Let us assume Max’s current age as a.

Then, his mother's current age will be = (a + 3a) = 4a.

(6+4a) = 52 (a+6)

= 8a + 12 = 5a + 30

= 3a = 18

a = 6

Therefore, Max’s mother would be (4a + 12)/(a+12) = 36/18 = 2 times.

Hence Option D is the correct one.

If the youngest child’s age is assumed as a.

Then, ages of all the four children can be defined as a , (a+2), (a+4), (a+6)

Given, a + (a+2) + (a+4) + (a+6) = 40

4a = 40 – 6 – 4 – 2

4a = 28

a = 7

Hence the youngest kid is 7 and the eldest one is 7 + 6 = 13years

Hence Option B is the correct one.

If the youngest child’s age is assumed as p.

Then, six children will be, p, (p+1.5), (p+3), (p+4.5), (p+6), (p+7.5)

Given in the question, p + (p+1.5) + (p+3) + (p+4.5) + (p+6) + (p+7.5) = 60

6p = 60 – (7.5+6+4.5+3+1.5)

6p =60 – 22.5

p = 6.25

Therefore, the youngest child is 6.25 years.

Hence option D is the correct one.

Let’s assume Sam’s current age as s.

Then, Ross’s will be = (s + 2s)

= 3s.

After 12 years their age will be,

= 32 (12+s )= (3s+12)

= 6s – 3s = 36 - 24

Or s= 4

Further after 12 years Ross’s age will be, 3*4 +24 = 36

Sam’s age will be 4+24 = 28

Therefore, the ratio required is 36/24 = 3/2 = one and a half.

Hence option A is the correct one.

Let Monika’s present age be a.

Then, Samantha’s age at the time Monika was born= (36-a) = a

2a = 36

a= 18.

Therefore, if the daughter is 18 years old at present then her age 4 years back will be,

18 - 4 = 14 years

Therefore option A is the correct one.

Present age of Amma= 15 (given)

Father’s age at the time of Amma’s birth= Twice her present age.

Therefore, her father’s age at present will be (15*2) + 15 = 45

Hence, the father’s age after five years will be, 45+5 = 50.

Therefore option D is the correct one.

Given, 5 years before Father’s age= Twice Jack’s age.

Let Jack’s age be a so father’s age= 2a.

Now Father’s present age= 2a + 5

Jack’s present age= a+5

After seven years: Father will be (2a + 5) + 7 and jack will be (a + 5) + 7.

Now as per the questions, father’s age would be thrice that of his son, 7 years hence.

(2a + 5) +7 = 3 [(a + 5) + 7]

(2a + 12) = 3[a + 12]

On Solving, we get,

a = 24

(2a + 5): (a + 5) = 53: 29

The answer is 29:53

Hence Option A is the correct one.

Let us assume Luke’s age a.

Then, Ross's age will be = (a - 8)

(a - 8)/a = 4/6

2a = 48

a = 24

Hence, Ross's age = (x - 8) = 16 years.

Hence Option D is the correct one.

The ratio of their present age is 5:3.

So, their present age can be 5x and 3x

Ashley’s age 3 years ago was 5x – 3

Dennis’s age 3 years hence will be 3x + 3

The ratio of Ashley’s age 3 years before and Dennis’s age 3 years hence is 1: 1

(5x - 3) / (3x + 3) = 1/1

2x = 6

x = 3

Now, we have to find the ratio among Ashley’s age 3 years later and Dennis’s age 3 years before.

Ashley’s age: (5x + 3)

Dennis’s age: (3x – 3)

On applying x’s value, we get:

(5x + 3) / (3x - 3) = 3:1

Therefore option A is the correct one.

Let Saif’s age be a, hence his mother’s age= 5a

Given, 3 years hence mother’s age= 4 times of Saif’s.

= (5a+3) = 4(a+3)

= 5a+3 = 4a+3

a = 6

If Saif’s age is 6, then mother’s age= 6*5 = 30 years

Further after 3 years mother’s age will become 30+3 = 33

Therefore Option D is the correct one.

Rachel age - x

Alex age - x + 10.

4 yrs prior , rachel - x - 4.

Alex - x + 10 - 4 = x + 6.

Acc to question, x + 6 = 3(x - 4)

2x = 18 , x = 9.

so rachel age = x = 9 years.

Alex age = x + 10 = 19 years.

Question is asked about alex age after one year , 19 + 1 = 20years ( ans).