Problem 13

• Gourav

n=int(input())
res=0
temp=n
lenn=0
while(temp!=0):
lenn+=1
temp=temp//10
for i in range(lenn):
res=res*(10)+n%10
n=n//10
print(res)

• Vaibhav

Python:
num=str(input())
print(num[::-1]

• shushank

#PYTHON
n=int(input())
c=0
while n!=0:
a1=n%10
c=c*10+a1
n=n//10
print(c)

• Sunny

n=int(input())
rev=[]
for i in str(n):
rev.append(int(i))
reverse_final=rev[::-1]
for i in range(len(reverse_final)):
print(reverse_final[i],end=””)

• Raman

// Online C compiler to run C program online
#include

int main() {
int n,rem,c=0,i=0;
int a[20];
scanf(“%d”,&n);
while(n>0){
rem=n%10;
a[i]=rem;
n=n/10;
i++;
c++;
}
for(i=0;i<c;i++){
printf("%d",a[i]);
}

return 0;
}

• Richik

PYTHON 3:
k=0
i=0
def rev(n):
global k
global i
if n==0:
return
else:
rev(n//10)
k+=(n%10)*10**i
i+=1
rev(int(input()))
print(k)

• Harsha

def reverse(n):
str_n=str(n)
if n<0:
str_n=str_n[1:]
str_n=str_n[::-1]
str_n='-'+str_n
else:
str_n=str_n[::-1]
return int(str_n)
n=int(input())
print(reverse(n))

• avi gehlot

#python code here
number =int(input())
reverse=0
while number>0:
remainder=number%10
reverse=reverse*10+remainder
number=number//10
print(reverse)

• Taha

#PYTHON
n= input()
print(reversed(n))