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How To Solve Directional Senses Question Quickly
How to Solve Directional Sense Questions Quickly in Logical
This Page will cover all the details for How To Solve Directional Sense Questions Quickly.
Now, there are two methods rules
- Calculation method :- Generally used for easy questions
- Cheat Scale method :- Can solve difficult questions without difficulty, may not work for all problems
Before going further make sure that you know Pythagorus Formula
Hypotenuse2 = Perpendicular2 + Base2
Now, these facts should also be handy before going any further.
- An object’s shadow will fall in to the west side, i.e. opp. side of sunrise(Sun rises in East)
- Similary, shadow will fall in east at sunset.
- At noon i.e. 12:00am, no shadow(Theoretically) will just fall vertically
Calculation Method –
We will solve 2 questions for this, one easy and one hard. So, first you understand the concept and then you try that question yourself.
Easy Question –
A car(walking at constant speed) starts walking towards north for 5 hours and then turns right and walks another 3 hour and turns right again and walks 9 hours.
In such questions where only hours are given and speed to constant so distance will linearly proportional to time travelled so time can be used as distance units
We think that the image is self explanatory –
Finally we will use Pythagorous theorem to calculate the distance(in red)
hypotenuse^{2} = Altitude^{2} + Base^{2}
= (9 – 5)2+ 32
= 42 + 32
= 25.
Thus Distance = \sqrt{25} = 5
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Cheat Scale Method
Lets say in the last question perpendicular was 29 and base 23.
In most exams you can carry, a pencil scale ;). Now, rather than calculating complicated under roots of such powers, use a scale to measure hypotenuse distance, for example in the last question just measure the red line.
- Use 1 hour as 1 scale distance while making exact diagram with scale
- If problem is complicated then use approximations for example in case of 43 consider 10 units as 1 scale centimetre and 4.3 cms will be our distance
Degree based movement Questions
In such questions rather than giving – person turns left toward east than giving – person turns left, toward east. They provide information like person facing towards a direction turns x degrees in anti-clickwise direction.
For example – A person facing towards East turn 135 degrees in anti-clockwise direction will now be facing north west or i.e will be facing the middle of Quadrant 2.
The following diagrams gives anti-clock wise movement will be just opposite of it.
Below mentioned are the questions provided with the solutions to more understand the concepts.
How To Solve Directional Sense Questions Quickly
Question 1.
Santosh starting from her home, walks 4 km in the East, then she moves to her right direction and walks 3 km. to reach santosh’s home what is the shortest distance?
Explanation:
To find out the minimum distance among these points we need to apply the Pythagoras theorem. the smallest distance among will come by applying the formula: sum of the squares of the other two sides is equal to the square of the hypotenuse
Minimum distance = root square of 4 and 3
=Root of 25=5kms
Hence, the distance between the starting point to finish point is 5 kms.
Question 2.
Temple ram is in the Northside of the temple Panna. The temple Radha is in the Eastside of temple ram. The temple Swaminarayan is to the left side of the temple Panna. In which direction is the temple Swaminarayan with respect to temple Radha?
A. West
B. South-West
C. South
D. North-West
Answer: B
Explanation:
South-west
Questions 3.
A dog is looking for his mother. He travelled 90 metres in the Eastside before turning to his right. He went 20 meters before turning to his right again to look for his mother at his master’s place 30 metres from this point. But dog’s mother was not there. From this point he again ran 100 metres to the Northside before finding his mother in a road. What is the minimum distance among the starting point and his mother’s position?
A. 40 metres
B. 80 metres
C. 100 metres
D. 160 metres
Answer: C
Explanation:
The movement of the dog from A to E is as shown in figure.
Clearly, the dog meets his mother at E.
Now, AF = (AB – FB)
= (AB – DC) = (90 – 30) metres = 60 metres.
EF = (DE – DF) = (DE – BC)
= (100 – 20) metres = 80 metres.
So the total distance is = root of (square of 60 + square of 80), which will be 100 metres.
Solve Quickly Directional Sense Questions: Right Direction/ Position of Shadow
Question 4.
One morning after dawn, Pritesh was standing facing a rod. The shadow of the rod fell exactly to his right. To which direction was he facing?
A. East
B. West
C. South
D. Data is inadequate
Answer: C
Explanation:
Sun rises in the east in the morning. Since the shadow of Pritesh falls to his right. So he is facing South.
Question 5.
One evening previous to dusk Rashmi and Heena were conversing face to face with each other. If Heena’s shadow was closely to the right side of Heena, so Rashmi was facing in which direction?
A. North
B. South
C. East
D. Data is inadequate
Answer: B
Explanation:
The sun sets in Westside in evening time. So, any shadow will falls in the Eastside only. Since Heena’s shadow was exactly to the right side of Heena. Hence Rashmi was facing towards South direction.
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