Harshad number or not using Java

September 28, 2022

Harshad number or not using Java : 

Harshad number is a number or an integer in base 10 which is completely divisible by sum of  its digits.

For better understanding let us consider an example.

Example :

  • Suppose a number 24 .
  • Calculate the sum of digits of the number (2 + 4) = 6 .
  • Check whether the number entered by user is completely divisible by sum of its digits or not.

Below are first few Harshad Numbers represented in base 10 :

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 18, 20………

In this article, we will create a java program to check whether the number entered by the user is Harshad number or not.

harshed or not in java

Working :

Step 1 : Ask the user to enter an integer.

Step 2 : Declare two variables, one for storing sum of digits and second for storing copy of the original number.

Step 3 : Use a while loop to perform continuous operations till the value of the integer do not becomes 0.

Step 4 : Use a statement to pick the last digit of the integer..

Step 5 : Perform addition and store the result in every iteration. 

Step 6 : Restore the integer value by removing last digit in every iteration of the loop.

Step 7 : Repeat the Steps from 3 to 6 till the integer value do not becomes 0.

Step 8 : Compare that whether the sum of digits of the integer is equal to the given integer or not.

  • If this gets true , then the given number is Harshad Number.
  • Else the number is not a Harshad Number. 

 

Harshad number or not in java

Code in Java :

Run 
//Java program to check whether a number is harshad number or not
// Online Java Compiler
// Use this editor to write, compile and run your Java code online

public class Main {
    public static void main(String[] args)
	{
		//make a copy of original number
		int n = 47;
		//declare a variable to store sum of digits
		int result = 0;
		//perform logic for calculating sum of digits of a number
		while(n != 0)
		{
			int pick_last = n % 10;
			result = result + pick_last;
			n = n / 10;
		}
		/*use condition to check whether the number entered by  
		user is completely divisible by its sum of digits or not*/
      if(n % result == 0)
      System.out.println("Harshad Number");
          else
        System.out.println("Not a Harshad Number");
}
}

Output :

Enter a number : 18
Harshad Number
Enter a number : 345
Not a Harshad Number

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7 comments on “Harshad number or not using Java”


  • siddeshaob2001

    public class Harshadnumber {

    public static void Harshad(int num)
    {
    int temp=num;
    int rem;
    int sum=0;
    while(num>0)
    {
    rem=num%10;
    sum=sum+rem;
    num=num/10;
    }
    if(temp%sum==0)
    {
    System.out.println(“is Harshad”);
    }
    else
    {
    System.out.println(“not”);
    }
    }
    public static void main(String[] args) {
    // TODO Auto-generated method stub
    int num=24;

    Harshad(num);
    }
    }

    0

  • Arunima

    import java.util.*;
    public class Main
    {
    public static void main(String[] args) {
    Scanner sc=new Scanner(System.in);
    int n=sc.nextInt();
    int sum=0,i,r,temp;
    temp=n;
    while(n!=0)
    {r=n%10;
    sum=sum+r;
    n=n/10;}
    if(temp%sum==0)
    System.out.println(“yesh”);
    else
    System.out.println(“not”);

    }}

    0

  • Soumen

    public class Main {
    public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int Num = sc.nextInt();
    int Sum = 0;
    int temp = Num;
    while (temp!=0){
    int rem = temp%10;
    Sum+=rem;
    temp/=10;
    }
    if(Num%Sum==0){
    System.out.println(Num+” “+”is a Harshad Number”);
    }
    else
    {
    System.out.println(Num+” “+”is not a Harshad Number”);
    }

    }

    }

    1

  • Harsh

    //Harshad Number: Number which is completely divisible by sum of its digits like 12 = 1+2 = 3 can divide 12
    import java.util.*;

    public class Main
    {
    public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int sum = 0;
    System.out.println(“Enter a no: “);
    int num = sc.nextInt();
    int n = num;
    while(n != 0){
    int rem = n%10;
    sum += rem; //summing the digits of given number
    n /= 10;
    }
    if(num % sum == 0) //checking if the no is divisible by sum or not
    System.out.println(“No. is Harshad”);
    else
    System.out.println(“Not a Harshad number”);
    }
    }

    0

    • Karri

      class HashatNumber
      {
      public static void main(String[] args)
      {
      int sln = 1;
      for(int num = 1;num<=100;num++)
      {
      int temp= num;
      int sum= 0;
      while(temp!=0)
      {
      int ld= temp%10;
      sum= sum+ld;
      temp= temp/10;
      }
      if(num%sum==0)
      {
      System.out.println(sln+") "+num);
      sln++;
      }
      }
      }
      }

      0

      • Karri

        class HashadNumber
        {
        public static void main(String[] args)
        {
        int sln = 1;
        for(int num = 1;num<=100;num++)
        {
        int temp= num;
        int sum= 0;
        while(temp!=0)
        {
        int ld= temp%10;
        sum= sum+ld;
        temp= temp/10;
        }
        if(num%sum==0)
        {
        System.out.println(sln+") "+num);
        sln++;
        }
        }
        }
        }

        0