# C Program Armstrong Numbers Between Two Intervals

## Armstrong numbers between two intervals:-

To identify the Armstrong number between two intervals in C programming, the user is required to insert integer numbers. A n digit number is known as an Armstrong number, when the sum of the values of the digits raised to nth power is equal to the number itself. For example: 153 = 13+53+33=153

Ex:- basically we know that Armstrong number in given range 0 to 999  are 1 2 3 4 5 6 7 8 9 153 370 371 407. ### Working:-

Step 1: Start

Step 2: Insert the start and end value

Step 3: Repeat from I = start value to end value

Step 4: Repeat the process until the temporary number is not equal to 0.

Step 5: Remainder = temp%0

Step 6: The result should be equal to result plus the power (remainder n).

Step 7: temp = temp/10

Step 8: If the value of the result is equals to the value of number then print the number

Step 9: Else repeat the steps until the end number is encountered.

Step 10: Stop ### C Program:-

```#include<stdio.h>
int main()
{
//For initializing variables
int start, end, i, temp1, temp2, rem, n = 0, result = 0;
//user give start and end point of a number
printf("Insert the start value and end value :");
scanf("%d %d", &start, &end);

//to display pint of range
printf("\n Armstrong nums between %d an %d are: ", start, end);

//for use this loop to store all number in given range
for(i = start + 1; i < end; ++i)
{
//store a duplicity value of given range
temp2 = i;
temp1 = i;

while (temp1 != 0)
{
//temp1 /= 10;
temp1=temp1/10;
++n;
}
while (temp2 != 0)
{
rem = temp2 % 10;
//result += pow(rem, n);
result=result+pow(rem,n);
//temp2 /= 10;
temp2=temp2/10;
}
//check true condition if result is equal to i
if (result == i)
{
//display
printf("%d ", i);
}
n = 0;
result = 0;
}
printf("\n");
return 0;
}```

### Output:

```Insert the start value and end value: 100, 500
Armstrong numbers between 100 and 500 are: 370, 371, 407.``` 