Tips-And-Tricks-And-Shortcuts To Solve Divisibility

Tips and Tricks  and Shortcuts for Divisibility

    The divisibility rule is the shorthand method of determining weather a number divisible by fixed divisor.
  • Rule for 2
    The number on divisible for 2 when the number is ending with 2,4,6,8.
  • Rule for 3
    If the sum of digit is divisible by 3 than the number is divisible by 3.
  • Rule for 4
    If the last two digit is divisible by 4, than the number is divisible by 4.
  • Rule for 5
    Number is divisible by 5 if the last digit is 0 or 5.
  • Rule for 6
    A number is divisible by if number is divisible by 2 AND 3.
  • Rule for 8
    If the last 3 number is divisible by 8 than the number is divisible by 8
  • Rule for 9
    Same as divisibility of 3.
  • Rule for 10
    If the last digit is 0 than the number is divisible by 10.
Note :- By using Tips and Tricks and Shortcuts for Divisibility Ques can solved easily
tips and tricks and shortucts for divisibility questions

Type 1:Find the largest or smallest number

Question 1.

Find the smallest 4 digit number which is exactly divisible by 41?


Options.

  1. 1000
  2. 1023
  3. 1025
  4. 1012

Correct option: 3

Solution

Smallest 4 digit number is 1000

On dividing 1000 by 41, remainder = 16

Required number = 1000 + (41 – 16) = 1025

Type 2:Which of the following numbers is/or not divisible by given number.

Question 1.

Which of these numbers is divisible by 3?

Options.

  1. 1003
  2. 253
  3. 1031
  4. 1221

Correct option: 4

Solution

Solution: 1003 = 1 + 0 + 0 + 3 = 4, 4 is not divisible by 3

253 = 2 + 5 + 3 = 10, 10 is not divisible by 3

1031 = 1 + 0 + 3 + 1 = 5, 5 is not divisible by 3

1221 = 1 +2 + 2 + 1= 6, 6 is divisible by 3

Type 3: Tips and Tricks to Solve Divisibility Questions.
Find the remainder

Question 1.

Find out the remainder of 212/5

Options.

  1. 1
  2. 2
  3. 0
  4. 3

Correct option: 1

Solution

Convert the base in power

24*24*2= 16 * 16 * 16

Now divide each number by 5

On dividing 16 by 5 we get remainder as 1

Now, multiply all the remainders 1 * 1 * 1 = 1