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Tips,Tricks and Shortcuts on Calendar.
The word calendar comes from ‘calendae’ , the word used for the first day of the month in the Roman calendar, related to the verb calare means “to call out” , referring to the “calling” of the new moon when it was first seen.


Best Tips , Tricks and Shortcuts on Calendar in Aptitude.
- The calendar starts on 1st January and ends on 31st December. The year is classified into two types:
- ordinary years (365 days)
- Leap year (366 days).
- In an ordinary year, there are 365 days, which means 52 x 7 + 1, or 52 weeks and one day.
- Here, are easy tricks and tips on Calendar problems Learn tricks on calendar.
- There are 3 types of questions asked in exams
Type 1: AP questions
Question 1.
Find 10th term in the series 2, 5, 8, 11, 14……
Options:
- 26
- 29
- 32
- 27
Solution:
We know that,
tn = a + (n – 1)d
In the given series,
a = 2
d = 3 …. (5 – 2, 8 – 5…..)
Therefore, 10th term = t10 = a + (n-1) d
t10 = 2 + (10 – 1) 3
t10 = 2 + 9 x 3
t10 = 29
Correct option: 2
Question 2.
The sum of 3 numbers in arithmetic progression is 36 and product of their extreme is 80. Find the numbers.
Options:
- 20 , 8 , 16
- 4 , 12, 20
- 12 , 20 , 28
- None of these
Solution:
We know that,
tn = a + (n – 1)d
Assume the numbers as:
a-d, a, a+d
or a-d+a+a+d=36
or 3a=36
a=12
now (a-d) (a+d)=80
a²-d²=80
144-d²=80
d²=64
d=8
thus the numbers will be: 4, 12 and 20
Correct option: 2
Type 1: Calendar Tips and Tricks- To find the day of given date
Question 1. What was the day on 27th May 2006?
Options:
A. Monday
B. Saturday
C. Sunday
D. Friday
Solution: 27th May, 2006 = (2005 years + Period from 1.1.2006 to 27.5.2006)
To calculate number of odd days till 2000, we need
Number of odd days in 1600 years = 0
Number of odd days in 400 years = 0
Now, for calculating odd days in the next five years,
5 years = (4 ordinary years +1 leap year) = (4+2)
= 6 odd days
Now to calculate number of odd days from 1st January 2006 to 27th May 2006
January (31 days) + February (28 days because 2006 is an ordinary year) + March (31 days) + (April 30 days) + May 27 days = 147 days
Total number of odd days in 147 days = ((147/7) = 21 weeks+ 0 odd days
Total number of odd days in the entire period = 0 (1600 years) + 0 (400 years) + 6 (5 years) + 0 (Period from 1.1.2006 to 27.5.2006) = 6 odd days
As per the table, on 27th May 2006 the day was Saturday.
Days | Sunday | Monday | Tuesday | Wednesday | Thursday | Friday | Saturday |
Number of odd days | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
Correct option: B
Type 2: To find the day of the week for the given date when some other date or day is specified.
Question 1. It was a Saturday on 8th December 2007. What was the day on 8th Dec 2006?
Options:
A. Tuesday
B. Friday
C. Sunday
D. Saturday
Solution: 2006 was an ordinary year.
Therefore the number of odd days in 2006 was = 1
Now, 8th Dec 2007 will be 1 day beyond the day on 8th December 2006 due to one odd day.
Since 8th December 2007 was Saturday, therefore, 8th December 2006 was Friday.
Correct option: B
Type 3: Shortcuts Tips and Tricks of Calendar To -Identify the year having same calendar.
Question 1. Which year will have the same calendar as that of the year 2007?
Options:
A. 2017
B. 2018
C. 2019
D. 2012
Solution: Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year | 2007 | 2008 | 2009 | 2010 | 2011 | 2012 | 2013 | 2014 | 2015 | 2016 | 2017 |
Number of Odd days | 1 | 2 | 1 | 1 | 1 | 2 | 1 | 1 | 1 | 2 | 1 |
Sum = 14 odd days = 0 odd days
Therefore, calendar of the year 2018 will have the same calendar as that of the year 2007.
Correct option: B
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