How To Solve Successive Discounts Questions Quickly

How to Solve Successive Discounts Questions Quickly

Successive Discount is the  reduction in price of a Goods or Service .

Successive Discount is the discount is applied on other discount .

How to Solve SuccessiveDiscounts Questions Quickly

How to solve Quickly Successive Discounts Questions

  • Successive discount is discount on discount.
    • Case 1: If there are two discounts.
    • Case 2: If there are three discounts.
  • Marked price is the price marked on the product. It is the same price on which you get discounts.

Example:   The marked price of a shirt is Rs.1000. A shopkeeper offers 10% discount on this shirt. How much will you have to pay, finally?

Solution :   Discount =10% of 1000 = \frac{10}{100} × 1000 =Rs 100

Selling Price= 1000- 100 = Rs 900

  • But in exam,you can do it directly in your head.So just think that 10 percent discount means you’ve to pay 100 percent minus 10 percent=90 percent of the marked price which means, ( \frac{90}{100})* 1000 =Rs. 900

Type 1: If there are two discounts (1st discount is x% and 2nd  discount is y%) 

Question 1. The present population of town is 5000. In the first year the population increased 20% and in the next year decreased by 30%. Find the population after two years?  

Options.

 A. 1000 

B. 3840

C. 1780

D. 4200

Solution      20% = \frac{20}{100} = \frac{2}{10}(Now add numerator and denominator as the percentage increased) 

Which is 10 + 2 = 12 

Similarly, 30 % =  \frac{30}{100} \frac{3}{10} (Now subtract numerator from denominator as the percentage decreased) 

Which is 10 – 3 = 7 

Now Multiply 10 * 10 and 12 * 7 

We get 100 and 84. 

Now solve  \frac{5000}{100} * 84 = 4200  

Correct option: D 

Question 2.  The successive discount of 30% and 40% is given on holiday package. If the price of the package is 10000. What is final price of the package? 

Options

 A. 2100 

B. 4200

C. 2400

D. 5800

Solution:     Total discount = M + N – \frac{MN}{100}

Total discount = 30 + 40 – \frac{30 × 40}{100}

Total discount = 58% 

Discount = 58% of 10000 

Discount = 5800 

S.P = M.P – Discount  

S.P = 10000 – 5800 

S.P = 4200 

Correct option: B 

Question 3. A shopkeeper is selling a phone at 15000 Rs but he is offering two schemes 

Scheme A: Buy it at one time discount of 30% 

Scheme B: Buy it at two successive discounts of 15% and 15% 

Help the customer to find the best scheme.

Options 

A. Scheme A 

B. Scheme B

C. Both are equal

D. None of the above

Solution:     Scheme A offers Discount of = 30%  

It means 0.7 * original price 

Scheme B offers Discount of = 15% and 15% 

It means 0.85 * 0.85 * original price = 0.7225 * original price 

Therefore, Scheme A is the best scheme.  

Correct option: D

Type 2: If there are two discounts (1st discount is x%, 2nd  discount is y% and 3rd discount z%) 

Question 1.  In a shop a dress was on a discount. The discount on the printed price of the dress are 20% and 12% and 5 % respectively, what is the total percentage of actual discount given on the dress? 

Options

A. 33.12% 

B. 33.5%

C. 21.3%

D. 33%

Solution:     First, calculate for first 2 discounts = 20 + 12 –  \frac{20 × 12}{100} = 29.6% 

Now discount D = 29.6% and Z = 5 % 

Total discount = D + Z – \frac{DZ}{100}

Total discount = [29.6 + 5 – \frac{29.6  ×5}{100}] % 

Total discount = 33.12% 

Therefore total discount is 33.12% 

Correct option: A  

Question 2. In a shop a dress was on a discounts. The discount on the printed price of the dress are 5% and 10% and 15 % respectively. The marked price of the dress is 1500. Then calculate overall discount and selling price of the dress? 

Options

A. 1000.125 

B. 1900.125

C. 1910.125

D. 1090.125

Solution:     First, calculate for first 2 discounts = 5 + 10 – \frac{5 × 10}{100} = 14.5% 

Now discount D = 14.5% and Z = 15 % 

Total discount = D + Z – \frac{DZ}{100}

Total discount = [14.515 – \frac{14.5 × 15}{100}] % 

Total discount = 27.32% 

Discount = 27.32% of 1500 = 409.875 

Selling price = 1500 – 409.875 = 1090.125 

Correct option: D 

Question  3.  A man gave his property at three successive discounts of 20%, 10% and 10%. If the price of a property was Rs. 500000 and sales tax on it is 15% of its sale price, then how much a buyer  will have to pay for it? 

Options

A. 327600 

B. 376200

C. 372600

D. 372060

Solution:     Selling price = price – discounts 

Selling price = 500000 * (1- \frac{20}{100}) * (1- \frac{10}{100}) * (1- \frac{10}{100}) 

Selling price = 324000 

Rate of sales tax = 15% 

Price to be paid by buyer = Selling price + tax 

Price to be paid by buyer = 324000 + 15% of 324000 

Price to be paid by buyer = 324000 + 48600 

Price to be paid by buyer = 372600

Correct option: C 

 

Read Also – Formulas to solve successive discount questions