C++ Program to find the Reverse of a Number

July 4, 2019

Program to find the Reverse of a Number

Here we will discuss how to find the reverse of a given number using C++ programming

language.

To find the reverse of a number we will use loop and arithmetic operators(%, / ).

Let’s take an example for example:

When a number say 87201 is given as an input then its output or we can say its reverse

will be 10278.

Working

Let’s see how the code works

The user gives an input.
The input will be stored in an int type variable say num
A do while loop is started
- Modulus(%) of num is founded with 10 and stored in an int type variable say rem.

rem=num%10;

- An int variable reverse(initialised at 0) is multiplied by 10 and rem is added to it and the result is stored in reverse itself.

reverse=reverse*10+rem;

- num is divided by 10 and the value is stored in num itself.

num/=10;

- The loop works until num is not equal to 0.

while(num!=0);

reverse is printed as output as it is the reverse of the number entered by the user.

C++ Code

//C++ Program
//Reverse of a number
#include <iostream>  
using namespace std;  
//main program
int main()  
{  
    //variables initialization
    int num, reverse=0, rem;    
    cout<<"Enter a number: ";    
    //user input
    cin>>num;    
    //loop to find reverse number
    do    
    {    
        rem=num%10;      
        reverse=reverse*10+rem;    
        num/=10;    
    }while(num!=0);   
    //output
    cout<<"Reversed Number: "<<reverse;     
return 0;  
}

Output

Enter a number: 1098
Reversed Number: 8901

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