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# Program to find the sum of numbers in a given range in C++

## Program to find the Sum of Numbers in a given range

Here we will discuss how to find the Sum of Natural Numbers in a range defined by user using c++ programming language.

All the positive integers (1, 2, 3, 4…) are the Natural Numbers.

To find the sum of N Natural Numbers we will use a simple loop with condition based on the range defined by the user.  ## Algorithm:-

1. Take two inputs.
2. Inputs are stored in two int type variable say lower_limit and upper_limit.
3. Initialize i to lower_limit
1. i=lower_limit
4. Initialize sum to 0
5. run a for loop till i is less than or equal to upper_limit, i<=upper_limit
1. update sum +=i
2. increment i by 1 in every iteration
6. sum is printed being the sum of Natural Numbers between lower_limit and upper_limit.

### C++ Code:-

//C++ Program
//Sum of Natural Numbers in a given range
#include<iostream>
using namespace std;
//main Program
int main()
{
int sum = 0 , upper_limitlower_limit;
cout << “Enter the lower limit: “;
cin >> lower_limit;

cout << “Enter the upper limit: “;
cin >> upper_limit;

//calculating sum of numbers in the given range
for(int i = lower_limiti <= upper_limiti++){
sum += i;
}

//printing output
cout<<“The Sum of Natural Numbers from “ << lower_limit << ” to “ << upper_limit << ” is “ << sum;
return 0;
}

### Output:-

Enter the lower limit: 19
Enter the upper limit: 65
The Sum of Natural Numbers from 19 to 65 is 1974 