Check for Perfect Square in C++

Program to Check for Perfect Square in C++

September 27, 2022

Check for Perfect Square in C++

Today in this article we will discuss the program to check for perfect square in C++ programming language. We are given with an integer number and need to print “True” if it is, otherwise “False”.

Method 1:

Take the floor() value square root of the number.
Multiply the square root twice.
We use boolean equal operator to verify if the product of square root is equal to the number given.

Method 1 :Code in C++

Run

#include <bits/stdc++.h>
using namespace std;
 
bool isPerfectSquare(long double x)
{
    if (x >= 0) {
 
        long long sr = sqrt(x);
        return (sr * sr == x);
    }
    
    return false;
}
 
int main()
{
    long long x = 84;
    if (isPerfectSquare(x))
        cout << "True";
    else
        cout << "False";
    return 0;
}

Output :

False

Method 2 :

In this method we use the floor and ceil function .
If they are equal that implies the number is a perfect square.

Method 2 :Code in C++

Run

#include <iostream>
#include <math.h>
using namespace std;
 
void checkperfectsquare(int n)
{
    if (ceil((double)sqrt(n)) == floor((double)sqrt(n))) {
        cout << "True";
    }
    else {
        cout << "False";
    }
}

int main()
{
 
    int n = 49;
    checkperfectsquare(n);
    return 0;
}

Output :

True

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One comment on “Program to Check for Perfect Square in C++”

sudhanshu
// perfect square

#include
#include
#include
using namespace std;

void perfect(int n){
int square, temp = n, digit;
for (int i = 1; i < n; i++)
{
square = pow(i,2);
if(square == temp)
break;
digit = i+1;
}
square == temp? cout<<square<<" is a Perfect square of "<<digit:cout<<"Not a perfect square";

}

int main()
{
int num;
cout<> num;
perfect(num);
return 0;
}

0

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