# How to Solve Quickly Speed Time And Distance Questions

## How to solve Speed Time and Distance Question Quickly

Speed can be defined as how quickly an object moves from one place to another.

Formula for speed = $\frac{distance}{time} \$

Or it can be written as, speed = $\frac{d}{t} \$ ### How to Solve Speed Time And Distance:-

• Speed Time and Distance is a part of our study since school time but still, students get confused while solving the questions.
• This page will provide you the easiest way to solve the questions quickly along with the help of some Solved Examples.
• Before solving the question, we have to know about the exact definitions of Speed Time and Distance.

### Definition:

• Speed:

Speed can be defined as how quickly an object moves from one place to another.

Formula for speed = $\frac{distance}{time} \$

Or it can be written as, speed = $\frac{d}{t} \$

• Time:

Time is defined as distance divided by speed.

Formula for time = $\frac{distance}{time} \$

Or it can be written as, $\frac{d}{s} \$

• Distance:

Area covered by an object from moving one place to another in a uniform speed and time is known as Distance.

Formula for distance = speed x time

Or it can be written as , s × t

### How to Solve Quickly Speed, Time and Distance Problems

Question 1 A dog runs from one side of a road to the other. The road is 80.0 meters across. The dog takes 16.0 seconds to cross the road. What is the speed of the dog?

Options:

A. 2.0 meters

B. 3.5 meters

C. 5.1 meters

D. 5.0 meters

Solution:    S = $\frac{d}{t} \$

S = $\frac{80.0}{16.0} \$

⇒ 5.0 meters

Question 2 An Old man and a Young man are working together in an office and staying together in a nearby apartment. The Old Man takes 30 minutes and the Young 20 minutes to walk from apartment to office. If one day the old man started at 10:00 AM and the young man at 10:05 AM from the apartment to office, when will they meet?

Options:

A. 10: 40 AM

B. 10: 15 AM

C. 10:00 AM

D. 10:05 am

Solution:    Ratio of old man speed to young man speed = 2:3

The distance covered by the old man in 5 min = 10

The 10 unit is covered with relative speed=$\frac{10}{(3-2)} \$=10 min

so, they will meet at 10:15 am.

ions ### How to Solve Quickly Speed, Time and Distance

Question 3 A motor/boat covers a certain distance downstream in 30 minutes, while it comes back in 45 minutes. If the speed of the stream is 5 km/h what is the speed of the boat in still water?

Options:

A. 10 kmph

B. 5 kmph

C. 20 kmph

D. 25 kmph

Solution:    Speed of boat = b km/hr

Speed of stream = s km/hr

Upstream speed = b-s km/hr

Downstream speed = b+s km/hr

Let x km be the distance

Therefore, downstream = $\frac{x * 30}{60}$ km/hr = 2x km/hr

upstream = $\frac{x * 45}{60}$ km/hr =$\frac{3x}{4} \$ km/hr

Given speed of stream s = 5km/hr

Question 4 Walking$\frac{6}{7th} \$ of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover the distance?

Options:

A. 2 hrs

B. 1 hr 30 min

C. 1 hr 12 min

D. 39 min

Solution:    New speed of man = $\frac{6}{7} \$of usual speed

As we know speed & time are inversely proportional

Hence, new time= $\frac{7}{6} \$of usual time

Hence $\frac{7}{6} \$ of usual time- usual time= 12 minutes
$\frac{1}{6} \$ of usual time= 12 minutes

Therefore, usual time = 12×6 = 72 minutes

It means 1 hr 12 minutes

Question 5 A kid takes 6 hours for walking to a certain place and riding back. He would have taken 2 hours less by riding both ways. What will be the time required by him to walk both ways?

Options:

A. 6 hrs

B. 1 hr

C. 3 hrs

D. 8 hrs

Solution:    Time taken by the kid in walking to a certain place & riding back is 6 hrs

Time walk+ Time ride = 6

2 hrs of the time is reduced if he rides both the ways.

Time ride+ Time ride = 4

2× ride= 4

ride = $\frac{4}{2} \$

ride= 2

Now by putting the value of ride, we get

time walk + 2= 6

timewalk = 6-2 =4

Here we are finding the time taken by the kid if he walk both the ways

4+4=8

Therefore, he will take 8 hrs to walk both the ways.