# Find the Armstrong Numbers between Two Intervals using Python

## Find the Armstrong Number in a given Range in Python

Given two integers high and low for limits as inputs, the objective is to write a code to Find the Armstrong Numbers in a given Interval in C++.

```For Instance,
Input : 150 160
Output : 153```

## Find the Armstrong Numbers in a given Range in Python

Given two integer inputs as intervals high and low, the objective is to write a python code to check if the numbers lying within the given interval are Armstrong Numbers or not.

An Armstrong number or a Narcissistic number is any number that sums up itself when each of its digits is raised to the power of a total number of digits in the number. Let us try to understand this through the below example,

• abcd… = an + bn + cn + dn + …
• Where n is the order(length/digits in number)

Let’s look at some examples of Armstrong Numbers.

### Examples

Here are few examples that’ll help you to understand the concept better.

## Method 1

### Python Code

Run
```low, high = 10, 10000

for n in range(low, high + 1):

# order of number
order = len(str(n))

# initialize sum
sum = 0

temp = n
while temp > 0:
digit = temp % 10
sum += digit ** order
temp //= 10

if n == sum:
print(n, end=", ")
```

## Method 2

### Python Code

Run
```import math

first, second = 150, 10000

def is_Armstrong(val):
sum = 0

# this splits the val into its digits
# example val : 153 will become [1, 5, 3]
arr = [int(d) for d in str(val)]

# now we iterate on array items (digits)
# add these (digits raised to power of len i.e order) to sum
for i in range(0, len(arr)):
sum = sum + math.pow(arr[i], len(arr))

# if sum == val then its armstrong
if sum == val:
print(str(val) + ", ", end="")

for i in range(first, second + 1):
is_Armstrong(i)
```

### Output

`153, 370, 371, 407, 1634, 8208, 9474, `

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### 15 comments on “Find the Armstrong Numbers between Two Intervals using Python”

• Rithick

n=int(input(‘Number : ‘))
x=str(n)
p=len(x)
amstrong=0

for i in x:
amstrong+=int(i)**p
if n==amstrong:
print(“Amstrong”)
else:
print(“Not Amstrong”)

• Raghvendra Singh Shekhawat

lower_number = int(input(“Enter any positive number: “))
higher_number = int(input(“Enter any positive number: “))

for i in range(lower_number,higher_number+1):
sum = 0
length = len(str(i))
original = i

while i > 0:
digit = i % 10
sum += digit ** length
i = i // 10

if sum == original:
print (original ,end=”, “)