# How To Solve Algebra Questions Quickly

## How To Solve Quickly Algebra Questions:-

### Definition:

Algebra is the study of mathematical symbols. It also covers and rules and regulations that helps users to evaluate these symbols. The study covers wide range of applications including simple equations that needs to be solved, to complex mathematical calculations. The page is covers everything that is helpful to Solve Algebra Questions Quickly

There are 6 main types of Algebraic Expressions. These are as under:

1. Monomial Expression
2. Binomial Expression
3. Trinomial Expression
4. Linear polynomial
6. Cubic polynomial

## Type 1: How To Solve Algebra Questions Quickly by Evaluation or finding the value of “a” variable

### Algebra Question 1:

Solve the given equation 17 x – 42 + 10= 100

Options

A. 7.76
B. 15.36
C. 36.96
D. None of the above

17 x – 42 + 10= 100
17x – 32 =100
17x = 100 +32
17x = 132
X= 7.76

### Question 2:

Solve 6a (2 – 3) – 3 (2a + b) = 5

Options

A. 6a + 2b+7
B. 10a+ 3b
C. 12a +3b + 5
D. None of the above

6a (2 – 3) – 3 (2a + b)= 5
12a – 18a – 6a -3b = 5
-6a – 6a -3b = 5
-12a – 3b = 5
12a +3b + 5

### Question 3:

Find the value of x in 3 (x- 5) – 5 (2x + 9) =10

Options

A. -5.69
B. – 9.28
C. 9.28
D. None of the above

3 (x- 5) – 5 (2x + 9) =10
3x – 15 – 10 x – 45 = 10
-7x – 60 = 10
-7x = 70
X= – 70/7
X= – 10

## Type 2: How to Solve Algebra Questions Quickly by- Substitution Methods

### Algebra Question 1:

Determine the value of 3(x)2 + 4(x)3 where x = 2

Options

A. 36
B. 56
C. 100
D. None of the above

3×2 + 4×3
Substituting the value of x, we get
3(2)2 + 4(2)3
3 x 4 + 4 x 6
12 + 24
36

### Question 2:

Calculate the value of the expression 3a + 2b – 15 where the value of a = 2 and b = 5.

Options

A. 6
B. 20
C. 5
D. 1

3a + 2b – 15
3 * 2 + 2 * 5 -15
6 + 10 -15
1

### Question 3:

What will be the value a in the given expression 2b + 2a + 53 = 72 where b = 10.

Options

A. 2/9
B. – 1/2
C. 3/2
D. None of the above

2b + 2a + 53 = 72
2 *10 + 2a +53 = 72
20 + 2a = 72 – 53
20 + 2a = 19
20 – 19 = -2a
1 = -2a
x= – 1/2

### Question 4:

Solve $(7 + 9 + 11)^{2}$ , using algebra identity.

Options

A. 729
B. 712
C. 669
D. 679

As the question given is $(7 + 9 + 11)^{2}$, we will be using identity of $(a + b + c)^{2}$ , which is also written as – $a^{2}+ b^{2} + c^{2} + 2ab + 2bc + 2ca$
Now – $(7 + 9 + 11)^{2}$
=> $7^{2}+ 9^{2} + 11^{2} + 2(7)(9) + 2(9)(11) + 2(11)(7)$