How To Solve Successive Discounts Questions Quickly

How to Solve Successive Discounts Questions Quickly

  • Successive Discount is the  reduction in price of a Goods or Service .
  • Successive Discount is the discount is applied on other discount .

Below you will get to know more about how to solve successive discount questions quickly. This will help you in solving successive discount questions easily.

Tips and Tricks Successive Discount

How to solve Quickly Successive Discounts Questions

  • Successive discount is discount on discount.
    • Case 1: If there are two discounts.
    • Case 2: If there are three discounts.
  • Marked price is the price marked on the product. It is the same price on which you get discounts.

Example:   The marked price of a shirt is Rs.1000. A shopkeeper offers 10% discount on this shirt. How much will you have to pay, finally?

Solution :   Discount =10% of 1000 = \frac{10}{100} × 1000 =Rs 100

Selling Price= 1000- 100 = Rs 900

  • But in exam,you can do it directly in your head.So just think that 10 percent discount means you’ve to pay 100 percent minus 10 percent=90 percent of the marked price which means, ( \frac{90}{100})* 1000 =Rs. 900

Type 1: If there are two discounts (1st discount is x% and 2nd  discount is y%) 

Question 1. The present population of town is 5000. In the first year the population increased 20% and in the next year decreased by 30%. Find the population after two years?  

Options.

 A. 1000 

B. 3840

C. 1780

D. 4200

Solution      20% = \frac{20}{100} = \frac{2}{10}(Now add numerator and denominator as the percentage increased) 

Which is 10 + 2 = 12 

Similarly, 30 % =  \frac{30}{100} \frac{3}{10} (Now subtract numerator from denominator as the percentage decreased) 

Which is 10 – 3 = 7 

Now Multiply 10 * 10 and 12 * 7 

We get 100 and 84. 

Now solve  \frac{5000}{100} * 84 = 4200  

Correct option: D 

Question 2.  The successive discount of 30% and 40% is given on holiday package. If the price of the package is 10000. What is final price of the package? 

Options

 A. 2100 

B. 4200

C. 2400

D. 5800

Solution:     Total discount = M + N – \frac{MN}{100}

Total discount = 30 + 40 – \frac{30 × 40}{100}

Total discount = 58% 

Discount = 58% of 10000 

Discount = 5800 

S.P = M.P – Discount  

S.P = 10000 – 5800 

S.P = 4200 

Correct option: B 

Question 3. A shopkeeper is selling a phone at 15000 Rs but he is offering two schemes 

Scheme A: Buy it at one time discount of 30% 

Scheme B: Buy it at two successive discounts of 15% and 15% 

Help the customer to find the best scheme.

Options 

A. Scheme A 

B. Scheme B

C. Both are equal

D. None of the above

Solution:     Scheme A offers Discount of = 30%  

It means 0.7 * original price 

Scheme B offers Discount of = 15% and 15% 

It means 0.85 * 0.85 * original price = 0.7225 * original price 

Therefore, Scheme A is the best scheme.  

Correct option: D

Type 2: If there are two discounts (1st discount is x%, 2nd  discount is y% and 3rd discount z%) 

Question 1.  In a shop a dress was on a discount. The discount on the printed price of the dress are 20% and 12% and 5 % respectively, what is the total percentage of actual discount given on the dress? 

Options

A. 33.12% 

B. 33.5%

C. 21.3%

D. 33%

Solution:     First, calculate for first 2 discounts = 20 + 12 –  \frac{20 × 12}{100} = 29.6% 

Now discount D = 29.6% and Z = 5 % 

Total discount = D + Z – \frac{DZ}{100}

Total discount = [29.6 + 5 – \frac{29.6  ×5}{100}] % 

Total discount = 33.12% 

Therefore total discount is 33.12% 

Correct option: A  

Question 2. In a shop a dress was on a discounts. The discount on the printed price of the dress are 5% and 10% and 15 % respectively. The marked price of the dress is 1500. Then calculate overall discount and selling price of the dress? 

Options

A. 1000.125 

B. 1900.125

C. 1910.125

D. 1090.125

Solution:     First, calculate for first 2 discounts = 5 + 10 – \frac{5 × 10}{100} = 14.5% 

Now discount D = 14.5% and Z = 15 % 

Total discount = D + Z – \frac{DZ}{100}

Total discount = [14.515 – \frac{14.5 × 15}{100}] % 

Total discount = 27.32% 

Discount = 27.32% of 1500 = 409.875 

Selling price = 1500 – 409.875 = 1090.125 

Correct option: D 

Question  3.  A man gave his property at three successive discounts of 20%, 10% and 10%. If the price of a property was Rs. 500000 and sales tax on it is 15% of its sale price, then how much a buyer  will have to pay for it? 

Options

A. 327600 

B. 376200

C. 372600

D. 372060

Solution:     Selling price = price – discounts 

Selling price = 500000 * (1- \frac{20}{100}) * (1- \frac{10}{100}) * (1- \frac{10}{100}) 

Selling price = 324000 

Rate of sales tax = 15% 

Price to be paid by buyer = Selling price + tax 

Price to be paid by buyer = 324000 + 15% of 324000 

Price to be paid by buyer = 324000 + 48600 

Price to be paid by buyer = 372600

Correct option: C 

 

Read Also – Formulas to solve successive discount questions