IBM Placement Papers for Freshers

Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
Then,
(2x+4000) / (3x+4000) = 40 / 57
⇒ 57 × (2x + 4000) = 40 × (3x+4000)
⇒ 6x = 68,000
⇒ 3x = 34,000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000

Q3. Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is -:-

• 1/2
• 16/19
• 4/5
• 17/20
• 3/5

Solution:- 17/20

n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 - 1/20 = 17/20

Q4. A man travelled a distance of $61$ km in $9$ hours. He travelled partly on foot at $4$ km/hr and partly on bicycle at $9$ km/hr. What is the distance travelled on foot?

• 12Km
• 14Km
• 16Km
• 18Km

Solution:-16 Km

Let the time in which he travelled on foot $=x$ hr
Then the time in which he travelled on bicycle $=(9-x)$ hr

distance = speed × time$\Rightarrow 4x+9(9-x)=61\Rightarrow 4x+81-9x=61\Rightarrow 5x=20\Rightarrow x=4$
Distance travelled on foot
$=4x=4\times 4=16\text{km}$

Q5. A mixture contains alcohol and water in the ratio 4 : 3. If 5 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture.

• 10
• 12
• 15
• 18

Solution:-10

Let the quantity of alcohol and water be 4x litres and 3x litres respectively

4x/(3x+5) = 4/5

20x = 4(3x+5)

8x = 20

x = 2.5

Quantity of alcohol = (4 x 2.5) litres = 10 litres.

Q6.A man goes to his office from his house at a speed of $3$ km/hr and returns at a speed of $2$ km/hr. If he takes $5$ hours in going and coming, what is the distance between his house and office?

• 3Km
• 4Km
• 6Km
• 5Km

Solution:-6Km

Q7.A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?

Average speed $=\frac{2\times 3\times \mathrm{2/}}{2+3}=\frac{12}{5}\text{km/hr}$
Total time taken $=5$ hours

Distance travelled $=\frac{\mathrm{12/}}{5}\times 5=12\text{km}$

Therefore, distance between his house and office
$=\frac{\mathrm{12/}}{2}=6\text{km}$

Q7.A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? 

• Rs. 1000
• Rs. 1140
• Rs. 860
• Rs. 760

Solution:-Rs 1000

90%

104%

--------

14% ---- 140

100% ---- ? => Rs.1000

Q 8. 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning?

Solution:-

• 3800
• 4200
• 4400
• 5500

Solution:-C

X * (95/100) * (85/100) = 3553
X = 4400

Q9.A mixture of 70 liters of wine and water contains 10% water. How much water must be added to make water 12 ½% of the total mixture? 

• 12L
• 10L
• 4L
• 2L

Solution:- 2L

70 * (10/100) = 7
Wine Water
87 1/2% 12 1/2%
87 1/2% ------- 63
12 1/2% -------? => 9-7=2

Q 10. In a factory, there are 40% technicians and 60% non-technicians. If the 60% of the technicians and 40% of non-technicians are permanent employees, then the percentage of workers who are temporary is?

• 32%
• 42%
• 52%
• 62%

Solution:-Total = 100
T= 40     NT= 60
40*(60/100)=24     60*(40/100)=24
24 + 24 = 48 => 100 - 48 = 52%

Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
Then,
(2x+4000) / (3x+4000) = 40 / 57
⇒ 57 × (2x + 4000) = 40 × (3x+4000)
⇒ 6x = 68,000
⇒ 3x = 34,000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000

Q4. Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is -:-

• 1/2
• 16/19
• 4/5
• 17/20
• 3/5

Solution:- 17/20

n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 - 1/20 = 17/20

Q5. A man travelled a distance of $61$ km in $9$ hours. He travelled partly on foot at $4$ km/hr and partly on bicycle at $9$ km/hr. What is the distance travelled on foot?

• 12Km
• 14Km
• 16Km
• 18Km

Solution:-16 Km

Let the time in which he travelled on foot $=x$ hr
Then the time in which he travelled on bicycle $=(9-x)$ hr

distance = speed × time$\Rightarrow 4x+9(9-x)=61\Rightarrow 4x+81-9x=61\Rightarrow 5x=20\Rightarrow x=4$
Distance travelled on foot
$=4x=4\times 4=16\text{km}$

Q5. A mixture contains alcohol and water in the ratio 4 : 3. If 5 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture.

• 10
• 12
• 15
• 18

Solution:-10

Let the quantity of alcohol and water be 4x litres and 3x litres respectively

4x/(3x+5) = 4/5

20x = 4(3x+5)

8x = 20

x = 2.5

Quantity of alcohol = (4 x 2.5) litres = 10 litres.

Q6.A man goes to his office from his house at a speed of $3$ km/hr and returns at a speed of $2$ km/hr. If he takes $5$ hours in going and coming, what is the distance between his house and office?

• 3Km
• 4Km
• 6Km
• 5Km

Solution:-6Km

Q7.A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?

Average speed $=\frac{2\times 3\times \mathrm{2/}}{2+3}=\frac{12}{5}\text{km/hr}$
Total time taken $=5$ hours

Distance travelled $=\frac{\mathrm{12/}}{5}\times 5=12\text{km}$

Therefore, distance between his house and office
$=\frac{\mathrm{12/}}{2}=6\text{km}$

Q7.A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? 

• Rs. 1000
• Rs. 1140
• Rs. 860
• Rs. 760

Solution:-Rs 1000

90%

104%

--------

14% ---- 140

100% ---- ? => Rs.1000

Q 8. 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning?

Solution:-

• 3800
• 4200
• 4400
• 5500

Solution:-C

X * (95/100) * (85/100) = 3553
X = 4400

Q9.A mixture of 70 liters of wine and water contains 10% water. How much water must be added to make water 12 ½% of the total mixture? 

• 12L
• 10L
• 4L
• 2L

Solution:- 2L

70 * (10/100) = 7
Wine Water
87 1/2% 12 1/2%
87 1/2% ------- 63
12 1/2% -------? => 9-7=2

Q 10. In a factory, there are 40% technicians and 60% non-technicians. If the 60% of the technicians and 40% of non-technicians are permanent employees, then the percentage of workers who are temporary is?

• 32%
• 42%
• 52%
• 62%

Solution:-Total = 100
T= 40     NT= 60
40*(60/100)=24     60*(40/100)=24
24 + 24 = 48 => 100 - 48 = 52%

Number Series:-

Q1. 2 3 10 38 172

• 192
• 10
• 38
• 4
• 2

Solution:- Logic is 2×1 + 1 = 3, 3 × 2 + 4 =10, 10 × 3 + 9 = 39, 39 × 4 + 16 = 172…. So in place of 38, it should be 39.

Q2. 4 2 3 7.5 26.75 

• 26.75
• 7.5
• 3
• 2
• 4

Solution:- Logic is 4 × .5 = 2, 2 × 1.5 = 3, 3 × 2.5 = 7.5, 7.5 × 3.5 = 26.25 In place of 26.75, it should be 26.25.

Q 3. 15 18 20 29 45 70 106 

• 18
• 20
• 29
• 45
• 70

Solution:-18

Starting from the back
106– 70 = 36, 70- 45 = 25, 45 – 29 = 16, 29 – 20 = 9, 20 – 16 = 4, 16 – 15 = 1. Every difference is perfect square starting from 36 and decreasing. Thus the wrong number is 18, it should be 16.

Q4. 49 50 46 55 38 64 28 

• 49
• 46
• 55
• 38
• 64

Solution:- 38

Logic is 49 + 1 = 50, 50 – 4 = 46, 46 + 9 = 55, 55 – 16 = 39, 39 + 25 = 64. Thus the wrong number is 38, it should be 39.

Q5. 35 19 11 7 5 4.5 3.5 

• 4.5
• 5
• 11
• 9
• 7

Solution:- 4.5

35-19 = 16, 19-11 = 8, 11-7 = 4, 7-5 = 2, 5-4 = 1, 4-3.5 = .5 The difference is halved every time. Thus the wrong number is 4.5, it should be 4.

Q6. 3, 12, 8, 19, 13, 32, 18, 42, 23, 52 

• 12
• 19
• 42
• 32
• None of these

Solution:-

The sequence is a combination of following two series:
I. 3, 8, 13, 18, 23 and II. 12, 19, 32, 42, 52
The pattern in I has a constant difference of +5, and the pattern in II has a constant difference of +10. So, in II, 19 is wrong and should be replaced by (12+10) i.e. 22

Q7. 1, 10, 9, 16, 25, 26, 49 

• 1
• 16
• 26
• 9
• 49

Solution:-

The given sequence is a combination of two series:
I. 1, 9, 25, 49 and II. 10, 16, 26
The pattern in I is +8, +16, +24.
The sequence in II is 3² + 1, 4² + 1, 5² + 1
So, 16 is wrong and must be replaced by (4² + 1) i.e. 17.

Q8. 13 17 23 29 31 37 ?? 

• 22
• 41
• 19
• 23
• 27

Solution:-

The given series is a prime number series. Hence the next prime number in this sequence would be 41.

Q 9. 31, 2, 41, 3, 52, 4, 61, 5, 71, 6 

• 41
• 61
• 52
• 31
• 6

Solution:-

The sequence is a combination of two given series:
I. 31, 41, 52, 61, 71 and II. 2, 3, 4, 5, 6
So, the pattern in I is + 10
Thus, 52 is wrong and should be replaced by (41 + 10) i.e. 51.

Q 10. 13 17 23 29 31 37 ?? 

• 22
• 41
• 19
• 23
• 27

Solution:-B

The given series is a prime number series. Hence the next prime number in this sequence would be 41.