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# How to Solve Speed Distance and Time Questions Quickly

**Solve Speed, Distance and Time Question Quickly**

Speed Distance and Time is a part of our study since beginning but students generally fail to focus on this topic . This page will provide you with the most simple approach to Solve Speed Distance and Time questions quickly along with the help of some Examples

**How to Solve Speed Distance and Time Questions Quickly:-**

Before solving the question, we need to know about the Formulas of Speed Time and Distance.

## Basic Formulas

- Distance (D1) = Speed × Time
- Time = Distance/Speed
- Speed = Distance / Time
- To Convert Km/h to M/s =Km/h * 5/18 = Values in m/s or m/sec *18/5 = Values in km/h
- Calculate Average Speed = 2ab/a + b
- X and Y may walk in same direction or in opposite direction.

**How to Solve Problems Quickly **

**Question 1 : Yamini runs from one side of a road to the other to save herself from a dog who was chasing her . The road was 100meters across. In order to save herself from the dog Yamini takes 25 seconds to cross the road. What is the speed of Yamini ?**

**Options:**

**A. 2 meters/second**

**B. 3.5 meters/second**

**C. 5.1 meters/second**

**D. 4 meters/second**

**Solution: **S = \frac{d}{t} \

S = \frac{100.0}{25.0} \

⇒ 4 meters/second

**Correct Answer: D**

**Question 2 : Two person X and a Y are working together in for a task and stay together in a nearby apartment. X takes 30 minutes and Y takes 20 minutes to walk from apartment to office. If one day X started at 10:00 AM and the Y at 10:05 AM from the apartment to office, when will they meet?**

**Options:**

**A. 10: 40 AM**

**B. 10: 15 AM**

**C. 10:00 AM**

**D. 10:05 am**

**Solution: **Ratio of old man speed to young man speed = 3:2

The distance covered by the old man in 5 min = 10units

The 10 unit is covered with relative speed= \frac{10}{(3-2)} \ =10 min

so, they will meet at 10:15 am.

**Correct Answer: B**

**Question 3 : A freight train takes 5 hours to travel a certain distance. If it reduces its speed by 10 km/h, it would take 6 hours to cover the same distance. Find the original speed of the freight train and the distance it traveled.**

** Options**

** A. 12Km/h, 60 km**

** B. 23 Km/h, 1 km**

** C.45Km/h, 30 km**

** D.18km/h, 1 km**

**Solution: **Let the original speed of the freight train be S km/h, and let the distance it traveled

be D kilometers.

According to the problem, time taken to travel the distance at the original speed is 5 hours, and time taken to travel the same distance at a reduced speed (S – 10) km/h is 6 hours.

We can set up the equations: D / S = 5 D / (S – 10) = 6

Now, we can solve for S and D. From the first equation, we get: S = D / 5 Substitute the value of S into the second equation: D / (D / 5 – 10) = 6 D / (D – 50) = 6 D = 6D – 300 5D = 300 D = 60 km

Now, substitute the value of D back into the first equation to find S: S = D / 5 S = 60 km / 5 S = 12 km/h

Therefore, the original speed of the freight train is 12 km/h, and it traveled a distance of 60 kilometers.

Correct Answer: A

**Question 4 Walking \frac{6}{7^{th}} \ of his usual speed, a man is 12 minutes late. What is the usual time taken by him to cover the distance? **

**Options:**

**A. 2 hrs**

**B. 1 hr 30 min**

**C. 1 hr 12 min**

**D. 39 min**

**Solution: **New speed of man = \frac{6}{7} \ of usual speed

As we know speed & time are inversely proportional

Hence, new time= \frac{7}{6} \ of usual time

Hence \frac{7}{6} \ of usual time- usual time= 12 minutes

⇒ \frac{1}{6} \ of usual time= 12 minutes

Therefore, usual time = 12×6 = 72 minutes

It means 1 hr 12 minutes

**Correct Answer: C**

**Question 5: Walking barefoot shanti takes 6 hours for walking to a certain place and coming back. She would have taken 2 hours less by riding both ways. What will be the time required by her to walk both ways? **

**Options:**

**A. 6 hrs**

**B. 1 hr**

**C. 3 hrs**

**D. 8 hrs**

**Solution: **Time taken by the kid in walking to a certain place & riding back is 6 hrs

Time walk+ Time ride = 6

2 hrs of the time is reduced if he rides both the ways.

Time ride+ Time ride = 4

2× ride= 4

ride = \frac{4}{2} \

ride= 2

Now by putting the value of ride, we get

time walk + 2= 6

timewalk = 6-2 =4

Here we are finding the time taken by the kid if he walk both the ways

4+4=8

Therefore, he will take 8 hrs to walk both the ways.

**Correct Answer: D **

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