Problem 18

March 5, 2021

11 comments on “Problem 18”


  • Satyam

    #include
    using namespace std;

    long int binary(int);
    long int binary(int num){
    int binarynum=0,temp=1;
    while(num){

    int last = num%2;
    num = num/2;
    binarynum = binarynum + last*temp;
    temp = temp * 10;
    }
    return binarynum;
    }

    int main (int argc, char *argv[]){
    if(argc>3){
    cout<<"\nInvalid Input";
    }
    else{
    int num1 = atoi(argv[1]);
    int num2 = atoi(argv[2]);
    int sum = num1+num2;
    long int binaryNum = binary(sum);
    cout<<binaryNum;
    }
    return 0;
    }

    0

  • rohan

    #include
    int main()
    {
    int i,j,k,l,x,y,r,arr[20],count=0;
    printf(“enter numbers which needs to be added\n”);
    scanf(“%d%d”,&k,&l);
    x=k+l;
    for(i=0;x>0;++i)
    {
    arr[i]=x%2;
    x=x/2;
    count++;
    }
    for(j=count-1;j>=0;–j)
    printf(“%d “,arr[j]);
    return 0;
    }

    0

  • rohan

    #include
    int main()
    {
    int i,j,k,l,x,y,r,arr[20],count=0;
    printf(“enter numbers which needs to be added\n”);
    scanf(“%d%d”,&k,&l);
    x=k+l;
    for(i=0;i<=20;++i)//454
    {
    arr[i]=x%2;
    x=x/2;//227
    count++;
    if(x=0;–j)
    printf(“%d “,arr[j]);
    return 0;
    }

    0

  • SRIHARI TIRUMALAGUDIMELLA

    #include
    #include
    int main(int argc, char *argv[])
    {
    int sum;

    if(argc == 1){
    printf(“enter number”);
    }
    else{
    int i,j,r,a[10];
    sum = atoi(argv[1]) + atoi(argv[2]);
    printf(“sum %d\n”,sum);

    for(i=0;sum>0;i++)
    {
    r = sum%2;
    a[i] = r;
    sum = sum/2;

    }
    printf(“binary format is\n”);
    for(j=i-1;j>=0;j–)
    {
    printf(“%d”,a[j]);
    }
    }
    return 0;
    }

    1

  • avi gehlot

    #Addition of 2 numbers and printing the result in binary
    a,b=map(int, input().split(” “))
    sum=a+b
    x=bin(sum).replace(“0b”,” “)

    print(“binary Addition is :”,x)

    0

  • sachin kushwah

    /* using c program*/

    #include
    void main()
    {
    int a,b,c,rem,arr[100],count=0;
    printf(“Enter two numbers \n”);
    scanf(“%d %d”,&a,&b);
    c=a+b;
    printf(“Addition of commandn line is %d”,c);
    while(c)
    {
    rem=c%2;
    arr[count]=rem;
    count++;
    c=c/2;
    }
    printf(“\nBinary Representation “);
    while(count)
    {
    printf(“%d”,arr[count-1]);
    count–;
    }

    }

    0

  • Hritik

    //Addition of 2 numbers and printing the result in binary Using Command Line Programming

    #include
    void binary(int,int);
    int main(){
    int a,b,res;
    scanf(“%d%d”,&a,&b);
    binary(a+b,2);
    }
    void binary(int n,int base){
    int rem;
    if(n==0)
    return;
    rem = n%base;
    binary(n/base,base);
    printf(“%d”,rem);
    }

    0

  • Mohd Saif

    #python

    n1,n2=map(int,input(“Enter the two number n1 and n2:\n”).split(” “))
    sum=n1+n2
    x=bin(sum)
    print(f”The addition of {n1} and {n2} is:{sum} and its binary representation is {x}”)

    0

  • Ravisankar ka

    public class NewClass6 {
    public static void main(String[] args) {
    Scanner sc=new Scanner(System.in);
    int a=sc.nextInt();
    int b=sc.nextInt();
    int sum=a+b;
    System.out.println(Integer.toBinaryString(sum));
    }
    }

    2

  • Tanaya

    #include
    #include
    int main(int argc,char *argv[])
    {
    if(argc0)
    {
    rem=sum%2;
    binary+=rem*base;
    base=base*10;
    sum=sum/2;
    }
    printf(“%d”,binary);
    return 0;
    }
    }

    4