Find the Sum of the Numbers in a Given Range in Java

March 7, 2024

Find the Sum of the Numbers in a Given Range in Java

Given two integer inputs number1 and number2, the objective is to find the sum of all Number that lay in the given interval by writing a code to Find the Sum of the Numbers in a Given Range in Java Language.

Example
Input : Number1 = 12 , Number2 = 15
Output : 54

Find the Sum of the Numbers in a Given Interval in Java

Given the range as integer input, the objective is to find the Sum of all the Numbers that lay in the given interval using different methods. To do so we basically iterate from the base interval to the final interval and keep adding the number. Here are some of the methods to solve the above mentioned problem in Java Language.

Method 1: Using Brute Force
Method 2: Using the Formula
Method 3: Using Recursion

We’ll discuss the above mentioned methods in detail in the upcoming sections.

Greatest of two numbers

Greatest of the Three numbers

Leap year or not

Prime number

Prime number within a given range

Method 1: Using Brute Force

In this method we’ll use loops to iterate through from the base interval to the upper interval meanwhile adding all the numbers to the sum variable.

Working

For the given integer input intervals number1 and number2

Initialize the required variables.
Initiate a for loop from range [5,10].
Keep adding the value of the iter variable to sum variable.
Print the sum variable.

Let’s implement the above working in Java Language.

Java Code

public class Main
{
  public static void main (String[]args)
  {
    int a = 5;
    int b = 10;

    int sum = 0;

    for (int i = a; i <= b; i++)
        sum = sum + i;
      System.out.println ("The sum is " + sum);
  }
}

Output

The sum is 45

Method 2: Using the Formula

In this method we’ll use a sequence and series formula to find the sum of n numbers in a series. Formula : N*(N+1)/2.

Working

For the given integer input intervals number1 and number2

Initialize the required variables.
Apply the given formula sum = b*(b+1)/2 – a*(a+1)/2 + a.
Print the sum variable as output.

Let’s implement the above working in Java Language.

Java Code

public class Main
{
	public static void main(String[] args) {
	    int num1 = 2;
	    int num2 = 5;
	    int sum = num2*(num2+1)/2 - num1*(num1+1)/2 + num1;
		System.out.println("The Sum is "+ sum);
	}
}

Output

The Sum is 14

Method 3: Using Recursion

In this method we’ll use recursion to iterate through and sum up all the numbers that lay in the given interval.

Working

For the Integer inputs number1 and number2

Initialize the required variable sum = 0.
Define a recursive function with base case as number1 == number2.
Set the recursive set call as num1+ function(sum,num1+1,num2).
print the returned value after calling the recursive functions.

Let’s implement the working in Java Language.

Java Code

public class Main
{
  public static void main (String[]args)
  {
    int a = 5;
    int b = 10;

    int sum = getSum (0, a, b);
      System.out.println ("The sum is " + sum);
  }


  static int getSum (int sum, int i, int b)
  {

    // stop when any recursion call tries to go over b (larger number)
    if (i > b)
      return sum;

    return i + getSum (sum, i + 1, b);
  }
}

Output

The Sum is 45

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ASCII Table
Positive or Negative number: C | C++ | Java | Python
Even or Odd number: C | C++ | Java | Python
Sum of First N Natural numbers: C | C++ | Java | Python
Sum of N natural numbers: C | C++ | Java | Python
Sum of numbers in a given range: C | C++ | Java | Python
Greatest of two numbers: C | C++ | Java | Python
Greatest of the Three numbers: C | C++ | Java | Python
Leap year or not: C | C++ | Java | Python
Prime number: C | C++ | Java | Python
Prime number within a given range: C | C++ | Java | Python
Sum of digits of a number: C | C++ | Java | Python
Reverse of a number : C | C++ | Java | Python
Palindrome number: C | C++ | Java | Python
Armstrong number : C | C++ | Java | Python
Armstrong number in a given range : C | C++ | Java | Python
Fibonacci Series upto nth term : C | C++ | Java | Python
Find the Nth Term of the Fibonacci Series : C | C++ | Java | Python
Factorial of a number : C | C++ | Java | Python
Power of a number : C | C++ | Java | Python
Factor of a number : C | C++ | Java | Python
Finding Prime Factors of a number : C | C++ | Java | Python
Strong number : C | C++ | Java | Python
Perfect number : C | C++ | Java | Python
Automorphic number : C | C++ | Java | Python
Harshad number : C | C++ | Java | Python
Abundant number : C| C++ | Java | Python
Friendly pair : C | C++ | Java | Python

One comment on “Find the Sum of the Numbers in a Given Range in Java”

Gyanendra
import java.util.*;

public class Main
{
public static void main(String[] args) {
Scanner scn=new Scanner(System.in);
int n1=scn.nextInt();
int n2=scn.nextInt();
int sum=ans(n1,n2);

System.out.println(sum);
}

public static int ans(int n1,int n2){
if(n1==n2){
return n1;
}

int ans=ans(n1+1,n2);
ans+=n1;

return ans;
}
}

1

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