Problem 10

9 comments on “Problem 10”


  • swapnil

    public static void main(String[] args) {
    // TODO Auto-generated method stub

    Scanner s=new Scanner(System.in);
    String s1=s.nextLine();
    String[] s2=s1.split(“”);
    ArrayList arrList=new ArrayList();
    ArrayList res=new ArrayList();
    for(String i:s2) {
    arrList.add(Integer.parseInt(i));
    }
    System.out.println(Math.pow(2,2));
    Math.pow(4, 3);
    if(arrList.size()%3!=0) {
    int m = arrList.size()%3;
    int k=3-m;
    for(int i=0;i<k;i++) {
    arrList.add(i,0);
    }
    }
    int size=arrList.size()/3;
    for(int i=0;i=0) {
    if(arrList.get(0)==1) {
    sum+= Math.pow(2,p);
    }
    arrList.remove(0);
    p-=1;
    }

    res.add(sum);
    } System.out.println(res);
    int index=0;
    for(float i:res) {
    arrList.add(0, (int) i);

    index+=1;
    }
    Collections.reverse(arrList);
    for(int i:arrList) {
    System.out.print(i);
    }
    }


  • swapnil

    arr=[int(i) for i in input()]
    if len(arr)%3!=0:
    extraZeroToAdd=len(arr)%3
    for i in range(3-extraZeroToAdd):
    arr.insert(0,0)
    size=len(arr)//3
    res=[]
    for i in range(int(size)):
    c=2
    sum=0
    while c>=0:
    if(arr[0]==1):
    sum=sum+2**c
    c=c-1
    arr.pop(0)
    res.append(sum)

    print(”.join(str(i) for i in res))


  • The Bong

    public class BinaryToOctal {
    public static void main(String[] args) {
    System.out.println(binToOct(“101001”));
    }
    static int binToOct(String number) {
    int dec = Integer.parseInt(number , 2);
    int oct = Integer.parseInt(Integer.toOctalString(dec));
    return oct;
    }
    }


  • Febin

    c=0
    s=0
    n=int(input(“Enter number:”))
    while n > 0:
    r=int(n%10)
    p=pow(8,c)
    s=s+(r*p)
    n=int(n/10)
    c=c+1
    print(s)


  • Bathula

    #python
    binary = input(“Enter any number in Binary Format: “);
    if binary == ‘x’:
    exit();
    else:
    temp = int(binary, 2);
    p=oct(temp)
    a=p.replace(“0o”,””)
    print(a)


  • Bathula

    #python
    binary = input(“Enter any number in Binary Format: “);
    if binary == ‘x’:
    exit();
    else:
    temp = int(binary, 2);
    print(temp)
    p=oct(temp)
    a=p.replace(“0o”,””)
    print(a)