Given: A = 58694 P = 50000 n = 2 years r=?
A = P (1 + r/100) n
58694 = 50000 (1 + r/100)²
58694/50000 = (1 + r/100)²
=1+ r/100 = root of 1.17=1.08
=r/100=1.08-1=0.08
r=0.08x100=8%

=9000(1+15/100)2⅓

=9000(1+3/20)²= (1+3/20x3)

=9000* 23  x23  x  23
20   20      20

=13687.875
∴ Compound Interest = Rs. (13687.875 – 9000) = Rs. 4687.875.

Given: P = Rs.8000, rate of interest = 8%, n = 4years

calculation: half-yearly, therefore, r=   8   %=4%

2

n=4x2=8 half years

A=8000( 1 + 4/100)⁸ =8000× (26/25)⁸

=8000x1.3685=10.948

Interest = Amount - Principal = `

10948 - 8000 = 2948

Let the sum be `100.

Therefore, SI=100×10×2/100 = `20

and CI=100 (1 + 10/100)² - 100 = 121 − 100 = 21

Difference of CI and SI = 21 − 20= 1

Now if the difference is 1 , then the total= 100

So if the difference is 20 then the total will be= 100× 20 = INR 2000

13560(1 + 7/100)³

Required population: 13560(1.07)³ = 16612

Measurement shows that 100 at 9% compounded semi-annually will grow to

A=100 (1 + .09/2)² = 100(1.045)²

=100(1.09)=109.20

So the actual rate=109.20 - 100=9.20. Thus if we get 9.20 % 100 in 1 year with yearly compounding, then the rate will be 9.20/100=0.092=9.20 so the actual rate = 9.20%

Given r=.049 and m= 12.

Value of `p after n years = p (1+ r/100) n

Effective rate is re = (1 + .049/12)₁₂ − 1

=1.050115575-1=.0501

or 5.01%

Down payment = INR 2000

So at the completion of 1^st-year x will become INR 1500.

So, 1500 = x (1 + 10/100) or

x = (1500×100/110) = 1363.63

Similarly, 1050 = y (1 + 10/100)² or y= (1050×20×20/22×22) = 420,000/484=867.76

and z = (930×20×20x20/22×22×22) = 698.72

Hence, CP = 2000+1363.63+867.76+698.72 = 4930.11 or 4930

As given, P+ Compound Interest of 3 years = 5500.......(i)
P+ Compound Interest of 2 yrs = 4645.......(ii)
By solving the equations we get Compound Interest of 3rd year = 5500-4645 = 855
Alternate method:
Difference of sum after n years and n + 1 years × 100 /Amount after n years
Here n=2
Rate =
= (5500−4645) × 100 = 855×100 = 18.40% or 18%.
4645 4645

After first year the amount =

28750 (1 + (4/100) = 28750 (104/100)

After 2 nd year the amount = 28750 (104/100) (108/100)

=28750 (26) (27) = (1.12x28750)=32292

25     25

CI = 32292-28,750 = 3542