Succesive Discounts Questions and Answers

Cost Price for a single stapler = \frac{100}{200} = INR 0.50
Selling Price for a single stapler = \frac{100}{150} = INR \frac{2}{3}
Profit formula = SP – CP = INR \frac{1}{6}
So, profit = \frac{\frac{1}{6}}{0.50}\times 100 = 33.34%

Assume cost price of the frame as Rs. C
Selling Price = Cost Price – Loss
=>1905 = Cost – 0.1 Cost
=>0.9 Cost = 1905
Cost = 2117
So, to gain 10 %, Selling Price = 2117 + (0.1 x 2117) = 2328.7

Assume the selling price of the jewellery be Rs. Z
=Cost price of the jewellery = 67 % of Z = 0.67 Z
Profit = SP – CP = 0.33 Z
So, profit = \frac{0.33 Z}{0.67 Z} \times 100 = 49.25 %

The information we have is 50 Kg at Rs. 20.50 per KG and 90 KG at Rs. 25 per KG.
=Total cost price = (50 x 20.50) + (90 x 25) = 1025 + 2250 = Rs. 3275 and total rice = 50 + 90 = 140 KG

Selling price = Total cost price + 15 % of total cost price
=Total selling price = 3275 + (0.15 x 3275) = Rs. 3766.25
Thus, selling price per KG = 3766.25 / 140 = Rs. 26.90

Profit per cent formula = (Correct Price – Given Price) / Given Price] x 100 %
Here, Correct Price = 1 kg
Given Price = 800 gm
Thus, profit = \frac{(1000 – 800) }{800}\times 100

=\frac{200}{800} \times 100

= 25 %

As we know that if two dress materials are sold at the similar price, one at an advantage of X% and another at the loss of X%, then the seller will always suffers a loss of \frac{x^{2}}{100}
Loss per cent = \frac{x^{2}}{100} = \frac{20^{2}}{100} = 4%

Assume the marked price of the tracksuit be Rs. 1000
Price after first discount = Rs. 1000 – 30 % of Rs. 1000 = Rs. 1000 – 300 = Rs. 700
Price after second discount = Rs. 700 – 10 % of Rs. 700 = Rs. 700 – 70 = Rs. 630
Price after cash discount = Rs. 630 – 5 % of Rs. 630 = Rs. 630 – 31.50 = Rs. 598.50
So, total discount = Rs. 1000 – 598.50 = Rs. 401.50
=> Overall discount percent = (401.50 / 1000) x 100 = 40.15 %

Assume the cost price of the laptop be Rs. 100
=> S.P. of the laptop = Rs. 100 + 25% of CP = Rs. 125
now assume the marked price as Rs. X
=> Selling price = Marked Price – Discount
=> 125 = X – 0.05 X
=> 125 = 0.95 X
=> X = 131.57
=> X – CP = 131.57 – 100 = 31.57
Thus percentage = (31.57 / 100) x 100 = 31.57 %

Given 22 CP = 20 SP
CP/SP = 20/22 = 10/11
Profit = SP – CP
=> 11 – 10 = 1
Profit (%) = profit/CP x 100
=> 1/10 x 100
=> 10 %

 Loss % = 22 %
= 22/100
= 11/50
Loss= 11 and CP = 50
SP = CP – Loss = 50 – 11 = 39
CP : SP =  50 : 39

Let the price at shop 1 = 100x
then price at shop 2 = 80x

100x – (80x + 200) = 200
20x = 400
x = 20
Price at shop 1 = 100×20 = 2000
Price at shop 2 includes cost of travel = 80×20 + 200 = 1800
Profit percentage = [(2000 – 1800) / 2000]x100=10%
Thus profit= 10%.

As given:
Computer/printer = 4/7
Difference in ratio = 3
3 -> 4500
1 -> 1500
The price of the Computer = 4×1500 = 6000

In this case there is always loss  of \frac{x^{2}}{100} = \frac{30^{2}}{100} = 9%

 

SP of smart watch = Rs 3500
Profit % = 15 %
CP = (SP/100+P)x100
CP = (3500/115) x 100
New profit% = 10%
New SP = CPx(100+P%)/100
= (3500/115)x100x(110/100)
= 3347.3, or 3347.
Therefore, the selling price of smart watch is Rs 3347.

CP = 3500

P =30%

Profit = 3500×30/100

= 1050

Net profit = profit – tax

= 1050 – 350 = 700

Net profit % = \frac{700}{3500} \times 100

= 20%

Hence, net profit percent is 20 %

 

Based on the information given: let’s assume that Arish sells to bromil at 100 rs.

Arish                 Bromil                 Catherin

100____{25% profit}____ 125_____{20% profit}___150

Now, 150 unit -> 900
1 unit -> 6
100 unit -> 600
Therefore, the cost price of the headphone is 600.

Let unit price of strawberry is x

\frac{72}{x} - \frac{72}{1.2x} = 4

72 - 60 = 4x

12 = 4x

x = 3

He purchased 24 strawberries of Rs 72 before increase of price and 4 less strawberries after increase.
24 strawberries = Rs 72
1 strawberry = Rs 3
16 strawberries = Rs 48.

Discount is calculated on Marked Price

Selling Price of 1 bedsheets = \frac{12000}{100} = 120

Gain = 20 x 120 = 2400

Cost Price = 12000 - 2400 = 9600

Let cost price = 100

Selling price = 100+20 =120

Marked Price = \frac{120}{0.90} = 133.33

20 unit -> 133.33

1 unit -> \frac{133.33}{20}

9000 unit = \frac{133.33}{20}\times 9000 = 59998.5 = 60000

Thus the marked price of car was Rs 60000.

As per the given information:

CP                MP

100 - Discount:  100 + profit

100 - 15      :   100 + 25

85          :     125

17           :      25

25-17 = 8
Raised % = \frac{8}{17} \times  100
= 47.05

Let the cost price be Rs. A

Actual Selling Price = Rs. 1770

Actual Profit = (1770 - A) Rs.

Profit % = \frac{(1770 - A)}{CP}\times 100

Now, new Selling Price = Rs. 3000

Original CP = Rs. A

New profit = (3000 - A) Rs.

New profit % = \frac{(3000 - A)}{CP}\times 100

\frac{(3000 - A)}{CP}\times 100 - \frac{(1770 - A)}{CP}\times 100 = 10

\frac{(300000 – 100A)}{CP} - \frac{(177000 - 100A)}{CP} = 10

\frac{123000}{CP} = 10

10CP = 123000

CP = 12300

CP = 12300. So, the original Cost price is Rs. 12300

For Bhaskar,

CP = 25,000   Profit = 10%

SP = ((100+P%)/100) * CP

SP = ((100+10)/100) * 25000

SP = 27500

For Mitesh,

CP= 27500  Loss = 10%

SP = ((100-10)/100) * 27500

SP = 24750

Therefore, totally Rakesh gains Rs.(27500-24750) i.e. Rs. 2750

Marked price= ₹ 600, d1 = 15, d2 = 10

SP = (1 - d1/100) (1- d2/100) × MP

SP = (1 - 15/100) (1 - 10/100) × 600

SP = (1 - 3/20) ( 1- 1/10) × 600

SP = 17/20 × 9/10 × 600

SP = 459

Therefore, S.P. = Rs. 459

Discount will be deducted

Tax will be Added

Amount she will have to pay for the items = 7550\times \frac{95}{100} \times \frac{110}{100} = 7889.75

Profit of Anjali is 20%. Profit of Bhawna is 25%.

Selling price of Bhawna is 225

Cost price of Bhawna= 100/(100+profit%)×Selling Price

={100/(100+25)}×225

=(100/125) ×225=180

Then selling price of Anjali is 180

So cost price of Anjali={100/(100+20) }×180=(100/120) ×180=150

10% discount so Selling Price=7200

Gift costing rs. 1200 so now Selling Price = 6000

CP +CP x 20%=6000

CP=5000

Cost price of annirudh is 4,50,000

Cost price of ishita is the selling price of Annirudh.

Cost price of ishita =\frac{100}{90} \times 4,95,000 = 5,50,000

Annirudh Profit = 5,50,000-4,50,000=10,0000

Annirudh Profit% = \frac{100000}{450000}\times 100 = 22.22%

selling price of 22 sharpeners is 12rs

Assume cost price of 22 sharpeners is x; so x-12 = 5

By solving, x = 17

Now the second condition says that selling price is 16 and cost price is 17 so loss = 17-16 = 1

Let the cost of article be x

when Selling Price = 1350

P% = \frac{(1350-x)}{x}\times 100

While SP = 1340

P% = \frac{(1340-x)}{x}\times 100

5% more is gained by selling article for rs. 1350 than for 1340

\frac{(1350-x)}{x} – \frac{(1340-x)}{x} = \frac{20}{100}

\frac{10}{x} = \frac{20}{100}

x = 50