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# How To Solve Ratio And Proportion Questions Quickly

## How To Solve Ratio And Proportion Question Quickly

### Ratio

In some situations, the comparison by a division process makes good sense when compared to performing their difference. On this page you’ll learn How to **Solve Ratio And Proportion Quickly.**

Therefore, the comparison of two quantities by the process of division method is called as ‘Ratio’ between two numbers. The two numbers in a ratio can only be compared when they have the same unit. We make use of ratios to compare two things. The sign used to denote a ratio is ‘:’.

### Proportion

Ratio and proportions are said to be faces of the same coin. When two ratios are equal in value, then they are said to be in proportion. In simple words, it compares two ratios. Proportions are denoted by the symbol ‘::’ or ‘=’.

Go through the Tips and Tricks to Solve Ratio And Proportion Quickly.

**How To Solve Ratio And Proportion Questions **

** How to Solve Ratio And Proportion Quickly – Compound Ratio Based On Individual Ratios**

#### Question 1.

**Find the compound ratio of (9 : 10), (11 : 13), (15 : 19).**

A. 156:157

B. 297:494

C. 221:431

D. 1:5

**Correct answer B**

**Solution: **

If we compound two or more ratio, then, a : b and c : d will become ac:bd.

Therefore, (9 : 10), (11 : 13), (15 : 19) = 9/10 * 11/13 * 15/19 = 1485/2470

= 297/494

#### Question 2.

**Find the composite ratio of 2 : 3, 3 : 5, 5 : 7.**

A. 11 : 24

B. 2 : 7

C. 14 : 23

D. 24 : 97

**Correct answer B**

**Solution: **

The composite ratio is intended by 2/3 * 3/5 * 5/7 = 30/105

= 2/7

#### Question 3.

**Find the compounded ratio of (3 : 7), (9:5), and (11:21)**

A. 99:245

B. 13:17

C. 114:221

D. 305:711

**Correct answer A**

**Solution: **

If we compound two or more ratio, then, a : b and c : d will become ac:bd.

Therefore, (3 : 7), (9:5), and (11:21)= 3/7 * 9/5 * 11/21 = 297/735 = 99/245

**Distributing Any Quantity Based On Ratios**

#### Question 4.

**Rs. 27440 is divided among 5 females, 3 men, and 1 child. The ratio of each woman, man, and kid, are 9 : 3 : 2. What is the child’s share?**

A. 550

B. 760

C. 980

D. 952

**Correct answer C**

**Solution: **

Given, the ratio of females, males, and toddlers = 9 : 3 : 2

No. of females, men, and child are 5, 3, 1

Thus actual ratio of females, men, and child = 9 * 5 : 3 * 3 : 2 * 1 = 45 : 9 : 2

Therefore, part of child = (2/56) * 27440 = Rs. 980

#### Question 5.

**An amount of Rs. 58666 is divided among three employees in the ratio of 1/17, 1/19, and 1/21. Find the smallest share.**

A. 17561.7

B. 17200.49

C. 17000

D. 11760.50

**Correct answer A**

**Solution:**

Given, three shares = 1/17, 1/19, 1/21.

Therefore, the ratio will be 399/6783, 357/6783, 323/6783

Thus, the ratio is 399 : 357 : 323

The smallest share = 58666*323/1079

= 17561.7

**Coins Based Ratio Problems**

#### Question 6.

**Sahil got old currencies from his cupboard worth Rs. 450 in the denomination of 2 paisa, 5 paisa, and 50 paisa in ratio 5 : 4 : 3. How many 2 paisa coins he got.**

A. 1200

B. 1250

C. 1100

D. 1220

**Correct answer B**

**Solution: **

Let the number of 2 paisa coins be 5x

Let the number of 5 paisa coins be 4x

Let the number of 50 paisa coins be 3x

Then, 2*5x/100 + 5*4x/100 + 50*3x/100 = 180x/100

Given, 180x/100 = 450

Therefore, 450*100/180 = x

x = 250

Hence, 2paisa coins = 5 * 250 = 1250

#### Question 7.

**A person has 180 rupees in the denomination of 5paisa, 10paisa, and 25paisa in ratio 5 : 3 : 1. Calculate how many 25 paisa coins he has.**

A. 225

B. 200

C. 350

D. 300

**Correct answer A**

**Solution: **

Let the number of 5 paisa coins be 5x

Let the number of 10 paisa coins be 3x

Let the number of 25 paisa coins be x

Then, 5*5x/100 + 10*3x/100 + 25x/100 = 80x/100

Given, 80x/100 = 180

Therefore, 180*100/80 = x

x = 225

Hence, 25 paisa coins = 1*225 = 225 coins

#### Question 8.

**Harish has 1500 rupees in the denomination of 5 paisa, 25 paisa, and 50 paisa in ratio 5 : 3 : 2. Calculate how many 25 paisa coins he has.**

A.2800

B.2000

C.2500

D.2250

**Correct answer D**

**Solution: **

Let the number of 5 paisa coins be 5x

Let the number of 25 paisa coins be 3x

Let the number of 1 rupee coins be 2x

Then, 5*5x/100 + 25*3x/100 + 50 * 2x/100 = 200x/100

Given, 200x/100 = 1500

Therefore, 1500*100/200 = x

x = 750

Hence, 25 paisa coins = 3*750 = 2250

**How to Solve Ratio And Proportion Quickly – ****Mixtures & Addition Based Ratio Problems**

#### Question 9.

**Chetan and Shaheen’s salaries are in the ratio 5 : 9. If both of their salaries are raised by Rs. 4200, then the proportion changes to 22 : 27. Find Shaheen’s salary.**

A. 9250.95

B. 8058.32

C. 7199.97

D. 13580.45

**Correct answer C**

**Solution: **

Let Chetan and Shaheen’s salaries be 5x and 9x

Given, 5x + 4200 / 9x + 4200 = 22/27

135x + 113400 = 198x + 92400

63x = 21000

x = 333.33

Therefore, Shaheen’s salary = 333.33 * 9 + 4200 = 7199.97

#### Question 10.

**Salaries of Preeti and Bina are in the ratio 14 : 15. If both get an increment of Rs. 5300, the new ratio becomes 33 : 35. What is Preeti’s salary?**

A. 24000

B. 34980

C. 30100

D. 10200

**Correct answer B**

**Solution: **

Let Preeti’s salary be 14x, and Bina’s salary be 15x

Given, 14x + 5300 = 33

Given, 15x + 5300 = 35

= 14x + 5300/15x + 5300 = 33/35

= 490x + 185500 = 495x + 174900

5x = 10600

x = 2120

Therefore, Preeti’s salary = 14 * 2120 + 5300 = 34980

#### Question 11.

**400 g of 25% sugar syrup was added to 600 g of 40% sugar syrup. Find the percentage of the syrup in the mixture.**

A. 22%

B. 34%

C. 31%

D. 38%

**Correct answer B**

**Solution: **

Amount of sugar syrup in mixture 1 = 25/100*400= 100

Amount of sugar syrup in mixture 2 = 40/100*600 = 240

The total amount of sugar syrup = 340

Percentage of sugar syrup in the mixture = 340 * 100/ 1000 = 34%

Practice More Questions to Solve Ratio And Proportion Quickly.

**Read Also: Formula for Ratio And Proportion Questions **

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