Go through Calendar Questions Page to get all the sample Calendar Questions for Practicing for Competitive Exam. Here you will also get some Formula that’ ll make Calendar Questions Solving easy.
About Calender:Basically, there are 365 days in an ordinary year, which means 52*7+1 day or 52 weeks plus one day per year. This concept is applicable only for years excluding the leap year.
Formula or Rule for solving CALENDAR questions
100 years give us 5 odd days
200 years give us 5 x 2 = 10 – 7 (one week) = 3 odd days.
300 years have 5 x 3 = 15 – 14 (two weeks) =1 odd day.
400 years have [{5 x 4 + 1 (leap century)} – 21] (three weeks)= 0 odd days.
January has 31 – 28 = 3 odd days.
February has 28 – 28 = 0 odd day in a typical year and 1 odd day in a leap year and so on for all the other months.
Concept of Odd Days:Whenever we are asked to find out a day of the week on a specific date, we use the concept of 'odd days'. Odd days may be defined as the number of days more than whole weeks.
Leap Year:If it is not a century, then each year divided by four is a leap year. One point also to be noted here is that leap year comes in every 4’th century.
Points To Remember:
Leap year rule:
A year is a leap year if it is divisible by 4.
However, if a year is divisible by 100, it is not a leap year unless it is also divisible by 400.
For example, the year 2000 was a leap year because it is divisible by both 4 and 400.
Odd days:
The concept of odd days is used in the doomsday rule to find the day of the week for a given date within the same year.
In a normal (non-leap) year, there are 365 days, which is equivalent to 52 weeks and 1 day (1 odd day).
In a leap year, there are 366 days, which is equivalent to 52 weeks and 2 days (2 odd days).
Doomsday rule:
The doomsday rule is a mental calculation technique to find the day of the week for any date in a given year.
It is based on a set of anchor days for each century (e.g., 1800, 1900, 2000) and applying simple arithmetic to find the day of the week.
With practice, this rule can be used to quickly determine the day of the week for any date.
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