TCS NQT Placement Papers and Questions

TCS NQT Placement Papers and Questions 2023

This year TCS NQT Pattern is completely changed. TCS NQT Written Test Questions pattern-based practice problems are available on the PrepInsta website. You may want to go through all the sections before you start writing the exam. Test Pattern has been changed for the TCS NQT Test as some sections have been replaced with the new sections also some new sections are added this year.

We have done every bit of research and analysis for TCS NQT Placement papers and Questions 2023 here. TCS NQT Previous Papers and Sample Papers show us that the exam is of high difficulty for all branches.

TCS NQT will use TCS iON platform for their both Rounds, below you will find details:

TCS NQT Round 1 (Foundation) Round 2 (Advance)
Total no. of question  66 MCQ and Non-MCQ Type 20 MCQ and Non- MCQ and 2 Coding Questions
Allotted Time 75 mins 90 mins
Total Sections 4 sections Advanced Round 1 - 2 sub-sections
Advanced Round 2 - 1 sub-section

IMPORTANT NOTE:

  1. There will be no negative marking.
  2. TCS NQT is non- adaptive this year
  3. You will not get any extra rough paper in the exam as a calculator and Rough Paper will be available on your Desktop Screen. You are not allowed to move your eyes down while giving the examination.

More Information for TCS - NQT 2023

NOTE: Traits is mandatory in TCS NQT off-campus round but it varies in On-Campus drive i.e in few colleges Traits is included but in few colleges it is not included.

Total Rounds

2

Time

165 mins

Type of Exam

Non- Adaptive

Negative Marking

No

Students

3,40,000

Open Positions

40,000

Curriculum

TCS NQT Test Pattern 2023:-

The TCS NQT Curriculum has seen modification this year. As TCS is going to conduct the TCS NQT Test using TCS iON platform. In this test email writing section is not there. There will be two rounds named as:

  1. Foundation Section (For Ninja aspirants)
  2. Advance Section (mandatory for Digital Aspirants)

Part A- Foundation Course

This round is divided into 4 section. Difficulty level of this round is Moderate.

  1. Traits
  2. Aptitude
  3. Logical
  4. Verbal

TCS NQT Round 1

Round 1 Important Information
Total no. of question 66 MCQ and Non- MCQ
Allotted Time 75 mins
Section 4 section and all sections are mandatory

**Note: Traits only contains 1 image type question but this section may or may not ask in your exam, it totally depends from college to college.

Part B- Advanced Course

Advanced round - 1 is divided into 2 section. Difficulty level of this round is High.

  1. Advanced Aptitude
  2. Advanced Logical

Advanced round - 2 consists Advanced Coding which only has 2 coding questions.

TCS NQT Round 2

Round 2 Important Information
Total no. of question 20 MCQs and Non-MCQ and 2 Coding Questions
Allotted Time 90 mins
Section Property 2 section and all sections are mandatory
Marking Scheme No Negative Marking

TCS NQT Overall Pattern - Detailed Information

TCS NQT Section Total Time Total Questions
Part A : Foundation Section (Mandatory for Ninja Aspirants)
Traits 75 mins (shared) 1 (image selection question)
Numerical Ability 75 mins (shared) 20
Verbal Ability 75 mins (shared) 25
Reasoning Ability 75 mins (shared) 20
Part B : Advanced Section (Mandatory for Digital Aspirants)
Advanced Quantitative Ability 35 mins (shared) 10
Advanced Reasoning Ability 35 mins (shared) 10
Advanced Coding 55 mins 2
Total Duration 165 mins 88

Additional Information:

  1. No Negative Marking
  2. Section Switching is not allowed
  3. Candidates are not allowed to revisit already answered questions.
  4. Sub- Section switching not allowed
  5. Browser tab shifting not allowed (Exam will end immediately)
  6. Video and Audio will be monitored by an AI ( for people giving test from home)
  7. One teacher will proctor the exam of over 20 students.

TCS NQT 2023 Section wise bifurcation:

TCS NQT Placement Papers

 

NOTE: Traits is mandatory in TCS NQT off-campus round but it varies in the On-Campus drive i.e in a few colleges Traits is included but in a few colleges it is not included.

TCS NQT Placement Paper 2023- Part A

TCS NQT Placement Paper Part A (which is Foundation Section) of TCS Off-campus drive has 4 sub sections in it. Eligible candidates are B.tech, B.E, M.E, M.Tech, MCA and M.Sc Students.

Below we have discussed TCS NQT Foundation Section Placement Paper details:

TCS NQT Foundation Section:

  1. Traits
  2. Numerical Ability
  3. Verbal Ability
  4. Reasoning Ability

TCS NQT Aptitude Test Curriculum

Traits:

Traits is also known as Psychometric Test, in which they will be asking few questions related to working environment, mental ability etc.

Note:** This section was not asked in On-campus drive but could be asked in Off-campus drive.

Quantitative Aptitude

Click here - TCS NQT Numerical Ability

Verbal Ability -

Click here - TCS NQT Verbal Ability

Logical Ability -

Click here- TCS NQT Reasoning Ability

Detailed Analysis

  • Total number of Questions: 66 MCQ and Non-MCQ type questions
  • Total Time: 75 mins
  • Difficulty: Moderate
  • Marking Scheme: No Negative Marking
  • Cut-Off: 75%

TCS NQT Foundation Exam Pattern:

TCS NQT Foundation Section

TCS NQT Placement Paper- Part B

TCS NQT Placement Papers Part B (which is Advance section) is mandatory for Digital candidates i.e., if you have cleared the Foundation Section then only you will be able to sit for Advance section.

TCS NQT Placement Paper Digital Round Curriculum

Advanced Round 1

Advanced Quantitative Syllabus

Click here - Advanced Quantitative Ability

Advanced Logical Ability -

Click here - Advanced Logical Reasoning Ability

Advanced Round 2

Advanced Coding -

The languages that are allowed for you to code are -

  1. C
  2. C#
  3. C++
  4. +Know More

Click here - Advanced Coding

Detailed Analysis

  • Total number of Questions: 20 MCQ and Non-MCQ and 2 Coding Questions
  • Total Time: 75 mins
  • Difficulty: High
  • Marking Scheme: No Negative Marking
  • Cut-Off: 75%

TCS NQT Advanced Section Pattern:

TCS NQT Advanced Section

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Preparation Section TCS NQT

TCS NQT Part A - Numerical Ability Test Detailed Analysis

  • Total number of Questions:  20 MCQ's
  • Total Time: 75 mins (shared)
  • Difficulty: Moderate-High
  • Marking Scheme: No Negative Marking
  • Cut-Off: 75%
> Start

P&C

0/100%
Completed

> Start

Number System/ LCM & HCF

0/100%
Completed

> Start

Percentages

0/100%
Completed

> Start

Allegations and Mixtures

0/100%
Completed

> Start

Probability

0/100%
Completed

> Start

Ratio and Proportion

0/100%
Completed

> Start

Reasoning

0/100%
Completed

> Start

Time and Work

0/100%
Completed

> Start

Time, Speed & Distance

0/100%
Completed

> Start

Geometry

0/100%
Completed

> Start

Elementary Statistics

0/100%
Completed

See More...

> Start

Profit & Loss

0/100%
Completed

> Start

Problem on Ages

0/100%
Completed

> Start

Calendar and Clocks

0/100%
Completed

> Start

Progressions

0/100%
Completed

> Start

Equations

0/100%
Completed

> Start

Averages

0/100%
Completed

> Start

Shapes and Perimeter

0/100%
Completed

> Start

Decimal Fractions

0/100%
Completed

> Start

Divisibility

0/100%
Completed

1. In how many ways can we give change for rs 100 using 1 rupee and 2 rupee coins? For example for 5 rs we can give three ways(1,1,1,1) (1,1,1,2) )(,1,2,2)

52 ways

52 ways

25.44%

50 ways

50 ways

21.51%

51 ways

51 ways

42.83%

53 ways

53 ways

10.23%

Let X be the number of 1 rupee and Y be the number of 2 rupees coin

X+Y= 100

Take x = 100, Y=0

Likewise,Y=1, X=98

It will go till Y=50, X=0

Therefore there are 51 ways

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

2. We are driving along a highway at a constant speed of 55 miles per hour (mph). You observe a car one-half mile behind you. The car is moving fast and zooms past you exactly one minute later. How fast is this car traveling (mph) if its speed is constant?

85

85

48.97%

70

70

24.81%

82

82

16.56%

80

80

9.66%

The car moves 1/2 mile in 1 minute.

Speed of the car = 1/2 mile for 1 min.

30 miles for 60 min(1 hr).

Therefore, the speed of the car is 30 mph.

Also, the speed of the observant car is 55 mph.

And both are moving in the same direction, we must add the speeds.

So, speed of the car = (55 + 30) mph

= 85 mph.

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

3. What is the next number in the series 70,54,45,41?

35

35

22.39%

40

40

69.84%

44

44

5.32%

45

45

2.45%

We are given to select the next number in the following series :

70, 54, 45, 41, . . .

Let a(n) denote the n-th term of the given series.

Then, we observe that

a(1)=70,\\\\a(2)=54=70-16=a(1)-4^{2},\\\\a(3)=45=54-9=a(2)-3^{2},\\\\a(4)=41=45-4=a(3)-2^{2},

Repeating the above rule, we get

a(5)=a(4)-1^{2}=41-1=40.

Thus, the next term in the given series is 40.

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

4. George can do some work in 8 hours. Paul can do the same work in 10 hours while Hari can do the same work in 12 hours. All the three of them start working at 9 AM. while George stops work at 11 am, the remaining two complete the work, approximately when will the work be finished?

11:30 AM

11:30 AM

11.69%

12 noon

12 noon

18.01%

1 pm

1 pm

56.06%

12.30 PM

12.30 PM

14.24%

George can do the work in 8 hours

⇒ 1 hour = 1/8 of the work

Paul can do the work in 10 hours

⇒1 hour = 1/10 of the work

Hari can do the work in 12 hours

⇒ 1 hour = 1/12 of the work

Find the amount of work that can be completed in an hour:

⇒ 1 hour = 1/8 + 1/10 + 1/12 = 37/120

Find the amount of work completed in 2 hours (9 am to 11 am):

⇒ 1 hour = 37/120

⇒2 hours = 37/120 x 2 = 37/60

Find the amount of work remain:

Work remain = 1 - 37/60 = 23/60

Find the amount of work Paul and Hari can do in an hour:

1 hour = 1/10 + 1/12 = 11/60

Find the number of hours needed for them to complete the rest of the work:

Number of hours needed = 23/60 ÷ 11/60 = 2.09 hours = 2 hours

Find the time the work is completed:

11am + 2 hours = 1 pm

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

5. Shush and Komal can do a job together in 7 days. Shush is 7/4 times as efficient as Komal. The same job can be done by Shush alone in

49/4 Days

49/4 Days

26.57%

49/3  Days

49/3  Days

15.13%

11 Days

11 Days

46.28%

28/3 Days

28/3 Days

12.02%

Shush completes work in s days.

so in one day \frac{1}{s}th part of the day.

Similarly;

Komal can complete \frac{1}{k}th part of the day.

\frac{1}{s} + \frac{1}{k} = \frac{1}{7}

Shush is \frac{7}{4}times more efficient

therefore, \frac{1}{s} = \frac{7}{4}\times \frac{1}{k}

\frac{4}{7}\times \frac{1}{s} = \frac{1}{k}[\latex]

so, last equation becomes

\frac{1}{s} + \frac{4}{7}\times = \frac{1}{7}[\latex]

S = 11 Days

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

6. a,b,c are positive numbers such that a+b+ab= 8, b+c+bc=15 and c+a+ca = 35. What is the value of a+b+c+abc?

34

34

13.75%

36

36

56.92%

35

35

17.71%

33

33

11.62%

Acc to the question, there are 3 equations given:

a+b+ab= 8-----(i)

b+c+bc=15------(ii)

c+a+ca = 35---------(iii)

Now adding 1 to both the sides of equ (i) we get,

a+b+ab+1= 8+1

or, (a+1)(b+1)=9.

Similarly we get, (b+1)(c+1)=16 and (a+1)(c+1)=36.

now starting from the second equation,

We know that 16 has many factors but we have to brute force for satisfying the equation.

We know, 16 = 2 * 8 = (1+1) * (7+1) now, comparing it with equ(ii) we get, b=1,c=7.

Now putting the value of c in any two of the remaining equation we get,

(a+1)*(c+1)=36

or, (a+1)*(7+1)=36

or,(a+1) = 36/8 = 4.5

or, a = 4.5 - 1 = 3.5.

Now, a+b+c+abc = 3.5 + 1 + 7 + 3.5*1*7 = 36.

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

7. The 260th term of the series a,b,b,c,c,c,d,d,d,d,e,e,e,e,e,f,f,f,f,f,f,….is:

U

U

14.32%

V

V

22.96%

W

W

51.37%

T

T

11.35%

Given,

First-term = a

third term = b

sixth term = c

We see that Each alphabet repeats for the number of times its position in the English Alphabet,

This series will come to end at z repeating itself for 26 times.

Last term z will be \frac{26\times 27}{2}[\latex] = 350th term

We can say that ,

N th alphabet will be existing from Σ(n-1)+1 to ΣN

ΣN ≥ 260

Let n = 23

Σ(n-1) +1 = 254

Σn = 276

Therefore , 23rd Alphabet will exist from 254 to 276 terms .

23rd Alphabet is W

The 260th term of the series is W

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

8. It is possible to pair up all the numbers from 1 to 70 so that the positive difference between the numbers in each pair is always the same. For example, one such pairing up is (1,2), (3,4), (5,6),….(69,70). Here the common difference is 1. What is the sum of all such common differences?

630

630

46.31%

640

640

25.98%

650

650

17.47%

660

660

10.24%

Here,
Two things have to be taken into account:
• Common difference
• No. of such pairs

For simplicity,
Consider range as 1 - 10
Here, when the common difference exceeds 5, numbers are not paired as per the condition.

Like if you take 6 as common difference, not all the pairs will have same value, because it is impossible.

•°• For range 1 - n, we have (n/2) common differences.

Now,
Coming to the given range 1 - 70
n = 70
=> (n/2) = 35

•°• No. of common differences that will satisfy the condition = 35

Now, Find sum of these differences.
1 + 2 + 3 + …… + 35
= (35 × 36) ÷ 2
= 630

•°• Required sum of all such common differences = 630

 

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

9. A  regular polygon with 12  sides (dodecagon) is inscribed in a square of area 24 square units as shown in the figure where four of the vertices are mid points of the sides of the square . The area of the dodecagon in square units is.

19

19

15.66%

20

20

33.17%

17

17

14.01%

18

18

37.16%

Let r be half the side of the square.

Consider one of the twelve triangle segments made by a side of the dodecagon and the centre of the dodecagon ( = the centre of the square).

The angle at the centre is 360° / 12 = 30°.

The two sides of the triangle that meet at the centre each have length r, as this is the radius of the circumscribed circle.

The area of this small triangle is then (1/2) r² sin 30° = r² / 4.

The dodecagon is made up of twelve of these triangles, so

area(dodecagon) = 12 × r² / 4 = 3 r².

As r is half the side of the square,

area(square) = 4 r².

Therefore

area(dodecagon ) / area(square) = 3 / 4

=> area(dodecagon) = 3 × 24 / 4 = 3 × 6 = 18

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

10. In how many ways can we give change for 100 using 1 rupee and 2 rupee coins? For example for 5 rs, we can give in three ways : (1,1,1,1,1) (1,1,1,2) (1,2,2)

51

51

78.55%

48

48

8.2%

50

50

9.55%

49

49

3.71%

Here we have to find out the number of ways we can distribute 100 rupees money to rupee 1 and rupee 2.

The simplest method is to find out the number of ways is to calculate the number of coins we use to break partitions. As an example, the ways are

1, 1, 1,..........................................,1 (100 times 1)

1, 1, 1, ......................................, 1 and 2 (98 times 1 and 1 time 2)

1, 1, 1, ....................................., 1, 2 , 2 ( 96 times 1 and 2 times 2)

.............................

proceeding in this way, our last combination for taking the coins be

2, 2, 2, ........................, 2 (50 times 2)

So, here, we can find the numbers of ways by counting the number of 2 we took and is equal to 50 + 1 = 51.

Answer: 51

Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.

Oops!

11. In the figure shown, a triangle is divided into nine stripes of equal height each parallel to the same side of the triangle. The shaped stripes have a total area of 135 square units. What is the area of the triangle in square units?

143 square units.

143 square units.

19.86%

243 square units.

243 square units.

34.35%

135 square units.

135 square units.

34.41%

240 square units.

240 square units.

11.38%

Triangle Image

A = Area of the full triangle

Stripe 1

is a triangle that is similar to the full triangle.
It has height =\frac{1}{9}× height of the larger triangle.
Area(1) = \frac{</span><span id="MathJax-Span-86" class="mstyle"><span id="MathJax-Span-87" class="mrow"><span id="MathJax-Span-88" class="mfrac"><span id="MathJax-Span-89" class="mn">1}{</span><span id="MathJax-Span-90" class="mn">9}</span></span></span></span><span id="MathJax-Span-91" class="mo">^{</span></span><span id="MathJax-Span-92" class="mn">2}× Area of larger triangle =\frac{</span><span id="MathJax-Span-97" class="mstyle"><span id="MathJax-Span-98" class="mrow"><span id="MathJax-Span-99" class="mfrac"><span id="MathJax-Span-100" class="mn">1}{</span><span id="MathJax-Span-101" class="mn">81}[\latex]</span></span></span></span><span id="MathJax-Span-102" class="mi">A</span></span></span></span></span></span></p> <p class="q-text qu-display--block">Stripes <span class="qtext_span qtext_math _1sNWenR7FDgH9GLRfri58K _1xzGCdFnEIP2F4OzuIN1m9"><span id="MathJax-Element-18-Frame" class="MathJax" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mn>1</mn></math>"><span id="MathJax-Span-106" class="math"><span id="MathJax-Span-107" class="mrow"><span id="MathJax-Span-108" class="mn">1 </span></span></span></span></span><span class="q-box qu-userSelect--text">and <span class="qtext_span qtext_math _1sNWenR7FDgH9GLRfri58K _1xzGCdFnEIP2F4OzuIN1m9"><span id="MathJax-Element-19-Frame" class="MathJax" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mn>2</mn></math>"><span id="MathJax-Span-109" class="math"><span id="MathJax-Span-110" class="mrow"><span id="MathJax-Span-111" class="mn">2</span></span></span></span></span></span><span class="q-box qu-userSelect--text"> form a triangle that is similar to a larger triangle.<br /> This triangle has height <span class="qtext_span qtext_math _1sNWenR7FDgH9GLRfri58K _1xzGCdFnEIP2F4OzuIN1m9"><span id="MathJax-Element-20-Frame" class="MathJax" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo><mstyle displaystyle="false" scriptlevel="0"><mfrac><mn>2</mn><mn>9</mn></mfrac></mstyle><mo>×</mo></math>"><span id="MathJax-Span-112" class="math"><span id="MathJax-Span-113" class="mrow"><span id="MathJax-Span-114" class="mo">=[latex]\frac{</span><span id="MathJax-Span-115" class="mstyle"><span id="MathJax-Span-116" class="mrow"><span id="MathJax-Span-117" class="mfrac"><span id="MathJax-Span-118" class="mn">2}{</span><span id="MathJax-Span-119" class="mn">9}× height of the larger triangle.
Area(1 and 2)=\frac{</span><span id="MathJax-Span-130" class="msubsup"><span id="MathJax-Span-131" class="mrow"><span id="MathJax-Span-132" class="mo"></span><span id="MathJax-Span-133" class="mstyle"><span id="MathJax-Span-134" class="mrow"><span id="MathJax-Span-135" class="mfrac"><span id="MathJax-Span-136" class="mn">2}{</span><span id="MathJax-Span-137" class="mn">9</span></span></span></span><span id="MathJax-Span-138" class="mo">}^{</span></span><span id="MathJax-Span-139" class="mn">2}× Area of larger triangle =\frac{</span><span id="MathJax-Span-144" class="mstyle"><span id="MathJax-Span-145" class="mrow"><span id="MathJax-Span-146" class="mfrac"><span id="MathJax-Span-147" class="mn">4}{</span><span id="MathJax-Span-148" class="mn">81}A
Area(2)=\frac{</span><span id="MathJax-Span-156" class="mstyle"><span id="MathJax-Span-157" class="mrow"><span id="MathJax-Span-158" class="mfrac"><span id="MathJax-Span-159" class="mn">4}{</span><span id="MathJax-Span-160" class="mn">81}</span></span></span></span><span id="MathJax-Span-161" class="mi">A</span><span id="MathJax-Span-162" class="mo">−\frac{</span><span id="MathJax-Span-163" class="mstyle"><span id="MathJax-Span-164" class="mrow"><span id="MathJax-Span-165" class="mfrac"><span id="MathJax-Span-166" class="mn">1}{</span><span id="MathJax-Span-167" class="mn">81}</span></span></span></span><span id="MathJax-Span-168" class="mi">A</span><span id="MathJax-Span-169" class="mo">= \frac{</span><span id="MathJax-Span-170" class="mstyle"><span id="MathJax-Span-171" class="mrow"><span id="MathJax-Span-172" class="mfrac"><span id="MathJax-Span-173" class="mn">3}{</span><span id="MathJax-Span-174" class="mn">81}</span></span></span></span><span id="MathJax-Span-175" class="mi">A

Stripes 1,2, and 3 forms a triangle that is similar to a larger triangle.
This triangle has height =\frac{</span><span id="MathJax-Span-191" class="mstyle"><span id="MathJax-Span-192" class="mrow"><span id="MathJax-Span-193" class="mfrac"><span id="MathJax-Span-194" class="mn">3}{</span><span id="MathJax-Span-195" class="mn">9} × height of the larger triangle.
Area(1,2, and 3)=\frac{</span><span id="MathJax-Span-209" class="msubsup"><span id="MathJax-Span-210" class="mrow"><span id="MathJax-Span-211" class="mo"></span><span id="MathJax-Span-212" class="mstyle"><span id="MathJax-Span-213" class="mrow"><span id="MathJax-Span-214" class="mfrac"><span id="MathJax-Span-215" class="mn">3}{</span><span id="MathJax-Span-216" class="mn">9</span></span></span></span><span id="MathJax-Span-217" class="mo">}^{</span></span><span id="MathJax-Span-218" class="mn">2} × Area of larger triangle = \frac{</span><span id="MathJax-Span-223" class="mstyle"><span id="MathJax-Span-224" class="mrow"><span id="MathJax-Span-225" class="mfrac"><span id="MathJax-Span-226" class="mn">9}{</span><span id="MathJax-Span-227" class="mn">81}A
Area(3)=\frac{</span><span id="MathJax-Span-235" class="mstyle"><span id="MathJax-Span-236" class="mrow"><span id="MathJax-Span-237" class="mfrac"><span id="MathJax-Span-238" class="mn">9}{</span><span id="MathJax-Span-239" class="mn">81}</span></span></span></span><span id="MathJax-Span-240" class="mi">A</span><span id="MathJax-Span-241" class="mo">− \frac{</span><span id="MathJax-Span-242" class="mstyle"><span id="MathJax-Span-243" class="mrow"><span id="MathJax-Span-244" class="mfrac"><span id="MathJax-Span-245" class="mn">4}{</span><span id="MathJax-Span-246" class="mn">81}</span></span></span></span><span id="MathJax-Span-247" class="mi">A</span><span id="MathJax-Span-248" class="mo">=\frac{</span><span id="MathJax-Span-249" class="mstyle"><span id="MathJax-Span-250" class="mrow"><span id="MathJax-Span-251" class="mfrac"><span id="MathJax-Span-252" class="mn">5}{</span><span id="MathJax-Span-253" class="mn">81}</span></span></span></span><span id="MathJax-Span-254" class="mi">A</span></span></span></span></span></span>[\latex]</p> <p class="q-text qu-display--block">and so on…</p> <p class="q-text qu-display--block">Area<span class="qtext_span qtext_math _1sNWenR7FDgH9GLRfri58K _1xzGCdFnEIP2F4OzuIN1m9"><span id="MathJax-Element-34-Frame" class="MathJax" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mo stretchy="false">(</mo><mn>4</mn><mo stretchy="false">)</mo><mo>=</mo><mstyle displaystyle="false" scriptlevel="0"><mfrac><mn>7</mn><mn>81</mn></mfrac></mstyle><mi>A</mi></math>"><span id="MathJax-Span-258" class="math"><span id="MathJax-Span-259" class="mrow"><span id="MathJax-Span-260" class="mo">(</span><span id="MathJax-Span-261" class="mn">4</span><span id="MathJax-Span-262" class="mo">)</span><span id="MathJax-Span-263" class="mo">=[latex]\frac{</span><span id="MathJax-Span-264" class="mstyle"><span id="MathJax-Span-265" class="mrow"><span id="MathJax-Span-266" class="mfrac"><span id="MathJax-Span-267" class="mn">7}{</span><span id="MathJax-Span-268" class="mn">81}A

Area(5)=\frac{</span><span id="MathJax-Span-276" class="mstyle"><span id="MathJax-Span-277" class="mrow"><span id="MathJax-Span-278" class="mfrac"><span id="MathJax-Span-279" class="mn">9}{</span><span id="MathJax-Span-280" class="mn">81}A

Area(6)=\frac{</span><span id="MathJax-Span-288" class="mstyle"><span id="MathJax-Span-289" class="mrow"><span id="MathJax-Span-290" class="mfrac"><span id="MathJax-Span-291" class="mn">11}{</span><span id="MathJax-Span-292" class="mn">81|}A

Area(7)=\frac{</span><span id="MathJax-Span-300" class="mstyle"><span id="MathJax-Span-301" class="mrow"><span id="MathJax-Span-302" class="mfrac"><span id="MathJax-Span-303" class="mn">13}{</span><span id="MathJax-Span-304" class="mn">81}A

Area(8)=\frac{</span><span id="MathJax-Span-312" class="mstyle"><span id="MathJax-Span-313" class="mrow"><span id="MathJax-Span-314" class="mfrac"><span id="MathJax-Span-315" class="mn">15}{</span><span id="MathJax-Span-316" class="mn">81}[\latex]</span></span></span></span><span id="MathJax-Span-317" class="mi">A</span></span></span></span></span></p> <p class="q-text qu-display--block">Area<span class="qtext_span qtext_math _1sNWenR7FDgH9GLRfri58K _1xzGCdFnEIP2F4OzuIN1m9"><span id="MathJax-Element-39-Frame" class="MathJax" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mo stretchy="false">(</mo><mn>9</mn><mo stretchy="false">)</mo><mo>=</mo><mstyle displaystyle="false" scriptlevel="0"><mfrac><mn>17</mn><mn>81</mn></mfrac></mstyle><mi>A</mi></math>"><span id="MathJax-Span-318" class="math"><span id="MathJax-Span-319" class="mrow"><span id="MathJax-Span-320" class="mo">(</span><span id="MathJax-Span-321" class="mn">9</span><span id="MathJax-Span-322" class="mo">)</span><span id="MathJax-Span-323" class="mo">=[latex]\frac{</span><span id="MathJax-Span-324" class="mstyle"><span id="MathJax-Span-325" class="mrow"><span id="MathJax-Span-326" class="mfrac"><span id="MathJax-Span-327" class="mn">17}{</span><span id="MathJax-Span-328" class="mn">81}[\latex]</span></span></span></span><span id="MathJax-Span-329" class="mi">A</span></span></span></span></span></p> <p class="q-text qu-display--block">So depending on which stripes are shaded, you should be able to figure out the area in terms of <span class="qtext_span qtext_math _1sNWenR7FDgH9GLRfri58K _1xzGCdFnEIP2F4OzuIN1m9"><span id="MathJax-Element-40-Frame" class="MathJax" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>A</mi></math>"><span id="MathJax-Span-330" class="math"><span id="MathJax-Span-331" class="mrow"><span id="MathJax-Span-332" class="mi">A</span></span></span></span></span><span class="q-box qu-userSelect--text">, set this <span class="qtext_span qtext_math _1sNWenR7FDgH9GLRfri58K _1xzGCdFnEIP2F4OzuIN1m9"><span id="MathJax-Element-41-Frame" class="MathJax" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mo>=</mo><mn>135</mn></math>"><span id="MathJax-Span-333" class="math"><span id="MathJax-Span-334" class="mrow"><span id="MathJax-Span-335" class="mo">=</span><span id="MathJax-Span-336" class="mn">135</span></span></span></span></span></span><span class="q-box qu-userSelect--text">, then solve for <span class="qtext_span qtext_math _1sNWenR7FDgH9GLRfri58K _1xzGCdFnEIP2F4OzuIN1m9"><span id="MathJax-Element-42-Frame" class="MathJax" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>A</mi></math>"><span id="MathJax-Span-337" class="math"><span id="MathJax-Span-338" class="mrow"><span id="MathJax-Span-339" class="mi">A</span></span></span></span></span></span><span class="q-box qu-userSelect--text">.</span></p> <p>So [latex]\frac{135}{A} = \frac{45}{81} gives an area of 243 square units.

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12. In the IT department of backrub, the administrator password is changed every month. The team of administrator spread across the globe, receive an 8 digits number via email. This number is to be prefixed with a single-digit number and suffixed with a single-digit number to get the actual password. The password is divisible by 11 and 8. If the team received 54218345 this month. Then which of the following pairs give valid prefix and suffix respectively?

8,7

8,7

17.55%

7,8

7,8

40.13%

6,8

6,8

19.3%

8,6

8,6

23.03%

By backtracking

Option a)

The password would be 8653513649

8653513649 ÷ 11 = 786683059

8653513649 ÷ 8 = 1081689206 Remainder 1

⇒ Number cannot be divisible by 8

Option b)

The password would be 7653513648

7653513648 ÷ 11 = 695773968

7653513648 ÷ 8 = 956689206

⇒ The number is both divisible by 8 and 11

Option c)

The password would be 3653513644

3653513644 ÷ 11 = 332137604

3653513644 ÷ 8 = 456689205 Remainder 4

⇒ The number cannot be divisible by 8

Option d)

The password would be 2653513647

2653513647 ÷ 11 = 241228513 Remainder 4

2653513647 ÷ 8 = 331689205 Remainder 7

⇒ The number cannot be divisible by 8 and 11

Answer: (b) 7, 8

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13. The people of the land of unsymmetric to ensure that there is very little symmetry in life. Even their unit of length (no one knows what it is) is called as unseen. It is their pride that the front wheel and the rear wheels of their bikes are of different sizes but are made so that they will not slip on the road. In a certain model of bike, the radius of the front wheel is 28 enzymes and that of the back wheels is 14 unsyms after driving a certain distance if a front wheel had revolution 54 times how many revolutions would the back wheel have undergone?

111

111

15.08%

110

110

21.82%

109

109

15.71%

108

108

47.39%

Find the circumference of the front wheel:

Circumference = 2πr

Circumference = 2π(28) = 56π unsyms

Find the total distance covered by the front wheel:

1 revolution = 56π unsyms

54 revolutions = 56π x 54 = 3024π unsyms

Find the circumference of the back wheel:

Circumference = 2πr

Circumference = 2π(14) = 28π unsyms

Find the number of revolutions made by the back wheel:

Number of revolutions = 3024π ÷ 28π = 108

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14. Rs. 3000 is distributed among A, B, and C such that A gets 2/3rd of what B and C together get and C gets ½ of what A and B together get. Find C’s share.

1000

1000

57.71%

1004

1004

19.12%

2000

2000

15.02%

1001

1001

8.16%

Step-by-step explanation:

first of all a+b+c=3000 --------(1)eqn

second: 2/3(b+c)=a; -----------(2)eqn

third: (a+b)/2=c; -----------------(3)eqn

so we got 3 equation and 3 variable

a+b+c=3000; (1)eqn

a+b-2c=0; (3)eqn

subtracting both we get c=1000

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15. Two finals are scheduled - The Wimbledon match and the World Cup Cricket at the same time. Anu wants to watch the Wimbledon finals and her brother Vinu wants to watch WCC final. They decide to roll a tetrahedral die twice. The tetrahedral Is numbered 1,2,3,4 on its four sides and all numbers are equally likely to appear. Anu rolls fist and then Vinu rolls. If the number on the first roll Is strictly greater than the number on the second roll. Anu wins and gets to watch Wimbledon. What Is the probability that Anu will get to watch Wimbledon?

\frac{3}{10}

\frac{3}{10}

16.36%

\frac{3}{8}

\frac{3}{8}

55.17%

\frac{1}{8}

\frac{1}{8}

16.2%

\frac{5}{8}

\frac{5}{8}

12.26%

The probability that Anu will get to watch the Wimbledon match is 3/8

Step-by-step explanation:

Probability of any number appearing = 1/4

Anu wins in the following condition

1) If 1 occus on the first roll then there is no chance of her winning because in the next roll the number appeaing will be either 1 or greater than 1

2) If 2 appears on 1st roll then Anu will win if 1 appears on the second roll

3) If 3 appears on the 1st roll then Anu will win if 1 or 2 appears on the second roll

4) If 4 appears on the first roll then Anu will win if 1, 2, 3 appears on the second roll

Therefore, the probability of Anu winning

\frac{1}{4}\times \frac{1}{4} + \frac{1}{4}\times \frac{2}{4} + \frac{1}{4}\times \frac{3}{4} = \frac{3}{8}

 

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TCS NQT Verbal Detailed Analysis

  • Total number of Questions: 25 MCQ's
  • Total Time: 75 mins (shared)
  • Difficulty: Moderate
  • Marking Scheme: No negative Marking
  • Cut-Off: 80%
> Start

Grammar

0/100%
Completed

> Start

Reading Comprehension

0/100%
Completed

> Start

Cloze Test

0/100%
Completed

> Start

Synonym and Antonym

0/100%
Completed

> Start

Spelling

0/100%
Completed

> Start

Selecting Words

0/100%
Completed

> Start

Passage Ordering

0/100%
Completed

> Start

Error Identification

0/100%
Completed

> Start

Error Correction

0/100%
Completed

> Start

Sentence Completion

0/100%
Completed

1. Fill in the blanks with suitable option-

The Super twenty just A …….. their first baseball game of the new season; I believe there is much to be B……… about. Although they lost, it was against an excellent team that had won the championship last year. The Super twenty fell behind early but C…….. excellent teamwork and D…….. back to tie the game. The team had 15 hits and scored 8 runs, which was excellent! Unfortunately, they made 5 fielding errors, which kept the other team in the lead the entire game. The game ended with the umpire E…… a bad call, and if the call had gone the other way, The Super twenty might have actually won the game. It wasn’t a victory, but I say The Super twenty look like they have a shot at the championship, especially if they F……… to improve.

Fill space A with correct option -

played

played

78.47%

plays

plays

11.48%

play

play

8.81%

None

None

1.24%

It will be played, as follows to just play so it goes to past action as the action is already done.

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2. Fill in the blanks with suitable option-

The Super twenty just A …….. their first baseball game of the new season; I believe there is much to be B……… about. Although they lost, it was against an excellent team that had won the championship last year. The Super twenty fell behind early but C…….. excellent teamwork and D…….. back to tie the game. The team had 15 hits and scored 8 runs, which was excellent! Unfortunately, they made 5 fielding errors, which kept the other team in the lead the entire game. The game ended with the umpire E…… a bad call, and if the call had gone the other way, The Super twenty might have actually won the game. It wasn’t a victory, but I say The Super twenty look like they have a shot at the championship, especially if they F……… to improve.

Fill space B with correct option-

excitement

excitement

15.1%

excited

excited

70.13%

excite

excite

11.98%

none

none

2.79%

It will be excited as follows to first part of the sentence so it is in past tense.

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3. Fill in the blanks with suitable option-

The Super twenty just A …….. their first baseball game of the new season; I believe there is much to be B……… about. Although they lost, it was against an excellent team that had won the championship last year. The Super twenty fell behind early but C…….. excellent teamwork and D…….. back to tie the game. The team had 15 hits and scored 8 runs, which was excellent! Unfortunately, they made 5 fielding errors, which kept the other team in the lead the entire game. The game ended with the umpire E…… a bad call, and if the call had gone the other way, The Super twenty might have actually won the game. It wasn’t a victory, but I say The Super twenty look like they have a shot at the championship, especially if they F……… to improve.

Fill space C with correct option-

showed

showed

79.18%

shows

shows

16.46%

show

show

3.52%

none

none

0.84%

It will be showed as paragraph is in past tense so v3 will be there(showed).

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4. Fill in the blanks with suitable option-

The Super twenty just A …….. their first baseball game of the new season; I believe there is much to be B……… about. Although they lost, it was against an excellent team that had won the championship last year. The Super twenty fell behind early but C…….. excellent teamwork and D…….. back to tie the game. The team had 15 hits and scored 8 runs, which was excellent! Unfortunately, they made 5 fielding errors, which kept the other team in the lead the entire game. The game ended with the umpire E…… a bad call, and if the call had gone the other way, The Super twenty might have actually won the game. It wasn’t a victory, but I say The Super twenty look like they have a shot at the championship, especially if they F……… to improve.

Fill space D with correct option-

will come

will come

20.48%

Come

Come

9.22%

came

came

68.54%

none

none

1.76%

It will be came as it is the v3 form of come, as the sentence is in past tense.

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5. Fill in the blanks with suitable option-

The Super twenty just A …….. their first baseball game of the new season; I believe there is much to be B……… about. Although they lost, it was against an excellent team that had won the championship last year. The Super twenty fell behind early but C…….. excellent teamwork and D…….. back to tie the game. The team had 15 hits and scored 8 runs, which was excellent! Unfortunately, they made 5 fielding errors, which kept the other team in the lead the entire game. The game ended with the umpire E…… a bad call, and if the call had gone the other way, The Super twenty might have actually won the game. It wasn’t a victory, but I say The Super twenty look like they have a shot at the championship, especially if they F……… to improve.

Fill space E with correct option-

making

making

14.43%

made

made

46.72%

make

make

6.87%

None

None

31.98%

It will be making as the given sentence is in past continuous tense. so it is in form of v1+ing.

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6. Fill in the blanks with suitable option-

Rohan used to do well in school, and people thought he was smart because of it. But it’s not true. In fact, three years ago he A…….. in school. However, two years ago he decided to get serious about school and made a few changes in his lifestyle and routine. First, he B……… he C…….. become interested in whatever was being taught in the class, regardless of what other people D……. . He decides he would work hard every day and never give up on any assignment. He decided to never, never fall behind. Finally, he E……. school a priority over friends and fun. After the F…….. these changes, he became an active participant in classroom discussions, his test scores began to rise. Some students made fun of him because “He was smart.” How exciting! It seems that being smart is simply a matter of working hard and being interested. After all, learning a new sport or a video game is hard work even when you are interested. Unfortunately, learning a new video game takes you nowhere.

Fill the blank E with correct option-

made

made

74.88%

makes

makes

15.07%

will make

will make

8.12%

none

none

1.93%

It should be made as given sentence is in past tense, so v3 will be used of make that is made.

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7. Choose a word that is OPPOSITE to the meaning of the word given below:

SYCOPHANT

Sincere

Sincere

53.4%

Atheist

Atheist

16.36%

Reserved

Reserved

14.51%

Parasite

Parasite

15.74%

Answer - sincere

Sycophant means to be a flatterer (false) while sincere means to be unflattering.

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8. In the question a part of the sentence is bold. Alternatives to the bold part is given which may improve the construction of the sentence. Select the correct alternative. :

Neha was fined for careless driving.

got fined

got fined

52.66%

will fined

will fined

4.08%

was to be fined

was to be fined

14.42%

No improvement needed

No improvement needed

28.84%

As word fined is well suitable here with respect to the time frame of the given sentence as the sentence is in the past tense therefore the verb also will be in  the past tense. Therefore this sentence does not need any improvement.

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9. Find the error in given sentence and choose the correct answer :

I lived in Rajasthan since 1931.

I had been lived in Rajasthan since 1931.

I had been lived in Rajasthan since 1931.

9.17%

I have been living in Rajasthan since 1931.

I have been living in Rajasthan since 1931.

62.39%

I had been living in Rajasthan since 1931

I had been living in Rajasthan since 1931

26.61%

None

None

1.83%

 Explanation: The sentence is representing the course of action which happened in the past is continued till present. So the sentence will be in present perfect continuous tense.

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10. Choose an alternate option for the italicized phrase in the sentence to create a better sentence:

Not only did everyone ate the chocolate cake and loved its taste too.

everybody have eaten chocolate cake but also loved

everybody have eaten chocolate cake but also loved

18.48%

everyone eat the chocolate cake but also loved

everyone eat the chocolate cake but also loved

28.71%

everyone eat the chocolate cake also have loved

everyone eat the chocolate cake also have loved

16.17%

everyone had eaten the chocolate cake but also had loved

everyone had eaten the chocolate cake but also had loved

36.63%

Answer - everyone eat the chocolate cake but also loved

with not only we use but also. when writing a sentence with not only we use the present or first form of verb in the first position and second form in the second position. Here - Eat, loved.

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TCS NQT Advance Coding Detailed Analysis

  • Total number of Questions:  2 Ques
  • Total Time: 55 mins
  • Difficulty: High
  • Marking Scheme: No Negative Marking
  • Cut-Off: 75%
> Start

Coding Question 11

0/100%
Completed

> Start

Coding Question 12

0/100%
Completed

> Start

Coding Question 13

0/100%
Completed

> Start

Coding Question 14

0/100%
Completed

> Start

Coding Question 15

0/100%
Completed

> Start

Coding Question 16

0/100%
Completed

> Start

Coding Question 17

0/100%
Completed

> Start

Coding Question 18

0/100%
Completed

> Start

Coding Question 19

0/100%
Completed

> Start

Coding Question 20

0/100%
Completed

> Start

Coding Question 21

0/100%
Completed

See More...

> Start

Coding Question 22

0/100%
Completed

> Start

Coding Question 23

0/100%
Completed

> Start

Coding Question 24

0/100%
Completed

> Start

Coding Question 25

0/100%
Completed

> Start

Coding Question 26

0/100%
Completed

> Start

Coding Question 27

0/100%
Completed

> Start

Coding Question 28

0/100%
Completed

> Start

Coding Question 29

0/100%
Completed

> Start

Coding Question 30

0/100%
Completed

> Start

Coding Question 31

0/100%
Completed

> Start

Coding Question 32

0/100%
Completed

See More...

> Start

Coding Question 33

0/100%
Completed

> Start

Coding Question 34

0/100%
Completed

> Start

Coding Question 35

0/100%
Completed

> Start

Coding Question 36

0/100%
Completed

> Start

Coding Question 37

0/100%
Completed

> Start

Coding Question 38

0/100%
Completed

> Start

Coding Question 39

0/100%
Completed

> Start

Coding Question 40

0/100%
Completed

TCS NQT Part A - Reasoning Ability Test Detailed Analysis

  • Total number of Questions:  20 MCQ's
  • Total Time: 75 mins (shared)
  • Difficulty: Moderate
  • Marking Scheme: No Negative Marking
  • Cut-Off: 75%
> Start

Word Pattern

0/100%
Completed

> Start

Number Series

0/100%
Completed

> Start

Blood Relation

0/100%
Completed

> Start

Coding - Decoding

0/100%
Completed

> Start

Data Sufficiency

0/100%
Completed

> Start

Seating Arrangement

0/100%
Completed

> Start

Directional Sense

0/100%
Completed

> Start

Statement and Conclusion

0/100%
Completed

> Start

Mathematical Operational Arrangement

0/100%
Completed

> Start

Syllogism

0/100%
Completed

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Visual Reasoning

0/100%
Completed

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Logical Venn Diagrams Based DI Questions

0/100%
Completed

TCS NQT Advance Aptitude Detailed Analysis

  • Total number of Questions: 10 MCQ's
  • Total Time: 35 mins (shared)
  • Difficulty: High
  • Marking Scheme: No Negative Marking
  • Cut-Off: 75%
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Probability

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Clocks and Calendar

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Permutation and Combination

0/100%
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Number System and HCF & LCM

0/100%
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Percentages

0/100%
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Allegations and Mixtures

0/100%
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Ratios and Proportion

0/100%
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Averages

0/100%
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Work and Time

0/100%
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Series and Progressions

0/100%
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Speed,Distance and Time

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Equations

0/100%
Completed

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Geometry

0/100%
Completed

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Problem on Ages

0/100%
Completed

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DI

0/100%
Completed

TCS NQT Advance Reasoning Detailed Analysis

  • Total number of Questions:  10 MCQ's
  • Total Time: 35 mins (shared)
  • Difficulty: High
  • Marking Scheme: No Negative Marking
  • Cut-Off: 75%
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Meaningful Word Creation

0/100%
Completed

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Number Series

0/100%
Completed

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Blood Relation

0/100%
Completed

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Coding Decoding

0/100%
Completed

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Ages

0/100%
Completed

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Data Sufficiency

0/100%
Completed

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Seating Arrangement(Complex)

0/100%
Completed

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Odd Man Out

0/100%
Completed

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Distance and Direction

0/100%
Completed

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Statement and Conclusion

0/100%
Completed

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Symbols and Notation

0/100%
Completed

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Visual Reasoning

0/100%
Completed

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Prepositional Reasoning

0/100%
Completed

TCS NQT 2023 Exam Pattern detailed analysis:

Exam Pattern

Note: Traits may or may not come in On-Campus drive, it is varying from college to college. Also, it contains only 1 image selection question which is fresh for everyone. So, attempt this section carefully.

 

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Quiz-1 (Free)

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Quiz-2 (Free)

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Quiz-3 (Free)

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Quiz-4 (Free)

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Quiz-5 (Free)

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Quiz-6 (Paid)

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Quiz-7 (Paid)

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Quiz-8 (Paid)

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Quiz-9 (Paid)

0/100%
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Quiz-10 (Paid)

0/100%
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Quiz-11 (Paid)

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Quiz-12 (Paid)

0/100%
Completed

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Quiz-13 (Paid)

0/100%
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Quiz-14 (Paid)

0/100%
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Quiz-15 (Paid)

0/100%
Completed

TCS NQT Practice Mock Test 2023

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Mock Test 1

0/100%
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Mock Test 2

0/100%
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Interview Preparation TCS NQT 2023

L&T InfoTech Interview Preparation

Click here to read more on TCS NQT Interview Preparation Dashboard

TCS Technical Check List given by HR’s to Technical Interviewer –

For CS/IT/MCA and other coding Domains –

  1. Try to stick to Technologies and Languages mentioned in Resume.
  2. Basic Questions on C / OOPS / Software Engineering / DSA i.e. you will necessarily be asked questions from these.
  3. Ask Questions about final year projects

For Non Coding Branches like EEE, Mech etc –

  1. Stick to Technologies and Languages mentioned in Resume.
  2. Very basic Questions on C / OOPS / other programming Language mentioned in Resume.
  3. Talk about Final year Projects – Can ask to make Circuit Diag / Diagrams / Formulas / Definitions only from topics related to Final year project of his respective Branch.
  4. Ask student about his favorite subject and ask basic questions on it.

Candidate Experience for TCS NQT Question Paper

Click here to read more on TCS NQT Interview Preparation Dashboard

  • Name: Mitanshu Mehta
  • College: Teerthanker Mahaveer University
  • Branch: Computer Science
  • Type of interview: On-Campus Interview

Student Interview

During our last semester TCS visited our campus for its recruitment drive. As it is one of the India’s leading IT Service and consultation organization, I really wanted to join it. I had no clues about how to organize myself for this interview. However, my seniors recommended me some Practice Sample Papers that were available at Prepinsta to brush up my programming and reasoning skills. The eligibility criteria for this drive is mentioned below:

Eligibility Criteria of  Interview

Qualification Full-time graduate from B.E/B.Tech/M.Tech./M.Sc./MCA
Eligible Streams All engineering fields
%Criteria 60% marks throughout academics
Backlogs 1 Active Backlog.
Gap Criteria Overall Gap not exceeding two years

Number of Rounds

Our professor informed us that we have to complete 2 written and 2 interview rounds to crack the interview. The rounds were Part A(Foundation Section), Part (Advance Section) technical interview round, and HR interview round. The written examination was divided into 2 rounds, which were further divided into several sections:

  1. Part A (Foundation Section)
    • Numerical Ability
    • Verbal Ability
    • Reasoning Ability
  2. Part B (Advance Section)
    • Advance Quantitative Ability
    • Advance Reasoning Ability
    • Advance Coding

The average time duration and number of questions for this round are detailed below:

TCS ITP Overall Pattern - Detailed Information

TCS NQT Section

Total Timee
Part A : Foundation Section
Traits 75 mins (shared)
Numerical Ability 75 mins (shared)
Verbal Ability 75 mins (shared)
Reasoning Ability 75 mins (shared)
Part B : Advanced Section (Mandatory for Digital Aspirants)
Advanced Quantitative Ability 35 mins (shared)
Advanced Reasoning Ability 35 mins (shared)
Advanced Coding 55 mins
Total Duration 165 mins

Since I Prepped up well with the help of the practice papers published by Prepinsta , and as most of the questions were of similar pattern to the sample papers itself  so I clear both round with good marks.

*Also, this experience is based on TCS ITP Interview Experience, because this year TCS NQT has same pattern as TCS ITP.

Round 2:

Technical Interview

The technical interview was divided in two parts. First was TCS Ninja (for students who only qualified in the Foundation Section) and the other one was TCS Digital (for Students who also qualified the Advance section).

TCS Ninja

Since TCS is a renowned establishment, the interview rounds were a bit challenging. I must admit that it was a very diverse interview wherein I was asked questions related my field. Some of the questions were:

1.)    Questions based on the fundamentals of C, C++ and dot net.

2.)    Data Structure,

3.)    Computer networking, etc.

TCS Digital

The second interview as conducted with TCS Digital. Now, this was a tricky one of all the other rounds, where I was asked the below mentioned questions:

  1. Check if Binary Tree is BST or not?
  2. Remove duplicates from a string, do it in place
  3. What is the least common ancestor of a Binary Tree or a Binary search tree?
  4. Check if the binary tree is balanced or not?

I somehow managed to answer all the question and sat that day my luck was with me. The interviewer was happy with me and told me that I was selected for the final HR round.

Round 3:

HR Interview

When I went inside the room at first the HR looked very rude, but when he offered me a glass of water, I felt a bit relaxed. He asked me for my CV and started with the interview. He asked me:

1.)    What are your achievements?

2.)    What are your greatest professional strengths?

3.)    How do you feel about working in nights shift?

4.)    What is your commitment to the company?

This round also went pretty well and my result proved it all as I was selected for TCS Digital. That was the happiest day of my life.

Student Details (This is previous year interview experience)

  • Name: Siddhant Verma
  • College: R.V. College of Engineering, Bangalore
  • Branch: ECE
  • Type of interview: Off-campus Interview

Student Interview

Two months back, the placement cell of our college notified all the final year students that TCS will be conducting a recruitment drive in our Off campus very soon. Since, PrepInsta is partnered with our college, we got emails from our placement cell to only study from PrepInsta and they had bought online classes from PrepInsta for all students.. Immediately, everyone applied for it. But due to the eligibility criteria of a minimum 60% marks throughout the academics career, only a few students were eligible for the drive. Fortunately, I was one of those few students. The TCS selection process had 3 rounds;

  1. Online Written Test
  2. Technical Interview Round
  3. HR Interview Round

Written Test

The first round consists of four sections, English, quantitative aptitude, programming concept, and coding.

  • In the English Section, there were 15 questions of sentence completion. Time allocated was 10 minutes.
  • In Quantitative Aptitude, there were 15 questions, and the time allocated was 30 minutes. This section had questions based on time & work, profit & loss, number, decimal fraction, time, speed & distance, coordinate geometry, and blood relations.
  • In the Programming Concept section, there were 10 questions, and time allotted was 20 minutes. The topics asked were Iteration, recursion, procedural vs. Oop, Algorithms, and Data Structures.
  • In the Coding Section, there was only one question, and the time allocated was 30 minutes. The question was based on Perl topic. Overall around 80% of the questions were of similar pattern as of PrepInsta.

Technical Interview

After the written round 3-4 days later I got mail from PrepInsta that I am selected in TCS and after 2 more days I got mail from TCS as well. My Interview center was in Mysore unfortunately. So I had to travel there. There was a technical interview which comprised of two interviews; TCS Ninja and TCS Digital. First, I was asked to go in the room for Ninja interview. When I entered the technical interviewer had a grim expression, so I was a bit scared at the first instance. Bust as soon as our conversation started; I was very comfortable talking to him. He asked me questions on the fundamental of C, C++, JAVA, DBMS, Oop, and my major final year project.

  1. What is the binary search?
  2. Explain the Object Oriented Programming.
  3. What is the difference between pass by value and pass by reference in c?

Except one, I knew all the answers. The interviewer was happy with me and sent me for the second Digital Interview. In this round, I was asked some technical questions:

  • What is Garbage collector in Java?
  • Explain the Kadane algorithm.
  • Discuss also?

The round was very tricky and the toughest of all. I answer what all I knew, and luckily, all my answers were correct. The interviewer congratulated me for clearing the second round and wished me luck for the HR round.

HR Interview

The HR round was very simple and went pretty well. As soon as I entered the HR offered me a glass of water and asked me about my personal life, strength and weakness, future goals, and expectations. He was primarily evaluating my communication skills and confidence by asking these questions. Then he asked me if I had any query or question. I asked him to give me feedback about my interview. He said you need to work on your pronunciations and rest all is great. I thanked him and left.

A week later, results were declared, and fortunately, I reserved my seat in TCS. Then I attended Digital interview as well but it went really bad as they were asking questions from dynamic programming and Data structures etc. But, I was not selected in TCS Digital but was selected in TCS Ninja.

*Note: This is previous TCS NQT interview experience of 2021.

Coming Soon!!

Analytics for TCS NQT 2023

Total Number of Question : 88 Questions

66
Part A

22
Part B

Overall Time: : 165 mins

75 mins (shared)
Time

90 mins (shared)
Time

Part A

Cut Off85%

Difficulty75%

Importance80%

Part B

Cut Off85%

Difficulty85%

Importance80%

Video

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Latest TCS NQT 2023 Recruitment Process
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Frequently Asked Questions

Getting the coding output is really really important, if you don't get 100% output then you will not get called for interview even if you've answered all the questions correctly.

No, as TCS NQT has now updated their exam pattern and syllabus, they have not mentioned negative marking anywhere on their registration process and we belive that this year there will be no negative marking.

Disclaimer: The Words Like “Placement Papers” and “Previous Year Papers” are used here for Google Search Purposes only and may not be. All these questions could be freely available on the internet, we are only charging students for the PrepInsta’s Mock Test experiences and Analytics as well as preparation for the exam. Prepinsta does not guarantee any recurrence of the questions in the exam however we believe that from our practise questions the exam should atleast be similar in pattern as per syllabus or difficulty. These are only practise mock questions. PrepInsta has compiled these from various internet sources and made them as per mock experience for students ease and are offering analytics as per performance

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December 7, 2022

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