Linear Equations Questions and Answers

Questions on Linear Equations 

Linear Equation Questions and Answers: Your Ultimate Resource | Top Tips and Tricks Discover a treasure trove of linear equation Q&A with top tips and tricks for solving them like a pro. Improve your problem-solving abilities and excel in math exams with our detailed answers.

questions on linear equations

Tips to solve Linear Equations :

Here are some useful tips to help you solve linear equations efficiently:

  1. Isolate the Variable: The goal is to get the variable (usually represented by ) on one side of the equation. Use inverse operations (addition, subtraction, multiplication, division) to move all other terms to the other side.

  2. Combine Like Terms: If you have multiple terms with the variable on the same side, combine them to simplify the equation.

  3. Use the Distributive Property: When dealing with parentheses, distribute the terms inside the parentheses to eliminate them.

  4. Eliminate Fractions: If the equation contains fractions, multiply both sides of the equation by the common denominator to eliminate them.

  5. Keep Equations Balanced: Perform the same operation on both sides of the equation to maintain equality.

  6. Simplify Radicals: If there are square roots or other radicals, try to simplify them by finding perfect square factors.

  7. Be Mindful of Negative Numbers: Pay attention to negative signs and avoid making sign errors during calculations.

  8. Check Your Solution: After finding the value of the variable, plug it back into the original equation to ensure it satisfies the equation.

  9. Practice Regularly: Like any skill, practice is crucial for mastering linear equations. Solve various problems to build your proficiency.

  10. Learn Common Mistakes: Be aware of common mistakes students make while solving linear equations and avoid them.

  11. Graphical Representation: Sometimes, graphing the equation on a coordinate plane can help visualize the solution.

  12. Word Problems: Convert word problems into linear equations by defining variables and setting up the equation before solving them.

By following these tips and practicing regularly, you’ll become more confident and proficient in solving linear equations. Happy math solving!

Rules for Linear Equations Questions and Answers.

  • If a=b then a+c=b+c for any c. All this is saying is that we can add a number, c, to both sides of the equation and not change the equation.
  • If a=b then a−c=b−c for any c. As with the last property we can subtract a number, c, from both sides of an equation.
  • If a=b then ac=bc for any c. Like addition and subtraction, we can multiply both sides of an equation by a number, c, without changing the equation.
  • If a=b then a/c=b/c for any non-zero c. We can divide both sides of an equation by a non-zero number, c, without changing the equation.

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Linear Equation Questions and Answers

1. The roots of the equation 4x-3\times 2x+2+32=0 would include-

20

20

8.28%

40

40

8.97%

5

5

2.07%

17

17

80.69%

Solution:

4x-3\times 2x+2+32=0

4x - 6x + 34 = 0

-2x + 34 = 0

2x - 34 = 0

2x = 34

x = 17

2. If ax =b, by=c  and  cz =a , then the value of xyz is:

4

4

2.05%

3

3

7.53%

2

2

2.05%

1

1

88.36%

Solution:

ax =b, by=c  and  cz =a

x = \frac {b}{a}

y = \frac {c}{b}

z = \frac {a}{c}

xyz = \frac{b}{a} \times \frac{c}{b} \times \frac{a}{c}

xyz = 1

3. If x = 1+21/2 and y=1-21/2, then x2+y2 is -

107/2

107/2

5.74%

203/2

203/2

8.2%

997/2

997/2

4.1%

445/2

445/2

81.97%

Solution:

x = 1+21/2 and y=1-21/2

x2+y2

\left ( 1 + \frac{21}{2} \right )^{2} + \left ( 1 - \frac{21}{2} \right )^{2}

1 + \left ( \frac{21}{2} \right )^{2}+ 2 \times 1 \times \left ( \frac{21}{2} \right ) + 1 + \left ( \frac{21}{2} \right )^{2}- 2 \times 1 \times \left ( \frac{21}{2} \right )

2 + 2 \times \left ( \frac{21}{2} \right )^{2}

2 + 441/2

445/2

4. If 4x+3 = 2x+7 , then the value of x is:

2

2

89.47%

3

3

3.76%

1

1

2.26%

4

4

4.51%

Solution:

4x+3 = 2x+7

2x = 4

x = 2

5. 2x+y = 2 and 2x-y = \frac {21}{2} ,the value of x is:

10/14

10/14

5.22%

9/8

9/8

0.87%

25/8

25/8

86.96%

5/4

5/4

6.96%

Solution:

2x+y = 2 and 2x-y = \frac {21}{2}

2x + y = 2

2x-y = \frac {21}{2}

Adding both equations we get:

4x = 2 + \frac {21}{2}

4x = \frac {25}{2}

x = \frac {25}{8}

Putting this in 2x-y = \frac {21}{2}

2 \frac {25}{8} - y = \frac {21}{2}

y = \frac {25}{8} - \frac {21}{2}

y =  \frac {25 -42}{4}

y = \frac {17}{4}

x = \frac {25}{8}

6. If x = 8, y = 27, the value of \sqrt{\left ( \frac{x^{4}}{3} + \frac{y^{2}}{3} \right )} is:

\sqrt{ \frac{4828}{3}}

\sqrt{ \frac{4828}{3}}

6.67%

\sqrt{ \frac{4825}{3}}

\sqrt{ \frac{4825}{3}}

79.05%

\sqrt{ \frac{4818}{3}}

\sqrt{ \frac{4818}{3}}

4.76%

\sqrt{ \frac{4826}{3}}

\sqrt{ \frac{4826}{3}}

9.52%

Solution:

= \sqrt{\left ( \frac{x^{4}}{3} + \frac{y^{2}}{3} \right )}

= \sqrt{\left ( \frac{8^{4}}{3} + \frac{27^{2}}{3} \right )}

= \sqrt{\left ( \frac{4096}{3} + \frac{729}{3} \right )}

= \sqrt{ \frac{4825}{3}}

7. What is the slope of the line represented by the equation 3y+4x=12?

​3/4

​3/4

8.87%

−4/3

−4/3

86.29%

3

3

1.61%

−4

−4

3.23%

Solution :

To find the slope of the line, we need to rewrite the equation in slope-intercept form (y=mx+b), where m is the slope.

Solving for y gives y = -\frac{4}{3}x + 4

The coefficient of x represents the slope, so the correct answer is −4/3​

8. If 2x + 3y = 16 and 2x - 3y= 36, the value of x is:

13

13

88.79%

23

23

2.8%

33

33

3.74%

43

43

4.67%

Solution:

2x + 3y = 16 -----(1)

2x - 3y= 36 ------ (2)

adding both eq we get

4x = 52

x = 13

9. If 6(x-3) = 36(x-5), then what is the value of x?

51/5

51/5

1.98%

27/5

27/5

90.1%

15/7

15/7

1.98%

17/3

17/3

5.94%

Solution:

6(x-3) = 36(x-5)

x - 3 = 6(x - 5)

x - 3 = 6x - 30

5x = 27

x = 27/5

10. Determine whether the ordered triple (3,−2,1) is a solution to the system.

2x+y+z=5,

6x−4y+5z=31,

5x+2y+2z=13

True

True

73.21%

False

False

16.96%

No solution

No solution

7.14%

None of the above

None of the above

2.68%

Solution - We will check each equation by substituting the values of the ordered triple for x,y, and z

x+y+z=2(3)+(−2)+(1)=5 True
6x−4y+5z=6(3)−4(−2)+5(1)=18+8+5=31 True 5x+2y+2z=5(3)+2(−2)+2(1)=15−4+2=13 True

The ordered triple (3,−2,1) is indeed a solution to the system.

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