# Formulas For Speed Time And Distance

## Introduction and Concept of Speed, Time, and Distance

Speed, Distance and Time is one of the most popular and significant topics in any competitive exam’s  Quantitative portion.  The concepts of speed, time, and distance are frequently utilized in issues about motion in a straight line, circular motion, boats and streams, races, and clocks, among other things. Therefore, we will discuss about Formulas for Speed, Time and Distance on this page.

### Speed, Time, and Distance Relationship

• Speed = Distance/Time – This shows us how fast or slow an object moves.
• It is defined as the distance travelled divided by the time it took to travel that distance.
• Distance is directly proportional to speed, but time is inversely proportional
• Distance = Speed X Time, and
• .Time = Distance / Speed, -The time taken will reduce as the speed increases, and vice versa. Any simple problem can be solved using these formulas.
However, when utilizing formulas, it’s also crucial to remember to use the right units.

### Units of Speed Time & Distance

Each Speed, Distance and Time can be expressed in different units:

• Time: seconds(s), minutes (min), hours (hr)
• Distance: (meters (m), kilometers (km), miles, feet
• Speed: m/s, km/hr

So if Distance = km and Time = hr, then as Speed = Distance/ Time; the units of Speed will be km/ hr.

Now that we’ve established the units of Speed, Time, and Distance, let’s look at the formulas for them.

### Formulas of Speed, Time and Distance

Distance = Speed x Time

 Speed = Distance Time
 Time = Distance Speed

#### Formula for Conversion of Km/hr to m/sec where x is in Km/hr

1 km = 1000m

1 h = 3600 s

So 1km /h = $\frac{1000}{3600} \$

= $\frac{5}{18} \$

 Y m/sec = X x 5 m/sec 18

#### Formula for Conversion of m/sec to Km/hr where x is in m/sec

1 m =$\frac{1}{1000} \$ km;

1 sec = $\frac{1}{3600} \$ hr

1m/sec = $\frac{3600}{1000}$

= $\frac{18}{5}$

=> Y km/hr = (X x $\frac{18}{5}$) km/hr

### Equal Distance at two speeds

• An object covers equal distance  at speed S1 and other equal distance at speed S2 then his average speed for the distance is $\frac {2S1S2}{S1 + S2}$

### Formulas of Train for Speed, Time and Distance-

• S = Speed of Train
• S = Speed of Object
• L = Length of Train
• L = Length of Object

#### Case 1 –

When Train Crosses a Stationary Object with no Length(e.g. Pole) in time t

• ST = $\frac{L_T}{t} \$

#### Case 2 –

When Train Crosses a Stationary Object with Length L(e.g. Train Platform) in time t

• ST = (L+LO) / t

#### Case 3 –

When Train Crosses a Moving Object with no Length (e.g. Car has negligible length) in time t

• Objects moving in Opposite directions
• (S+ SO) = LT/ t
• Objects moving in Same directions
• (S– SO) = LT/ t

#### Case 4 –

When Train Crosses a Moving Object with Length LO (e.g. Another Train treated as an object) in time t

• Objects(Trains) moving in Opposite directions
• (S+ SO) = (L+LO)/ t
• Objects(Trains) moving in Same directions
• (S– SO) = (L+LO)/ t

Note – In Case for Train 2 is treated as an object

Read Also: Tips And Tricks to solve Speed, Time and Distance question

How to Solve Speed, Distance and Time Quickly

Questions on Speed , Distance and Time