Java Program to Check Whether a Number is Even or Odd

Check if a Number is Even or Odd in Java

Check Whether a number is Even or Odd using Java 

Given an integer input num, the objective is to write a code to Check Whether a Number is Even or Odd in Java Language. To do so we check if the number is divisible by 2 or not, it’s Even if it’s divisible otherwise Odd.

Example 
Input : num = 11
Output : Odd

Check Whether a Number is Even or Odd in Java

Given an integer input the objective is to write a Java code to Check Whether a Number is Even or Odd. To do so the main idea is to divide the number by 2 and check if it’s divisible or not. It’s an Even number is it’s perfectly divisible by 2 or an Odd number otherwise.

Here are the Methods to solve the above mentioned problem,

  • Method 1 : Using Brute Force
  • Method 2 : Using Ternary Operator
  • Method 3 : Using Bitwise Operators
We’ll discuss the above mentioned methods in detail in the next section.

Method 1 : Using Brute Force

This method simply checks if the given input integer is divisible by 2 or not. If it’s divisible then print Even or Odd otherwise.

Algorithm

The working of the above code is mentioned below

  1. Input an integer input “number
  2. Check whether the number is divisible by 2
  3. This means using modulo/remainder operator leaves 0 as a remainder
  4. Do : if (number % 2 == 0)
    1. if yes, print “Even number”
    2. if not, print “Odd number”

Java Code

Run
public class Main
 {
      public static void main(String[] args) {
           int number = 29;


     //checking whether the number is even or odd
     if (number % 2 == 0)
              System.out.println(number + " is Even");
     else
              System.out.println(number + " is odd");
      }
 }

Output

29 is Odd 

Method 2 : Using Ternary Operator

This Method uses the ternary operator to check if the integer input is divisible by 2, If true print Even or Odd otherwise.

Algorithm

The working of the above code is as follows,

  1. Input an integer input “number
  2. Check whether the number is divisible by 2 using the ternary operator
  3. (number % 2) ? (cout <<“Even”) : (cout << “Odd”)

Java Code

Run
 public class Main
 {
   public static void main (String[]args)
   {
     int number = 29;

     //Checking if the number is divisible by 2
     String status = number % 2 == 0 ? " is Even" : " is Odd";
       System.out.println (number + status);
   }
 }

Output

 29 is Odd

Method 3 : Using Bitwise Operator

This Method uses bitwise operators to check if a given number is Even or Odd.

Algorithm

The working of the above code is as follows,

  1. If we have any number ‘n‘ doing bitwise ‘&‘ operation will give resultant as
    • 1: If n is odd
    • 0: if n is even

Java Code

Run
public class Main
{
  public static void main (String[]args)
  {
    int number = 29;

    if (isEven (number))
        System.out.println ("Even");
    else
        System.out.println ("Odd");
  }


// Returns true if n is even, else odd
  static bool isEven (int number)
  {

    // n & 1 is 1, then odd, else even
    return (!(number & 1));
  }
}


Output

Odd

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