Check if a Number is Positive or Negative in Java

Check if a Number is Positive or Negative in Java

Check if a Given Number is Positive or Negative in Java

Given an integer num input the objective is to write a code to Check if a Given Number is Positive or Negative in Java Language.

Example
Input : num = 11
Output : Positive

Check if a Number is Positive or Negative in Java

In this article, we will create a java program to check whether the number entered by the user is positive or negative. The number is demonstrated as positive or negative by comparing the entered number with the Zero(0). If the number entered by the user is greater than zero, then the number is positive, else if the number is less than zero, then the number is negative and else the number is zero.

  • N > 0 then, number is Positive.
  • N < 0 then, number is Negative.
  • N = 0 then, number is Zero.

To solve the above problem we write a Java code using three different methods.

  • Method 1: Using Brute Force
  • Method 2: Using Nested if-else Statements
  • Method 3: Using Ternary Operators

The Above methods are discussed in depth in the sections below.

  1.  
Check if a Number is Positive or Negative in Java

Method 1: Using Brute Force

This method uses Brute Force to check whether a given integer is Positive or Negative.

Java Code

Run
//Brute force
class Main
{
  public static void main (String[]args)
  {

    int num = 5;

    //Conditions to check if the number is negative or positive
    if (num > 0)
        System.out.println ("The number is positive");
    else if (num < 0)
        System.out.println ("The number is negative");
    else
        System.out.println ("Zero");
  }
}

Output

The number is positive

Algorithm

This method uses Brute Force to check whether a given integer is Positive or Negative. The Algorithm for the above code is as follows

  • Step 1. Start
  • Step 2. Insert the number.
  • Step 3. If the number is greater than Zero then print “The number is Positive”
  • Step 4: If the number is smaller than zero, then print, “The number is Negative”
  • Step 5. Else print, “The number is Zero”
  • Step 6. Stop

 

Method 2: Using Nested if-else Statements

This method uses a nested if-else Statements to check whether a given number is Positive or Negative.

Java Code

Run
//Using Nested If-else statement
class Main
{
  public static void main (String[]args)
  {

    int num = 5;
    
     //Condition to check if the number is negative or positive
    if (num >= 0)
    {
        if (num == 0)
            System.out.println ("Zero");
        else
            System.out.println ("The number is positive");
    }
    else
        System.out.println ("The number is negative");

  }
}


Output

The number is positive

Algorithm

This method uses a nested if-else Statements to check whether a given number is Positive or Negative.

  • Step 1 – Start
  • Step 2 – Insert the number.
  • Step 3 – If the number is greater or equal move to the inner nested loop
    • Step 3.1 – If the number is zero, print Zero
    • Step 3.2 – Else print The Number is Positive
  • Step 4 – Else the number has to be negative, Print The number is Negative
  • Step 5 – Stop

 


Method 3: Using Ternary Operator

This method uses a ternary operator to check whether a number is Positive or Negative.

Java code

Run
//Using Ternary Operator
class Main
{
  public static void main (String[]args)
  {

    int num = 0;

    //Condition to check if the number is negative or positive

    if (num == 0)
      {
	    System.out.println ("Zero");
      }
      
    else{
        String result = num > 0 ? "The number is positive" : "The number is negative";
        System.out.println (result);
    }
  }
}


Output

Zero

Algorithm

This method uses a ternary operator to check whether a number is Positive or Negative. The Algorithm for the above code is as follows,

  • Step 1 – Start
  • Step 2 – Insert the number.
  • Step 3 – If number is equal to zero, Print Number is Zero
  • Step 4 – Else do following – (num > 0) ? cout << “Positive”: cout << “Negative”;
  • Step 5 – Stop

 

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