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0Armstrong Numbers between Two Intervals using Java
Find the Armstrong Numbers in a given Interval in Java
Given two integers high and low for limits as inputs, the objective is to write a code to Find the Armstrong Numbers in a given Interval in Java.
Example
Input : 10 1000
Output : 153 370 371 407
Find the Armstrong Numbers in a given Range using Java
Given two integer inputs as high and low, the objective is to find all the Armstrong Numbers that falls under the limits [Low,High] interval. Before Going into the Explanation let’s understand the problem and the definition of Armstrong Numbers.
Armstrong Number
In number theory, an Armstrong number or a Narcissistic number in a given number base b is a number that is the sum of its own digits each raised to the power of the number of digits.
A number is an Armstrong Number if and only if it can be represented in the following form,
A number is an Armstrong Number if and only if it can be represented in the following form,
abcd...nth = pow(a,n) + pow(b,n) + pow(c,n) + pow(d,n) + .... pow(nth,n)Here are some example to understand the definition
Example 1 Input : 120 Output : No 120 is not a Armstrong number. 1*1*1 + 2*2*2 + 0*0*0 = 9 Example 2 Input : 1253 Output : No 1253 is not a Armstrong Number 1*1*1*1 + 2*2*2*2 + 5*5*5*5 + 3*3*3*3 = 723
From the above explanation we gather that to check if a number is it must be represented in the above stated equation. We then check
Java Code
Method 1
This is a simple iterative method to find all Armstrong numbers between two ranges –
Run
//Java program to print armstrong numbers between two intervals
import java.util.Scanner;
public class LearnCoding2
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
System.out.print("Enter lower and upper ranges : ");
int low = sc.nextInt();
int high = sc.nextInt();
System.out.println("Armstrong numbers between "+ low + " and " + high + " are : ");
// loop for finding and printing all armstrong numbers between given range
for(int num = low ; num <= high ; num++)
{
int sum = 0, temp, digit, len;
len = getOrder(num);
temp = num;
// loop to extract digit, find ordered power of digits & add to sum
while(temp != 0)
{
// extract digit
digit = temp % 10;
// add power to sum
sum = sum + (int) Math.pow(digit,len);
temp /= 10;
};
if(sum == num)
System.out.print(num + " ");
}
}
private static int getOrder(int num) {
int len = 0;
while (num!=0)
{
len++;
num = num/10;
}
return len;
}
}Output
Enter lower and upper ranges : 1 1000 Armstrong numbers between 1 and 1000 are : 1 2 3 4 5 6 7 8 9 153 370 371 407
Working
Working of the above code is given below –
- Ask the user to enter two ranges, one starting range and the second ending range.
- Use a loop to find all Armstrong numbers between starting range and ending range.
- Use the logic for checking number is Armstrong or not for every number between the given range and then display the result.
Method 2 (Recursive)
This method uses a recursive approach to find Armstrong sum. You can check recursion in Java here
Run
import java.util.Scanner;
public class LearnCoding2
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
System.out.print("Enter lower and upper ranges : ");
int low = sc.nextInt();
int high = sc.nextInt();
System.out.println("Armstrong numbers between "+ low + " and " + high + " are : ");
// loop for finding and printing all armstrong numbers between given range
for(int num = low ; num <= high ; num++)
{
int len = getOrder(num);
if(num == getArmstrongSum(num, len))
System.out.print(num + " ");
}
}
private static int getOrder(int num) {
int len = 0;
while (num!=0)
{
len++;
num = num/10;
}
return len;
}
private static int getArmstrongSum(int num, int order) {
if(num == 0)
return 0;
int digit = num % 10;
return (int) Math.pow(digit, order) + getArmstrongSum(num/10, order);
}
}
Output
Enter lower and upper ranges : 1 1000 Armstrong numbers between 1 and 1000 are : 1 2 3 4 5 6 7 8 9 153 370 371 407
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public class Main
{
public static void main(String[] args)
{
int c=0;
int s=0;
for(int i=1; i<=1000; i++)
{
if(amstrong(i))
{
System.out.print(i+" ");
c++;
s=s+i;
}
}
System.out.println();
System.out.println("Sum :"+s);
System.out.println("Count :"+c);
System.out.println("Avg :"+s/c);
}
public static boolean amstrong(int n)
{
int s=0;
int n1=n;
while(n!=0)
{
int d=n%10;
s=s+(d*d*d);
n=n/10;
}
return n1==s;
}
}
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public class Main
{
public static void main(String[] args) {
//Armstrong number in a given range :
int start=1;
int end =500;
for(int i=start;i<=end;i++)
{
if(amstrong(i))
{
System.out.println(i);
}
}
}
static boolean amstrong(int n)
{
int original=n;
int sum=0;
int digit=digits(n);
while(n!=0)
{
int rem=n%10;
sum += (int) Math.pow(rem,digit);
n=n/10;
}
return sum==original;
}
static int digits(int n)
{
int count =0;
while (n!=0)
{
count++;
n=n/10;
}
return count;
}
}
import java.util.Scanner;
public class ArmstrongBetweenTwoNumbers {
public static void main(String args[]){
int num1, num2;
Scanner sc = new Scanner(System.in);
System.out.println(“Enter the first number ::”);
num1 = sc.nextInt();
System.out.println(“Enter the second number ::”);
num2 = sc.nextInt();
for (int i = num1; i<num2; i++){
int check, rem, sum = 0;
check = i;
while(check != 0) {
rem = check % 10;
sum = sum + (rem * rem * rem);
check = check / 10;
}
if(sum == i){
System.out.println(""+i+" is an Armstrong number.");
}
}
}
Class sd{public static void main (String []args){
int n1,n2,last,total,n,rem;
System.out.println(” enter a first no”);
Scanner s= new Scanner (System.in);
n1=s.nextInt();
System.out.println(” enter a second no”);
n2= s.nextInt();
for(int i= n1; i0){
rem=n%10;
last=last+(rem*rem*rem);
n=n/10;
}
if(total==last){
System.out.println(last);
}}}
package ppjava;
import java.util.*;
public class ArmSeries {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println(“Enter start no: “);
int s = sc.nextInt();
System.out.println(“Enter second no: “);
int l = sc.nextInt();
int r=0;
for(;s0) {
int d= a%10;
r= r+(d*d*d);
a=a/10;
}
if(r==s) {
System.out.println(s);
}
}
sc.close();
}
}
for(int i = start ; i <= end ; i++)
{
n = i;
int length=String.valueOf(i).length();
sum = 0;
//logic for checking number is armstrong or not
while(n != 0)
{
int pick_last = n % 10;
sum = sum + Math.pow(pick_last, length);
n = n / 10;
}
if(sum == i)
System.out.println(i);
}