Python Program to Check Whether a Number is Even or Odd

September 27, 2022

Check Whether a Number is Even or Odd in Python

Given an integer input num, the objective is to write a code to Check Whether a Number is Even or Odd in Python. To do so we check if the number is divisible by 2 or not, it’s Even if it’s divisible otherwise Odd.

Example 
Input : num = 3
Output : Odd

Check Whether a Number is Even or Odd in Python

Given an integer input the objective is to write a Python code to Check Whether a Number is Even or Odd. To do so the main idea is to divide the number by 2 and check if it’s divisible or not. It’s an Even number is it’s perfectly divisible by 2 or an Odd number otherwise.

Here are the Methods to solve the above mentioned problem,

Method 1 : Using Brute Force
Method 2 : Using Ternary Operator
Method 3 : Using Bitwise Operators

We’ll discuss the above mentioned methods in detail in the next section.

Sum of First N Natural numbers

Sum of N natural numbers

Sum of numbers in a given range

Greatest of two numbers

Greatest of the Three numbers

Method 1 : Using Brute Force

This method simply checks if the given input integer is divisible by 2 or not. If it’s divisible then print Even or Odd otherwise.

Python Code

Run

num = int(input("Enter a Number:")) 
if num % 2 == 0: 
  print("Given number is Even") 
else: 
  print("Given number is Odd")

Output

Enter a Number: 5 
Given number is Odd

Working

The working of the above mentioned code is as follows,

Start
Insert a number.
If the given number is divisible by 2, then print,” Given number is even”.
If the given number is not divisible by 2, then print ,”Given number is odd”.
Stop

Explanation

Given an integer as input, the objective is check whether the number is even or odd in Python. To do so we check if it’s divisible by 2 or not. If true, it’s even or it’s odd otherwise.

The algorithm for the above code is as given below,

Import the required modules using import keyword.
Initialize the required variables.
Check if the number is divisible by 2, if true print even or odd otherwise using print() function.

The output for the above code is wither even or odd based on whether or not it’s divisible by 2.

Method 2 : Using Ternary Operator

This Method uses the ternary operator to check if the integer input is divisible by 2, If true print Even or Odd otherwise.

Ternary Operator Syntax Python ( True : Action ) if ( Condition ) else ( False : Action )

Python Code

Run

num = 17
print("Even") if num%2 == 0 else print("Odd")

Output

Odd

Working

The working of the above code is as follows,

Input an integer input num.
Check whether the number is divisible by 2 using the ternary operator
Ternary Operation, print(“Even”) if (num%2 == 0) else (print(“Odd”))

Explanation

Given an integer as input, the objective is check whether the number is even or odd in Python. To do so we check if it’s divisible by 2 or not using a Ternary Operator in Python. If true, it’s even or it’s odd otherwise.

The algorithm for the above code is as given below,

import the required modules using import keyword.
Initialize the required variables.
Check if the number is divisible by 2 using a Ternary Operator, if true print even or odd otherwise using print() function.

The output for the above code is wither even or odd based on whether or not it’s divisible by 2.

Method 3 : Using Bitwise Operator

This Method uses bitwise operators to check if a given number is Even or Odd.

Bitwise Operators In computer programming, a bitwise operation operates on a bit string, a bit array or a binary numeral at the level of its individual bits. It is a fast and simple action, basic to the higher-level arithmetic operations and directly supported by the processor.

Python Code

Run

def isEven(num):
  return not num&1

if __name__ == "__main__":
  num = 13
  if isEven(num):
    print('Even')
  else:
    print('Odd')

Output

Odd

Working

The working of the above code is as follows,

If we have any number num doing bitwise ‘&‘ operation will give resultant as
- 1: If n is odd
- 0: if n is even

Explanation

Given an integer as input, the objective is check whether the number is even or odd in Python. To do so we check if it’s divisible by 2 or not using Bitwise Operator. If true, it’s even or it’s odd otherwise.

The algorithm for the above code is as given below,

Import the required modules using import keyword.
Define a function isEven() which returns a boolean variable to check if the number is even or odd.
Initialize the required variables.
Check if the function after calling returns True or False, if true print even or odd otherwise using print() function.

The output for the above code is wither even or odd based on whether or not it’s divisible by 2.

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ASCII Table
Positive or Negative number: C | C++ | Java | Python
Even or Odd number: C | C++ | Java | Python
Sum of First N Natural numbers: C | C++ | Java | Python
Sum of N natural numbers: C | C++ | Java | Python
Sum of numbers in a given range: C | C++ | Java | Python
Greatest of two numbers: C | C++ | Java | Python
Greatest of the Three numbers: C | C++ | Java | Python
Leap year or not: C | C++ | Java | Python
Prime number: C | C++ | Java | Python
Prime number within a given range: C | C++ | Java | Python
Sum of digits of a number: C | C++ | Java | Python
Reverse of a number : C | C++ | Java | Python
Palindrome number: C | C++ | Java | Python
Armstrong number : C | C++ | Java | Python
Armstrong number in a given range : C | C++ | Java | Python
Fibonacci Series upto nth term : C | C++ | Java | Python
Find the Nth Term of the Fibonacci Series : C | C++ | Java | Python
Factorial of a number : C | C++ | Java | Python
Power of a number : C | C++ | Java | Python
Factor of a number : C | C++ | Java | Python
Finding Prime Factors of a number : C | C++ | Java | Python
Strong number : C | C++ | Java | Python
Perfect number : C | C++ | Java | Python
Automorphic number : C | C++ | Java | Python
Harshad number : C | C++ | Java | Python
Abundant number : C| C++ | Java | Python
Friendly pair : C | C++ | Java | Python

9 comments on “Python Program to Check Whether a Number is Even or Odd”

Raghvendra Singh Shekhawat
number = int(input(“Enter the number: “))

if number % 2 == 0:
print(f”{number} is even”)
elif number % 2 != 0:
print(f”{number} is odd”)

0

Log in to Reply
aparna232000
n = int (input(“enter a number:”))
if n%2=0:
print(“given number is even”)
else:
print(“given number is odd”)

1

Log in to Reply
Kiran
num=int(input(“enter a number”))
if num%2==0:
print(“The number is even”)
else:
print(“the number is odd”)

1

Log in to Reply
Sangisetty
#user input
n = int(input(‘Enter your number:’))

#function declaration
def EvenOrOdd(n):
if(n%2==0):
print(‘Even number’)
else:
print(‘Odd number’)

#function calling
EvenOrOdd(2)
#output
even number

2

Log in to Reply
Raaz
a = int(input(“Enter The Number To Find:\n”))
if a%2==0:
print(“The Number Is Even”)
else:
print(“The Number Is odd”)

2

Log in to Reply
rohitnamdev876
n = int(input(“Enter the number for check : “))
if n%2== 0:
print(“Number is Even “)
else:
print(“Number is Odd “)

0

Log in to Reply
M
num=int(input(“enter the number:”))
if num%2 == 0:
print(str(num) + ” num is even”)
else:
print(str(num) + ” num is odd”)

0

Log in to Reply
18-513
numb = int(input(“Enter the Number: “))

if numb % 2 == 0:
print(f”Number {numb} is Even Number”)

else:
print(f”Number {numb} is Odd Number”)

0

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Jagruti Yuvraj Dhangar
I =int(input (‘enter the no: ‘)
if(&1):
Print(“odd”)
Else:
Print(“even”)

0

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