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# How to Solve Quickly Speed Time And Distance Questions

## How to solve Speed Time and Distance Question Quickly

**Speed can be defined as how quickly an object moves from one place to another. **

**Formula for speed = \frac{distance}{time} \ **

**Or it can be written as, speed = \frac{d}{t} \ **

**How to Solve Speed Time And Distance:-**

- Speed Time and Distance is a part of our study since school time but still, students get confused while solving the questions.
- This page will provide you the easiest way to solve the questions quickly along with the help of some Solved Examples.
- Before solving the question, we have to know about the exact definitions of Speed Time and Distance.

**Definition:**

**Speed:**

Speed can be defined as how quickly an object moves from one place to another.

Formula for speed = \frac{distance}{time} \

Or it can be written as, speed = \frac{d}{t} \

**Time:**

Time is defined as distance divided by speed.

Formula for time = \frac{distance}{time} \

Or it can be written as, \frac{d}{s} \

**Distance:**

Area covered by an object from moving one place to another in a uniform speed and time is known as Distance.

Formula for distance = speed x time

Or it can be written as , s × t

**How to Solve Quickly Speed, Time and Distance Problems**

**Question 1 A dog runs from one side of a road to the other. The road is 80.0 meters across. The dog takes 16.0 seconds to cross the road. What is the speed of the dog?**

**Options:**

**A. 2.0 meters**

**B. 3.5 meters**

**C. 5.1 meters**

**D. 5.0 meters**

**Solution: **S = \frac{d}{t} \

S = \frac{80.0}{16.0} \

⇒ 5.0 meters

**Correct Answer: D**

**Question 2 An Old man and a Young man are working together in an office and staying together in a nearby apartment. The Old Man takes 30 minutes and the Young 20 minutes to walk from apartment to office. If one day the old man started at 10:00 AM and the young man at 10:05 AM from the apartment to office, when will they meet?**

**Options:**

**A. 10: 40 AM**

**B. 10: 15 AM**

**C. 10:00 AM**

**D. 10:05 am**

**Solution: **Ratio of old man speed to young man speed = 2:3

The distance covered by the old man in 5 min = 10

The 10 unit is covered with relative speed= \frac{10}{(3-2)} \ =10 min

so, they will meet at 10:15 am.

**Correct Answer: B**

**How to Solve Quickly Speed, Time and Distance**

**Question 3 A motor/boat covers a certain distance downstream in 30 minutes, while it comes back in 45 minutes. If the speed of the stream is 5 km/h what is the speed of the boat in still water?**

**Options:**

**A. 10 kmph**

**B. 5 kmph**

**C. 20 kmph**

**D. 25 kmph**

**Solution: **Speed of boat = b km/hr

Speed of stream = s km/hr

Upstream speed = b-s km/hr

Downstream speed = b+s km/hr

Let x km be the distance

Therefore, downstream = \frac{x * 30}{60} km/hr = 2x km/hr

upstream = \frac{x * 45}{60} km/hr = \frac{3x}{4} \ km/hr

Given speed of stream s = 5km/hr

**Correct Answer: B**

**Question 4 Walking \frac{6}{7<sup>th</sup>} \ of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover the distance? **

**Options:**

**A. 2 hrs**

**B. 1 hr 30 min**

**C. 1 hr 12 min**

**D. 39 min**

**Solution: **New speed of man = \frac{6}{7} \ of usual speed

As we know speed & time are inversely proportional

Hence, new time= \frac{7}{6} \ of usual time

Hence \frac{7}{6} \ of usual time- usual time= 12 minutes

⇒ \frac{1}{6} \ of usual time= 12 minutes

Therefore, usual time = 12×6 = 72 minutes

It means 1 hr 12 minutes

**Correct Answer: C**

**Question 5 A kid takes 6 hours for walking to a certain place and riding back. He would have taken 2 hours less by riding both ways. What will be the time required by him to walk both ways? **

**Options:**

**A. 6 hrs**

**B. 1 hr**

**C. 3 hrs**

**D. 8 hrs**

**Solution: **Time taken by the kid in walking to a certain place & riding back is 6 hrs

Time walk+ Time ride = 6

2 hrs of the time is reduced if he rides both the ways.

Time ride+ Time ride = 4

2× ride= 4

ride = \frac{4}{2} \

ride= 2

Now by putting the value of ride, we get

time walk + 2= 6

timewalk = 6-2 =4

Here we are finding the time taken by the kid if he walk both the ways

4+4=8

Therefore, he will take 8 hrs to walk both the ways.

**Correct Answer: D**

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