Formulas For Speed Time And Distance

Formula

Formulas of Speed, Time and Distance:-

Speed measures of how quickly an object moves from one place to another. Speed is equal to the distance traveled divided by the time taken.

By using speed, time and distance formulas we can easily find the three values

Formulas of Speed, Time and Distance

Distance = Speed x Time

Speed =Distance
Time
Time =Distance
Speed

speed time and distance formulas

Formula for Conversion of Km/hr to m/sec where x is in Km/hr

1 km = 1000m

1 h = 3600 s

So 1km /h =  \frac{1000}{3600} \

=  \frac{5}{18} \

m/sec =X x5m/sec
18

Formula for Conversion of m/sec to Km/hr where x is in m/sec

1 m = \frac{1}{1000} \ km;

1 sec = \frac{1}{3600} \ hr

1m/sec = \frac{3600}{1000} \

= \frac{18}{5} \

km/hr =X x18km/hr
5

Equal Distance at two speeds

An object covers equal distance  at speed S1 and other equal distance at speed S2 then his average speed for the distance is (2S1S2)/(S1 + S2)

Formula for speed, time and distance

Train based Formulas of Speed, Time and Distance-

  • S = Speed of Train
  • S = Speed of Object
  • L = Length of Train
  • L = Length of Object
Formula PrepInsta

Case 1 –

When Train Crosses a Stationary Object with no Length(e.g. Pole) in time t

  • ST =  \frac{L_T}{t} \
Formula PrepInsta

Case 2 –

When Train Crosses a Stationary Object with Length L(e.g. Train Platform) in time t

  • ST = (L+LO) / t
Formula PrepInsta

Case 3 –

When Train Crosses a Moving Object with no Length (e.g. Car has negligible length) in time t

  • Objects moving in Opposite directions
    • (S+ SO) = LT/ t
  • Objects moving in Same directions
    • (S– SO) = LT/ t
Formula PrepInsta

Case 3 –

When Train Crosses a Moving Object with no Length (e.g. Car has negligible length) in time t

  • Objects moving in Opposite directions
    • (S+ SO) = LT/ t
  • Objects moving in Same directions
    • (S– SO) = LT/ t
Formula PrepInsta

Case 4 –

When Train Crosses a Moving Object with Length LO (e.g. Another Train treated as an object) in time t

  • Objects(Trains) moving in Opposite directions
    • (S+ SO) = (L+LO)/ t
  • Objects(Trains) moving in Same directions
    • (S– SO) = (L+LO)/ t

Note – In Case for Train 2 is treated as an object

Read Also: Tips And Tricks to solve Speed, Time and Distance question

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