Check if a Year is a Leap Year or Not in Python

September 28, 2022

Check if a Year is a Leap Year or Not in Python

Given an integer input year, the objective of the code is to Check if a Year is a Leap Year or Not in Python Language. To do so we’ll check if the year input satisfies either of the two conditions of leap year.

Example
Input : 2020
Output : It's a Leap Year.

Check Whether a Year is a Leap Year or Not in Python

Given an integer input as the year, the objective is to Check if a Year is a Leap Year or Not in Python Language. To do so we’ll check each condition mentioned below in the blue box. It either of the conditions is satisfied, the year is a leap year. It’s not otherwise. Here are some methods to check whether or not it’s a leap year

Method 1: Using if-else statements 1
Method 2: Using if-else statements 2

We’ll discuss all the above mentioned methods in detail in the upcoming sections. Before going for the approach read out the blue box below for better understanding of the concept.

Conditions for a Leap Year Here are the two conditions that any year must satisfy to be called a leap year
1. The year must be perfectly divisible by 400.
2. The number must be divisible by 4 but not by 100.

Greatest of two numbers

Greatest of the Three numbers

Prime number

Prime number within a given range

Sum of digits of a number

Method 1: Using if-else Statements 1

In this method we’ll use the if-else statements to check whether or not the input integer satisfies either of the conditions. To learn more about control statements in python, check out if-else control statements in Python.

Working

For a User Input year we do

Check if the year variable is divisible by 400.
Check if the year variable is divisible only by 4 and not 100.
If the above mentioned conditions are satisfied, prints “Leap Year”, print “Not a Leap Year” otherwise.

Let’s implement the above logic in Python Language.

Python Code

Run

year = 2000
if (year%400 == 0) or (year%4==0 and year%100!=0):
  print("Leap Year")
else:
  print("Not a Leap Year")

Output

Leap Year

Method 2: Using if-else Statements 2

In this method we’ll use the if-else statements to check whether or not the input integer satisfies either of the conditions. This method is a modified and simpler version of the previous method.

Working

For a User Input year we do

The input is stored in an int type variable say year.
year is checked for being a leap year or not with the following condition if( ((year % 4 == 0)&&(year % 100 != 0)) || (year % 400==0) )
If the above condition is true then input is a leap year otherwise input is not a leap year.

Let’s implement the above logic in Python Language.

Python Code

Run

year = 2000
if( ((year % 4 == 0) and (year % 100 != 0)) or (year % 400==0) ):
    print("Leap Year")
else:
    print("Not leap Year")

Output:

Leap Year

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36 comments on “Check if a Year is a Leap Year or Not in Python”

MAITHREYI
year=int(input())
if (year%400==0):
print(“Leap Year”)
elif(year%4==0 and year%100!=0):
print(“Leap Year”)
else:
print(“Not Leap Year”)

1

Log in to Reply
Ganesh
# Write your code
year = int(input(‘enter year:’))
if year% 4 == 0:
print(year, ‘is a leap year’)
else:
print(year, ‘is not a leap year’)

5

Log in to Reply
Abhishek
year=int(input())
if year%4==0:
if year%100==0:
if year%400==0:
print(“yes it is leap year”)
else:
print(“NO it is not leap year”)
else:
print(“yes it is leap year”)
else:
print(“NO it is not leap year”)

1

Log in to Reply
Bibhudutta
a=int(input())

if(a%4==0 and a%100!=0) or (a%400==0 and a%100==0):
print(a,’ is a leap year’)
else:
print(“Not a leap year”)

0

Log in to Reply
Amol
#Please check this one hacker rank proven
year=int(input(“Enter the year:”))

if (year%4==0) or (year%100==0 and year%400==0):
print(“Yes {} is leap year”.format(year))
else:
print(“No,{} is not leap year”.format(year))

0

Log in to Reply
Abhishek
year = int(input(“ENTER THE YEAR:— “))
if year % 4 == 0:
if year % 100 == 0:
if year % 400 == 0:
print(” {0} YEAR IS A LEAP YEAR “.format(year))
else:
print(“THIS IS NOT A LEAP YEAR”)
else:
print(“THIS IS A LEAP YEAR”)
else:
print(“THIS IS NOT A LEAP YEAR”)

0

Log in to Reply
Poonam
n=int(input(“Enter the year:”))
if n%4==0 and n%100==0 and n%400==0:
print(“Leap year”)
else:
print(“Not leap year”)

0

Log in to Reply
ankush
x = int(input())
if x % 100 == 0:
if x % 400 == 0:
print(“{} is leap year”.format(x))
else:
print(“{} is not leap year”.format(x))
if x % 100 != 0:
if x % 4 == 0:
print(“{} is leap year”.format(x))
else:
print(“{} is not leap year”.format(x))

0

Log in to Reply
Sonal
year=int(input(“Enter the year “))
if(year%4==0 and year%100!=0) or (year%400==0):
print(year,”is a leap year”)
else:
print(year,”is not a leap year”)

0

Log in to Reply