# C++ Program to find the Sum of N Natural Numbers # Sum of N natural number

In this C++ program we will find the sum of n natural numbers. First, the user have to insert any integer value.  Then user is asked to enter a value of n and run for loop to the range of n. Inside for loop for every cycle value will be incremented by i.
N natural numbers means 1,2,3,4,5,6,7,8…….infinite
To perform the arithmetic addition operation of n numbers where n will be entered by the user.

For Example:-
Enter number : 8
Where first 8 number is 1,2,3,4,5,6,7,8
Sum of numbers = 1+2+3+4+5+6+7+8 = 36  ## Algorithm:-

Step 1 : Ask the user to enter a  number which will denote the limit.

Step 2 : Declare a variable to store the addition and initialize it with 0.

Step 3 : Use a loop to perform iterations for adding natural numbers from 1 till the limit entered by the user.

Step 4 : Use a statement for addition purpose.

Step 5 : Print the result. ### C++ Code:-

```#include<iostream>
using namespace std;
int main()
{
//for initialize variable
int Number, i, Sum = 0;
//to take user input
cout<<"\n Kindly Insert an Integer Variable\n"; cin>>Number;

//use for loop for these condition
for(i = 1; i <= Number; i++)
{
Sum = Sum + i;
}

//display
cout<<"Sum of Natural Numbers: "<< Sum;

return 0;
}
```

### Output

```Kindly Insert an Integer Variable
4
Sum of Natural Numbers: 10``` 