Speed Time and Distance Questions and Answers

Relative speed of cop with respect to robbers = (11 - 10) = 1 Km/hr.

Now the relative distance covered by cop in 6 min

= Speed x Time = 1 x 6/60

=1/10km = 100m

The distance between the Cop and Robbers after 6 min = 200 - 100 = 100 m.

Assume the time in which he travelled on foot = x hour
Time required to travel on cycle = (9 - x) hr

the total distance = 66 km
Hence,
4x + 9(9-x) = 66
=> 5x = 15
=> x = 3

so distance travelled on foot = 4(3) = 12 km. Option 3 is the correct answer.

The Airbus A350 flying north would have travelled for 2 hours at 2 PM.

It travels at 500 kmph.

Hence, the Airbus flying north would have covered 1000 kms from the city at 2 PM.

The Spice jet flying east would have travelled for 1.5 hours at 2 PM.

It travels at 400 kmph.

Hence, the Spice jet flying east would have covered 1.5*400 = 600 kms from the city at 2 PM.

Both the Airbus and Spice jet are flying at right angles to each other.

The shortest distance between the two planes is the length of the hypotenuse of the right triangle whose legs are the distances covered by both of them.

Hence, distance =   = 1166 km

When going downstream, the speed of the boat and the flow of the river are added to calculate the net speed.
When going upstream, we take the difference between the speed of the boat and the flow of the river as the net speed.
Time = Distance / Speed

Calculation:
Let the flow of the river be R kmph.
According to the question,
{150 / (20 + R)} + {150 / (20 - R)} = 16

On solving, R = 5.

Since the distance covered is same,
Average speed = 2*a*b/ (a+b), where a & b are respective speeds of to and fro journey.
Avg speed = 2*3.5*7.5/ (3.5+7.5) = 4.77 km/hr (approx.)
The total time = 6 hrs 37 minutes.
Rest = 45 minutes
Hence, travel time = 6 hrs 37 minutes - 45 minutes = 5 hrs 52 minutes =5\frac{52}{60} = 5\frac{13}{15}
D = S * T = 4.77 *5\frac{13}{15}
= 4.77 *\frac{88}{15}  = 28 Km
This is the total distance, that is, to and fro.
Hence distance to town = 28/2 = 14 Km.
Option 1 is the correct answer.

In one hour without stopping, the bus would have travelled 54km. Once stopping is factored in, the bus actually travels 45km. So it travels 9km less far as a consequence.
Distance/Speed = Time
9km/54kmph = 0.16 hours
0.16 * 60 = 10 minutes
So the bus stops for ten minutes in every hour on average.
Option 3 is the correct answer.

Let ‘s’ km/h be the speed of Jack’s yacht.
Then, 1(s+4) = 2(s-4) → s=12 km/h
So option 2 is the correct answer.

To arrive at the business meeting exactly on time, John should have driven at a speed of 2m / (2h - 1) miles per hour. This formula takes into account the distance he needs to cover (m miles) and the adjusted time he should have taken to arrive on time (2h - 1 hours).
So option 3 is the correct answer.

Distance between Mewar to chittorgarh = 80 km

Speed of Romita = Speed of supriya - 6

Ratio of distance = 80 : 80+20

= 80 : 100 = 4 : 5

Difference  = 1

So, 1 unit = 6

Value of 4 unit(distance covered by Romita) = 24 km/hr

Speed of Romita = 24 km/hr

Length of the platform = speed of train * extra time taken to cross the platform.
So length of platform = 72 kmph * 30 seconds
Convert 72 kmph into m/sec
1 kmph = 5/18 m/s
Therefore 72 kmph = 5/18∗72 = 20 m/sec
Hence the length of the platform = 20 m/s * 30 sec = 600 meters.

Option 1 is the correct answer.

Aria runs 25 percent faster than Briana.
If Briana runs 100 m in a time interval given, Aria will run 125 m in the same time.

Assuming.

If Aria runs 5 m in a given time, then Briana will run 4 m in the same time.

If the length of a race is 5 m, then Aria can give Briana a start of 1 m (Aria can allow Briana to start 1 ahead of the start point) so they end the race.
The ratio of length of start given: length of race: 1: 5

As given in the question,
The start given in the question is 7 m.
Finally, length of the race will be 7 * 5 = 35 m.

Assume that Kane travel in x hours at 60 km per hour.
As the total time taken to cover 340 miles is 5 hours, Kane would have travelled (5 - x) hours at 80 km per hour.
Distance covered at 60 km per hour = Speed * time = 60 * x = 60x km.
Distance covered at 80 km per hour = Speed * time = 80 (5 - x) = 400 - 80x km.
Total distance covered = Distance covered at 60 km per hour + Distance covered at 80 km per hour.
So, the total distance = 60x + 400 - 80x.
Total distance travelled = 340 km
340 = 60x + 400 - 80x
20x = 60 or x = 3 hours.
Option 2 is the correct answer.

6.64 km = 6640 m
He hears the sound 20 seconds late.
We know, Speed = Distance/Time
Therefore the speed of the sound = 6640/20 = 332 m/s.

Option 3 is the correct answer.

Let the speeds of the two buses be 11x and 9x respectively.
Speed of the second bus = 270/15 = 18 km/hr (∵ Speed = Distance/Time)
⇒ 9x = 18
⇒ x = 18/9 = 2
Speed of the first bus = 11x = 11 × 2 = 22 km/hr
Therefore the speed of the first bus = 22 km/hr
Option 4 is the correct answer.

There are 24 lamp posts and the gap between two is 50 meters
Total distance = 23 × 50 = 1150 m
Time = 1 min= 60 sec
Now, speed = Distance/Time
⇒ Speed = 1150/60 = 19.16 m/s
⇒ Speed = (19.16 × 3600)/1000 = 69 km/hr
Option 3 is the correct answer

We know that speed is defined as:
Speed=distance travelled/time required to travel the distance
For the bus, it covers a distance of 660 meters in 1 minute (or 60 seconds).
From the above formula,
Speed of bus (SB) =660 meters /second
Or, speed of bus SB = 11 meters/second
Similarly, for the car, it covers a distance of 44 km (or 44 × 1000 meter) in 50 minutes (or 50 × 60 seconds).
From the above formula,
car speed (CS) =44000 meters / (50×60) second
Or, speed of car SC = 44/3 meters/second
Bus speed (BS)/ car speed (CS) =11/44/3=3/4
Or, Speed of bus: speed of car = 3: 4

Option 1 is the correct answer.

Assuming that the constant speed be x km/hr.
715/x-715/(x+10) =2⇒1/x-1/(x+10) =2/715
⇒(x+10)-x/x(x+10) =2/715⇒x(x+10) =3575
⇒x^{2}+10x-3575=0⇒x^{2}+65x-55x-3575=0
⇒x(x+65)-55(x+65) =0
⇒(x+65) (x-55) =0
⇒x=55.
∴Original speed of the car is 55km/hr.

Option 4 is the correct answer.

required distance = sum of distance covered by A and B
= {(80*12/60) + (65*12/60)} = (16+13) = 29 km

Option 2 is the correct answer.

Ratio of time taken by Arash and Bunty = 1/2: 1/3
Suppose Bunty takes x min. Then, Arash takes (x+10) min.
∴(x+10): x= 1/2: 1/3 = 3:2 ⇒ x+10/x = 3/2 ⇒ 2x+20 = 3x ⇒x = 20
Thus Bunty takes 20 min. and Arash takes 30 min.
AT double speed A would covers it in 15 min.

Option 3 is the correct answer.

Raghuveer’s speed = 6 km/hr = 6x 5/18 m/sec = 5/3 m/sec

Length of the bridge = (5/3) x18x60 = 1800 m

Option 1 is the correct answer.

Distance covered in 2 hours = 100 x 2 = 200 km

To cover the remaining distance the time will be taken = (680 - 200)/60 = 480/60 hrs = 8 hrs

The Total time = 2 + 8 = 10 hrs

Sarita will reach Jamnagar at 4:00 P.M.

Speed of Saroj w.r.t Arita = 6 - 1 = 5 rounds per hour
At this speed the time taken to complete 1 round = 1/5 = 12 min i.e. 7:30am plus 12 minutes is equal to 7:42am.

Option 4 is the correct answer.

Let x km be the distance travelled on roadways bus
The total distance covered by cng rickshaw = (80 - x) km
So, x/6 + (80 - x)/12 = 12
12x + 6(80 - x) = 12
x = 64 km

Option 3 is the correct answer

Original speed is 40km per hour
If the speed is increased by 50%, then the new speed is = 150 % of 40= 60km per hour
It is given that the distance to be covered is 330 kms.
The total time taken to cover 330 kilometres distance at 60 km per hour is
330 / 60 = 5.5 hours = 5 hrs 30 minutes
Hence, if the person is increased by 50%, it will take 5 hrs 30 minutes to cover 330 km distance.

Option 1 is the correct answer.

The total distance covered= (600 + 800 + 500 + 100) km = 2000 km
the total time =

\frac{600}{80} +\frac{800}{40} + \frac{500}{400} + \frac{100}{50} = \frac{123}{4}

So, the average speed = \frac{2000*4}{123}

Option 1 is the correct answer.

modifying speed of the electric bike = 60 km/h

Distance it covers in 6h. = (60 * 6) km = 360km

The time taken to cover 360 km when it is not modified = (360 / 50) = 7.2h

Option 3 is the correct answer.

In 12 hours the distance travelled = (45 + 47 + 49 + ..... up to 12 terms.)
It is an AP which has its first term as a = 45, number of terms, n = 12, common difference, d = 2.
Distance that is required =

12/2 [2*45 + (12-1)*2] = 6 (90 + 22) = 672 km.

Option 4 is the correct answer.

Let x be the distance to be covered by the boat when it goes against the stream.

Motor boat goes down the river at a speed of 65 + 5 = 70 km/h and up the river at a speed of 65 - 5 = 60km/h.

Time taken to meet = (Distance) / (speed) = 81/ (3 + 6) = 9 hours

So, Hirendra’s wife has travelled = 9 x 3 = 27km.