How To Solve Clocks And Calendar Questions Quickly Definition of Clock and Calendar

We will be discussing How to Solve Clocks and Calendar Questions Quickly to help students to increase efficiency at the time of Examination.

Calendar

In general terms, calendar is a series or chart of pages showing the days, weeks, and months of a particular year, or gives specific seasonal information. A calendar is a system of organizing the days in a year.

Clock

A clock is an instrument to measure time. It is meeting the need to measure intervals of time.

How to Solve Clocks and Calendar questions Quickly: Clock Type

Question 1.

What was the day on 10th November,1581 ?

Options:

A. Thursday

B. Monday

C. Wednesday

D. Tuesday

Solution

10 November 1581 = (1580 years + Period from 1.1.1581 to 10.11.1581)

To calculate number of odd days till 1580, we need

Number of odd days in 1200 years = 0

Number of odd days in 300 years = 1

Number of odd days in 80 years = 20 leap years + 60 ordinary years = 2 odd days

Therefore, 1580 years had 0 + 1 + 2 = 3 odd days

Now, for calculating odd days for 1.1.1581 to 10.11.1581,

January (31 days) + February (28 days) + March (31 days) + (April 30 days) + May (31 days) + June (30 days) + July (31 days) + August (31 days) + September (30 days) + October (31 days) + November (10 days)= 314 days

Total number of odd days in 314 days = (314/7) = 6 odd days

Total Number of odd days corresponding to the given date = 3 + 6 = 9 days = 9/7 = 2 odd days

As per the table, on 10 November 1581 the day was Tuesday.

DaysSundayMondayTuesdayWednesdayThursdayFridaySaturday
Number of odd days0123456

Question 2.

Suppose today is Monday. Now find out what will be the day after 62 days?

Options:

A. Sunday

B. Monday

C. Wednesday

D. Tuesday

Solution

Each day to the week is repeated after 7 days.

Therefore, after 63 days, it will be Monday.

Which means that on 62nd day, it will be Sunday.

Question 3.

Which year will have the same calendar as that of the year 2019?

Options

A. 2029

B. 2030

C. 2031

D. 2024

Solution

Count the number of odd days from the year 2019 onwards to get the sum equal to 0 odd day.

Year20192020202120222023202420252026202720282029
Number of Odd days12111211121

Sum = 14 odd days = 0 odd days

Therefore, calendar of the year 2030 will have the same calendar as that of the year 2019.

How to Solve Clocks and Calendar Questions Quickly: Calendar Type

Question 1.

Calculate the angle between the two hands of a clock when the time shown by the clock is 5: 30 a.m?

Options

A. 100

B. 150

C. 200

D. None of the above

Solution

According to the formula

Angle = (11/2)M – 30H, where M =30, and h =5

=  (11/2) x 30 – 30 x 5

= |165 – 150|, taking the mode of the values, we get

= 15°

Question 2.

How many degrees will the minute hand move, in which the second hand moves 480 ?

Option

A. 4°

B. 8°

C. 10°

D. 12°

Solution

In 480 seconds the minute hand will cover = 480/60 = 8°

Therefore, minute hand moves for 8° when the second hand has moved 480 .

Question 3.

A clock is started in the afternoon. By 10 minutes past 5, the hour hand has turned through how many degrees?

Options

A. 134°

B. 148°

C. 135°

D. 155°

Solution

Angle traced by hour hand in 12 hrs = 360°.

Angle traced by hour hand in 5 hrs 10 min = 5*60 + 10 = 310 = 310/60 = 31/6 hrs

= 360/12 * 31/6

= 155°