Java Program to Check Leap Year or not

December 16, 2023

Check Whether or Not the Year is a Leap Year in Java

We will write Leap Year Program in Java. Given an integer input “year” the objective is to check if the given year is a leap year or not using the conditions for a leap year. Therefore, keeping them in mind we write a code to Check Whether or Not the Year is a Leap Year in Java Language.

Example
Input : 2024
Output: Leap Year

Check Whether or Not the Year is a Leap Year in Java

Given an integer input for the year, the objective is to check whether or not the user given input “year” is a Leap year or not. In order to do so we check if the integer input satisfies the conditions for a leap year mentioned below. Therefore, we write a Java code to check and tell if it’s a leap year or not. Some of the methods to check for leap year are mentioned below

  • Method 1: Using if-else Statements 1
  • Method 2: Using if-else Statements 2
  • Method 3: Using Ternary Operator
  • Method 4: Bonus Boolean method

We’ll discuss the above-mentioned methods in detail in the upcoming sections. Before we get to coding check the blue box below for better understanding.

Method 1: Using if-else Statements 1

Working

For the input integer “year” we perform the following

  • Check if the year variable is divisible by 400.
  • Check if the year variable is divisible by 4 but not by 100.
  • If the above conditions are satisfied, print it’s a Leap year. It’s not a Leap Year otherwise.

Let’s try and implement the above mentioned logic in Java Language.

Java Code

Run 
// Leap year program in Java
// If the year satisfies either of the conditions, it's considered a leap year -
// 1. The year must be divisible by 400.
// 2. The year must be divisible by 4 but not 100.
public class Main{
   public static void main (String[]args)
   {

     int year = 2020;

     if (year % 400 == 0)
       System.out.println (year + " is a Leap Year");

     else if (year % 4 == 0 && year % 100 != 0)
       System.out.println (year + " is a Leap Year");

     else
         System.out.println (year + " is not a Leap Year");

   }
 }

Output

2020 is a Leap Year
While loop in C

Greatest of two numbers

Greatest of the Three numbers

Prime number

Prime number within a given range

Sum of digits of a number

Method 2: Using if-else Statements 2

Working

For a given integer variable “year”, we check for the following

  • If the year variable is divisible by 400 or is it divisible by 4 but not 100.
  • Print it’s a Leap Year if true, Print it’s not a Leap year otherwise.

Let’s implement the above logic in Java Language.

Java Code

Run 
public class Main
 {
   public static void main (String[]args)
   {

     int year = 2020;

     if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0))
       System.out.println (year + " is a Leap Year");

     //not leap year
     else
         System.out.println (year + " is not a Leap Year");

   }
 }

Output

2020 is a Leap Year

Method 3: Using Ternary Operator

Working

In this method we’ll use the knowledge of ternary operators. To know more about ternary operators in C, check out Ternary operators in C.

For a given input integer variable “year”, we check for the following using the ternary operator

  • Check if the year variable is divisible by 400 or divisible by 4 but not 100.
  • If either of the above mentioned conditions are satisfied, print it’s a Leap Year. Print it’s not a Leap Year otherwise.

Let’s implement the above mentioned logic in Java Language.

Java Code

Run 
public class Main
{
  public static void main (String[]args)
  {

    int year = 2019;
    
     int flag = (year%400 == 0) || (year%4==0 && year%100!=0 ) ? 1 : 0;
    if (flag ==1)
    {
        System.out.println (year + " is a Leap Year");
    }
    else
    {
         System.out.println (year + " is not a Leap Year");
    }
  }
}

Output

2019 is not a Leap Year

Method 4: Bonus Boolean Method

Java Code

Run 
class Main {

    public static void main(String[] args) {

        // If the year satisfies either of the conditions, it's considered a leap year -
        // 1. The year must be divisible by 400.
        // 2. The year must be divisible by 4 but not 100.
        int year = 2020;
        boolean leap;

        if (year % 400 == 0)
            leap = true;

        else if (year % 4 == 0 && year % 100 != 0)
            leap = true;

        else
            leap = false;

        if (leap)
            System.out.println(year + " is a leap year.");
        else
            System.out.println(year + " is not a leap year.");
    }
}

Output

2020 is a Leap Year

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4 comments on “Java Program to Check Leap Year or not”


  • Srivalli Parre

    package pack1;

    import java.util.Scanner;

    public class ClassD
    {
    static Scanner sc=new Scanner(System.in);
    public static void main(String[] args)
    {
    System.out.println(“Enter the year”);
    int n1=sc.nextInt();
    String temp=(n1%4==0)?”leap year “: “not a leap year”;
    System.out.println(temp);
    }
    }

    0

  • Sornammal

    import java.util.Scanner;
    public class Main{
    public static void main(String [] args)
    {
    Scanner in=new Scanner(System.in);
    System.out.println(“enter the year: “);
    int year=in.nextInt();
    String leap=(((year%400==0) || (year%4==0 && year%100!=0)) && (year%400!=0)) ?”is leap year “: “is not leap year”;
    System.out.println(“year “+ year +” “+leap);
    }

    }

    2

  • Yatish

    package com.Yash.Practice.Basics;

    public class Program10 {
    public static void main(String[] args) {
    int Year = 2020;

    if (Year%4==0){
    System.out.println(Year+” is Leap Year”);
    }
    else {
    System.out.println(Year +” Not a Leap Year”);
    }
    }
    }

    0