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# Clock Formulas

**Formula and Basic Concepts of Clock**

On this page you will find some of the basic Clock Formulas that will help you to solve Clock Based Question Easily.

**Clocks Formulas & Properties**

- The dial of the clock is circular in shape and is divided into 60 equal minute spaces.
- 60-minute spaces traces an angle of 360
^{0}. Therefore, one minute space traverses an angle of 6^{0}. - The hands of a clock are perpendicular when they are 15-minute space apart.
- Hands of a clock are in straight line and are opposite to one another when they are 30 minutes space apart.
- Hands of a clock are perpendicular to each other 22 times in 12 hours and 44 times in 24 hours.
- Hands of the clock are opposite to each other for 11 times in 12 hours and 22 times in a day.
- The minute hand gains 55 minutes over hour hand every hour.

**A) Angle between hands of a clock**

1. When minute hand is behind the hour hand, the angle between the two hands at M minutes past H o’clock.

= 30 [H -(M/5)] + M/2 degree

= 30H – (5.5 x M)

2. In the case where the minute hand is ahead of the hour hand, the angle between the two hands at M minutes past H ‘o clock will be calculated as

= 30 (M/5-H ) -M/2 degree

= 5.5 x M – 30H

** B) To calculate x minute space gain by the minute hand over the hour hand,**

= x\frac{60}{55}

= x\frac{12}{11}

**C) Both the two hands of the clock will be at the right angles between H and (H+1) o’clock at ****(5H ± 15) minutes H<’o clock.**

**D) If the minute hand of a clock overtakes the hour hand at the interval of M minutes when the time is correct, the clock gains or loses a day by**

=\frac{720}{11} – M [(60×24)/M] minutes

**E) Between H and H+1 o’clock, the two hands of the clock are M minutes apart at ****(5H ± M)12/11 minutes past H o’ clock.**

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**Sample Clock Questions With Solution**

**Question 1: What is the angle between the hands at 6: 30?**

**Solution:**

Angle = |(30 x Hour – 5.5 x Minutes)|

where Hour is the hour hand position and Minutes is the minute hand position.

At 6:30:

Hour = 6

Minutes = 30

Angle = |(30 x 6 – 5.5 x 30)| = |(180 – 165)| = |15| = 15 degrees

So, the angle between the hour and minute hands at 6:30 is 15 degrees.

**Question 2: What is the angle between the hands at 2: 45?**

**Solution: **

Angle = |(30 x Hour – 5.5 x Minutes)|

Where:

Hour = 2 (the given hour)

Minutes = 45 (the given minutes)

Let’s calculate the angle:

Angle = |(30 x 2 – 5.5 x 45)| = |(60 – 247.5)| = |(-187.5)| = 187.5 degrees

So, the angle between the hour and minute hands at 2:45 is 187.5 degrees.

**Question 3: If the minute hand of a clock is at 3 and the hour hand is at 2, what is the angle between the hands?**

**Solution: **

To find the angle between the hands, use the formula: Angle = |(30 x Hour – 5.5 x Minutes)|

Angle = |(30 x 2 – 5.5 x 3)| = |(60 – 16.5)| = 43.5 degrees

So, the angle between the hour and minute hands is 43.5 degrees.

**Question 4: At what time between 4 o’clock and 5 o’clock will the hour and minute hands be exactly 120 degrees apart?**

**Solution:**

For hour and minute hands 120 degrees apart, we can use the formula:

Angle = |(30 x Hour – 5.5 x Minutes)|

Let’s check all the times between 4 o’clock and 5 o’clock and check the angle:

4:00 = Angle = |(30 x 4 – 5.5 x 0)| = |(120 – 0)| = 120 degrees (Exactly 120 degrees)

Therefore, the hour and minute hands will be exactly 120 degrees apart at 4:00.

**Question 5: How many times do the hour and minute hands of a clock overlap in a 24-hour period?**

**Solution:**

The hour hand overlaps the minute hand 11 times in every 12-hour cycle.

In a 24-hour period, there are two 12-hour cycles.

So, the total number of overlaps in 24 hours = 11 + 11 = 22 times.

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