Calendar Questions and Answers

It was Saturday on 31^st December 2005.

Odd days from the year 2006 to 2009 = (1+1+2+1) = 5 days

Therefore, it was Thursday on 31^st December 2009, and the next day, 1^st January 2010 will be Friday.

28 May 2006

= (2005 + time from 1^st Jan 2006 to 28^th May 2006)

Number of odd days in 1600 years =0

Number of odd days in 400 years =0

Calculation for 4 years = (4 ordinary years + 1 leap year)

= (4 x 1 + 1x 2)

= 6 odd days

Also, total days =

Jan = 31

Feb = 28

March = 31

April = 30

May= 28

Sum of all these days = 148

Number of add days in these 148 days = (21 weeks + 1 day) = 1 odd day

Total odd days = 0+0+6+7 = 7 (which leaves no odd day)

Therefore, the required day is Sunday.

It takes seven days to repeat each day in a week.

Therefore, after 63 days, it will be on Monday.

And after 61 days, it will be on Saturday.

2004 is a leap year and has 2 odd days

The month of Feb 2004 will not be calculated and hence, it has only 1 odd day.

Therefore, the day of 6^th March 2005 will be one day after the day on 6^th March 2004.

It is also given that 6^th March 2005 is a Monday.

Hence, 6^th March 2004 is a Sunday.

Determining the day on 1^st April 2001 = (2000 + time from 1.1.2001 to 1.4.2001)

Number of odd days in 1600 years = 0

Number of odd days in 400 years = 0

Calculation for Jan, Feb, March, and April= 31 +28 + 31 +1 = 91 days and 0 odd days

Total odd days = (0+0+0) =0

Day on 1^st April 2001 = Sunday

Therefore, dates on which Wednesday will fall = 4, 11, 18, and 25 as counted by the interval of 7 days each.

p weeks and p days = (7p + p) days

= 8p days

Odd days in 100 years = 5

Therefore, we can say that the last day of the first century is Friday.

Odd days in 200 years = (2 x 5) Ξ 3 odd days

Therefore, the last day of the second century is Wednesday

Odd days in 300 years = (5 x 3) = 15  Ξ 1 odd days

Therefore, we can say that the last day of the third century is Monday.

Odd days in 400 years = 0

Therefore, we can say that the last day of the 3rd centaury is Sunday.

The above cycle is repeated.

We can say that a century’s last day cannot be Tuesday, Thursday, or Saturday.

2004 is a leap year and hence, number of odd days = 2

Therefore, the day of 8th Feb 2004 will be 2 days before the day on 8th Feb 2005.

Therefore, the day is Saturday.

The number which is divisible by 400 is a leap year.

Therefore, the year 300 is not a leap year.

2006 is an ordinary year. Hence, the number of odd days = 1.

Also, the day of 7^th December 2007 will be one day after the day on 7^th December 2006.

Day on 7^th December 2007= Friday.

Hence, 8^th December 2006 = Thursday.