Tricks And Shortcuts on Calendar

Tips,Tricks and Shortcuts on Calendar.

The word calendar comes from ‘calendae’ , the word used  for the first day of the month in the Roman calendar, related to the verb calare means  “to call out” ,  referring to the “calling” of the new moon when it was first seen.

Tricks And Shortcuts on Calendar

Best  Tips , Tricks and Shortcuts on Calendar in Aptitude.

  • The calendar starts on 1st January and ends on 31st December.  The year is classified into two types:
    1. ordinary years (365 days)
    2. Leap year (366 days).
  • In an ordinary year, there are 365 days, which means 52 x 7 + 1, or 52 weeks and one day.
  • Here, are easy tricks and tips on Calendar problems Learn tricks on calendar.
  • There are 3 types of questions asked in exams

Type 1: AP questions

Question 1.

Find 10th term in the series 2, 5, 8, 11, 14……

Options:

  1. 26
  2. 29
  3. 32
  4. 27

Solution:

We know that,

tn = a + (n – 1)d
In the given series,

a = 2
d = 3 …. (5 – 2, 8 – 5…..)

Therefore, 10th term = t10 = a + (n-1) d

t10 = 2 + (10 – 1)  3

t10 = 2 + 9 x 3

t10 = 29

Correct option: 2

Question 2.

The sum of 3 numbers in arithmetic progression is 36 and product of their extreme is 80. Find the numbers.

Options:

  1. 20 , 8 , 16
  2. 4 , 12, 20
  3. 12 , 20 , 28
  4. None of these

Solution:

We know that,

tn = a + (n – 1)d

Assume the numbers as:

a-d, a, a+d

or a-d+a+a+d=36

or 3a=36

a=12

now (a-d) (a+d)=80

a²-d²=80

144-d²=80

d²=64

d=8

thus the numbers will be: 4, 12 and 20

Correct option: 2

Type 1: Calendar Tips and Tricks- To find the day of given date

Question 1. What was the day on 27th May 2006?

Options:

A. Monday

B. Saturday

C. Sunday

D. Friday

Solution:    27th May, 2006 = (2005 years + Period from 1.1.2006 to 27.5.2006)

To calculate number of odd days till 2000, we need

Number of odd days in 1600 years = 0

Number of odd days in 400 years = 0

Now, for calculating odd days in the next five years,

5 years = (4 ordinary years +1 leap year) = (4+2)

= 6 odd days

Now to calculate number of odd days from 1st January 2006 to 27th May 2006

January (31 days) + February (28 days because 2006 is an ordinary year) + March (31 days) + (April 30 days) + May 27 days = 147 days

Total number of odd days in 147 days = ((147/7) = 21 weeks+ 0 odd days

Total number of odd days in the entire period = 0 (1600 years) + 0 (400 years) + 6 (5 years) + 0 (Period from 1.1.2006 to 27.5.2006) = 6 odd days

As per the table, on 27th May 2006 the day was Saturday.

           Days   Sunday   Monday  Tuesday  Wednesday  Thursday  Friday  Saturday
Number of odd days       0         1        2           3        4     5       6

Correct option: B

Type 2: To find the day of the week for the given date when some other date or day is specified.

 

Question 1. It was a Saturday on 8th December 2007. What was the day on 8th Dec 2006?

Options:

A. Tuesday

B. Friday

C. Sunday

D. Saturday

Solution:     2006 was an ordinary year.

Therefore the number of odd   days in 2006 was = 1

Now, 8th Dec 2007 will be 1   day beyond the day on 8th   December 2006 due to one   odd day.

Since 8th December 2007 was Saturday, therefore, 8th December 2006 was Friday.

Correct option: B

Type 3: Shortcuts Tips and Tricks of Calendar To -Identify the year having same calendar.

Question 1. Which year will have the same calendar as that of the year 2007?

Options:

A. 2017

B. 2018

C. 2019

D. 2012

Solution:   Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Year  2007 2008 200920102011201220132014201520162017

Number of Odd days

     1    2     1    1    1   2   1   1   1    2    1

Sum = 14 odd days = 0 odd days

Therefore, calendar of the year 2018 will have the same calendar as that of the year 2007.

Correct option: B

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