 which is a multiple of 7.

So, the only remainders possible are remainders that share no factors with 28. Or numbers that are co-prime to 28.

There is a formula for this and a shorter way of finding the number of numbers co-prime to a given natural number. A more detailed discussion on this is provided here and here.

1, 3, 5, 9, 11, 13, 15, 17, 19, 23, 25 and 27. q can take 12 different values

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

4. The difference between the compound interest and the simple interest on a certain sum at 12% p.a. for two years is Rs.90. What will be the value of the amount at the end of 3 years?

9000

9000

17.75%

6250

6250

26.89%

8530.80

8530.80

26.36%

8780.80

8780.80

29%

Solution:

The difference in the simple interest and compound interest for two years is on account of the interest paid on the first year\'s interest, when interest is reckoned using compound interest, interest being compounded annually.
Hence 12% of simple interest = 90 => simple interest = 90/0. =750.

As the simple interest for a year = 750 @ 12% p.a., the principal = 750/0.2 = Rs.6250.

If the principal is 6250, then the amount outstanding at the end of 3 years = 6250 + 3(simple interest on 6250) + 3 (interest on simple interest) + 1 (interest on interest on interest) = 6250 + 3(750) + 3(90) + 1(10.80) = 8780.80.

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

5. Two persons A and B start moving at each other from point P and Q respectively which are 1400 Km apart. Speed of A is 50 Km/hr and that of B is 20 Km/hr. How far is A from Q when he meets B for the 22nd time?

1000 km

1000 km

25.65%

400 km

400 km

37.18%

800 km

800 km

21.07%

1400 km

1400 km

16.1%

Total distance travelled by both of them for 22nd meeting = 1400 + (21 * 2 * 1400) = 43 * 1400
Distance travelled by each will be in proportion of their speed :
Therefore, distance travelled by A = 50/(50 + 20) * 43 * 1400 = 43000 (Note - Always do complicated calculations at last because things cancel out generally)
Now, for every odd multiple of 1400, A will be at Q and for every even multiple of 1400 A will be at P. So, at 42000 Km (1400 x 30, even multiple) A will beat P. So at their 22 meeting, A will be 1000 Km from P, therefore, 400 Km from Q.

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

6. A and B take part in a duel. A can strike with an accuracy of 0.6. B can strike with an accuracy of 0.8. A has the first shot, post which they strike alternately. What is the probability that A wins the duel?

7/10

7/10

22.8%

15/23

15/23

49.41%

2/3

2/3

17.81%

11/17

11/17

9.98%

A can win in the following scenarios:
A strikes in first shot.
A misses in the first shot, B misses in the second, A strikes in the third.
A misses in the 1st shot, B misses in the 2nd, A misses the 3rd, B misses the 4th and A strikes the 5th.
And so on…
P(A in 1st shot) = 0.6
P(A in 3rd shot) = 0.4 * 0.2 * 0.6 {A misses, then B misses and then A strikes}
P(A in 5st shot) = 0.4 * 0.2 * 0.4 * 0.2 * 0.6 {A misses, then B misses and then A misses, then B misses, then A strikes}
Overall probability = Sum of all these

= 0.6 + 0.4 * 0.2 * 0.6 + 0.4 * 0.2 * 0.4 * 0.2 * 0.6 + …
Which is nothing but
0.6 + (0.4 * 0.2) * 0.6 + (0.4 * 0.2)2 * 0.6 + (0.4 * 0.2)3 * 0.6…

This is an infinite geometric progression with first term 0.6 and common ratio 0.4 * 0.2
Required Probability = a1−r = 0.61−0.08 = 0.60.92 = 3046 = 1523

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

7. If log2X + log4X = log0.25√6 and x > 0, then x is

6^(-1/6)

6^(-1/6)

32.71%

6^(1/6)

6^(1/6)

39.06%

3^(-1/3)

3^(-1/3)

16.47%

6^(1/3)

6^(1/3)

11.76%

log2x + log4x = log0.25√6
We can rewrite the equation as:
log2x + log2xlog24 = log0.25√6
log2x * 32 = log0.25√6
=> log2x * 3 = 2log0.25√6
=> log2x3 = -log46
=> log2x3 = −log26log24
=> log2x3 = −log266

=> 2log2x3 = -log26
2log2x3 + log26 = 0
log26X6 = 0
6x6 = 1
x6 = 16
x = 16−−√6

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

8. Traders A and B buy two goods for Rs. 1000 and Rs. 2000 respectively. Trader A marks his goods up by x%, while trader B marks his goods up by 2x% and offers a discount of x%. If both make the same non-zero profit, find x

25%

25%

41.73%

12.5%

12.5%

27.74%

37.5%

37.5%

22.14%

40%

40%

8.4%

SP of trader A = 1000 (1 + x).
Profit of trader A = 1000 (1 + x) – 1000.
MP of trader B = 2000 (1 + 2x).
SP of trader B = 2000 (1 + 2x) (1 – x).

Profit of trader B = 2000(1 + 2x) (1 – x) – 2000.
Both make the same profit => 1000(1 + x) – 1000 = 2000(1 + 2x) (1 – x) – 2000
1000x = 2000 – 4000x2 + 4000x – 2000x – 2000
4000xx2 -1000x = 0
1000x (4x – 1) = 0
=> x = 25%

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

9. Let the nth term of AP be defined as tn, and sum up to 'n' terms be defined as Sn. If |t8| = |t16| and t3 is not equal to t7, what is S23?

23(t16 - t8)

23(t16 - t8)

33.14%

zero

zero

35.98%

23t11

23t11

18.13%

Cannot be determined

Cannot be determined

12.75%

t8|=|t16|. This can happen under two scenarios t8 = t16 or t8 = – t16.
If t8 = t16, the common difference would be 0 suggesting that t3 would be equal to t7.
However, we know t3 is not equal to t7, so the common difference cannot be zero.
This tells us that t8 = – t16 Or, t8 + t16 = 0.
If t8 + t16 = 0, then t12 = 0. t12 = t8 + 4d, and t16 – 4d So, t12 = t8+t162
For any two terms in an AP, the mean is the term right in between them.
So, t16 is the arithmetic mean of t8 and t16.
So, t12 = 0.
Now, S23 = 23 * t12. We know that average of n terms in an A.P. is the middle term.
This implies that sum of n terms in an A.P., is n times the middle term. So, S23 = 0.

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

10. Two circles are placed in an equilateral triangle as shown in the figure. What is the ratio of the area of the smaller circle to that of the equilateral triangle

Geometry - triangles: CAT Geometry Triangles Area

π:36√3

π:36√3

22.65%

π:18√3

π:18√3

32.06%

π:27√3

π:27√3

40.81%

π:42√3

π:42√3

4.48%

In-radius of equilateral triangle of side a = a2√3
Diameter of larger circle = a2√3

Let us say common tangent PQ touches the two circle at R, center of smaller circle is I.
Now, PQ is parallel to BC. AR is perpendicular to PQ. Triangle PQR is also an equilateral triangle and AORID is a straight line. (Try to establish each of these observations. Just to maintain the rigour.)

AD = √32

a
RD = a√3
AR = √32a - a√3 = 3a−2a2√3 = a2√3
AR = 13 AD
Radius of smaller circle = 13 radius of larger circle
Radius of smaller circle = 13 * a2√3 = a6√3
Area of smaller circle = πr2
π (a6√3)2 = πa2108
Area of triangle = √34a2
Ratio = πa2108 : √34a2 = π:27√3

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

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Analytics 2025

Stats About DXC

Number of Questions 100%
Cut-off 81.25%
Difficulty 70%

Topic Wise Analytics

LCM and HCF
0-1 Number of Questions
Difficulty 65%
Importance 70%
Divisibility
0-1 Number of Questions
Difficulty 60%
Importance 65%
Number System and decimal Fraction
0-1 Number of Questions
Difficulty 65%
Importance 92.31%
Profit and Loss
1-2 Number of Questions
Difficulty 60%
Importance 65%
Simple and Compund Interest
0-1 Number of Questions
Difficulty 60%
Importance 65%
Time,Speed and Distance
1-2 Number of Questions
Difficulty 65%
Importance 70%
Logarithm
0-1 Number of Questions
Difficulty 65%
Importance 60%
Probability
1-2 Number of Questions
Difficulty 65%
Importance 60%
Percentage
1-2 Number of Questions
Difficulty 75%
Importance 60%
Series and Progression
0-1 Number of Questions
Difficulty 65%
Importance 70%
Area,Shape and Perimeter
0-1 Number of Questions
Difficulty 80%
Importance 75%
Time and Work
0-1 Number of Questions
Difficulty 70%
Importance 65%
Allegation and Mixture
1-2 Number of Questions
Difficulty 60%
Importance 65%
Geomtery and Coordinate Geometry
1-2 Number of Questions
Difficulty 70%
Importance 65%
Mensuration
1-2 Number of Questions
Difficulty 70%
Importance 65%
Ratio and Proportion
0-1 Number of Questions
Difficulty 65%
Importance 70%
Algebra
0-1 Number of Questions
Difficulty 65%
Importance 60%
Equations
1-2 Number of Questions
Difficulty 60%
Importance 65%

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One comment on “DXC Technology Aptitude Test Papers and Questions & Answers 2025”


  • mahesh

    I used to have a lot of doubt but after going through this section, this section cleared my doubts like broom to the dust.. 😉

February 4, 2025