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0Check Whether a Number is Even or Odd in C++
Check Whether a Number is Even or Odd in C++
Given an integer input num, the objective is to write a code to Check Whether a Number is Even or Odd in C++. To do so we check if the number is divisible by 2 or not, it’s Even if it’s divisible otherwise Odd.
Example
Input : num = 12
Output : Even
Check Whether a Number is Even or Odd in C++
Given an integer input the objective is to write a C++ code to Check Whether a Number is Even or Odd. To do so the main idea is to divide the number by 2 and check if it’s divisible or not. It’s an Even number is it’s perfectly divisible by 2 or an Odd number otherwise.
Here are the Methods to solve the above mentioned problem,
- Method 1 : Using Brute Force
- Method 2 : Using Ternary Operator
- Method 3 : Using Bitwise Operators
Method 1 : Using Brute Force
This method simply checks if the given input integer is divisible by 2 or not. If it’s divisible then print Even or Odd otherwise.
C++ Code
#include <iostream>
using namespace std;
int main ()
{
int number;
cout << "Enter a number:"; cin >> number;
//checking whether the number is even or odd
if (number % 2 == 0)
cout << number << " : Even";
else
cout << number << " : Odd";
return 0;
}
Output
Enter a number: 4 24 : Even
Working
The working of the above code is mentioned below
- Input an integer input “number“
- Check whether the number is divisible by 2
- This means using modulo/remainder operator leaves 0 as a remainder
- Do : if (number % 2 == 0)
- if yes, print “Even number”
- if not, print “Odd number”
Method 2 : Using Ternary Operator
This Method uses the ternary operator to check if the integer input is divisible by 2, If true print Even or Odd otherwise.
C++ Code
#include <iostream>
namespace std;
int main ()
{
int number;
cout << "Enter a number:"; cin >> number;
//Checking if the number is divisible by 2
number % 2 == 0 ? cout << "Even":cout << "Odd";
return 0;
}
Output
Enter a number: 17 Odd
Working
The working of the above code is as follows,
- Input an integer input “number“
- Check whether the number is divisible by 2 using the ternary operator
- (number % 2) ? (cout <<“Even”) : (cout << “Odd”)
Method 3 : Using Bitwise Operator
This Method uses bitwise operators to check if a given number is Even or Odd.
C++ Code
#include <iostream>
using namespace std;
// Returns true if n is even, else odd
bool isEven(int number)
{
// n & 1 is 1, then odd, else even
return (!(number & 1));
}
// Driver code
int main()
{
int number;
cout << "Enter the number: "; cin >> number;
if(isEven(number))
cout << "Even";
else
cout << "Odd";
//below can also be used instead of if else conditions
//isEven(number)? cout << "Even" : cout << "Odd";
return 0;
}
Output
Enter a number: 13 Odd
Working
The working of the above code is as follows,
- If we have any number ‘n‘ doing bitwise ‘&‘ operation will give resultant as
- 1: If n is odd
- 0: if n is even
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