Leap Year Program in Python

August 11, 2023

Check if a Year is a Leap Year or Not in Python

Given an integer input year, the objective of the code is to Check if a Year is a Leap Year or Not in Python Language. To do so we’ll check if the year input satisfies either of the two conditions of leap year.

Example
Input : 2020
Output : It's a Leap Year.

Check Whether a Year is a Leap Year or Not in Python

Given an integer input as the year, the objective is to Check if a Year is a Leap Year or Not in Python Language. To do so we’ll check each condition mentioned below in the blue box. It either of the conditions is satisfied, the year is a leap year. It’s not otherwise. Here are some methods to check whether or not it’s a leap year

Method 1: Using if-else statements 1
Method 2: Using if-else statements 2
Method 3 : Using Ternary Operator
Method 4 : Using Calendar Mode
Method 5 : Using Lamda Function

We’ll discuss all the above mentioned methods in detail in the upcoming sections. Before going for the approach read out the blue box below for better understanding of the concept.

Conditions for a Leap Year Here are the two conditions that any year must satisfy to be called a leap year
1. The year must be perfectly divisible by 400.
2. The number must be divisible by 4 but not by 100.

Greatest of two numbers

Greatest of the Three numbers

Prime number

Prime number within a given range

Sum of digits of a number

Method 1: Using if-else Statements 1

In this method we’ll use the if-else statements to check whether or not the input integer satisfies either of the conditions. To learn more about control statements in python, check out if-else control statements in Python.

Working

For a User Input year we do

Check if the year variable is divisible by 400.
Check if the year variable is divisible only by 4 and not 100.
If the above mentioned conditions are satisfied, prints “Leap Year”, print “Not a Leap Year” otherwise.

Let’s implement the above logic in Python Language.

Python Code

Run

year = 2000

if (year%400 == 0) or (year%4==0 and year%100!=0):
    print("Leap Year")
else:
    print("Not a Leap Year")

Output

Leap Year

Method 2: Using if-else Statements 2

In this method we’ll use the if-else statements to check whether or not the input integer satisfies either of the conditions. This method is a modified and simpler version of the previous method.

Working

For a User Input year we do

The input is stored in an int type variable say year.
year is checked for being a leap year or not with the following condition if( ((year % 4 == 0)&&(year % 100 != 0)) || (year % 400==0) )
If the above condition is true then input is a leap year otherwise input is not a leap year.

Let’s implement the above logic in Python Language.

Python Code

Run

year = 2000
if( ((year % 4 == 0) and (year % 100 != 0)) or (year % 400==0) ):
    print("Leap Year")
else:
    print("Not leap Year")

Output:

Leap Year

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Method 3: Using Ternary Operator

In this method we’ll use ternary operator in Python

Python Code

Run

def check_leap(year): 
    return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) 

year = int(input("Enter a year: ")) 

print(f"{year} is leap year" if check_leap(year) else f"{year} is not leap year")

Method 4: Using Calendar Module

In this method we’ll use calendar mode in python

Python Code

Run

import calendar

year = int(input("Enter a year: "))

if calendar.isleap(year):
    print(year, " is a leap year")
else:
    print(year, "is not a leap year.")

Python Code

Method 5: Using Lamda Function

In this method we’ll use lamda function in python

Run

is_leap_year = lambda year: (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)

year = int(input("Enter a year: "))

if is_leap_year(year):
    print(year, " is a leap year")
else:
    print(year, "is not a leap year.")

Positive or Negative number: C | C++ | Java | Python
Even or Odd number: C | C++ | Java | Python
Sum of First N Natural numbers: C | C++ | Java | Python
Sum of N natural numbers: C | C++ | Java | Python
Sum of numbers in a given range: C | C++ | Java | Python
Greatest of two numbers: C | C++ | Java | Python
Greatest of the Three numbers: C | C++ | Java | Python
Leap year or not: C | C++ | Java | Python
Prime number: C | C++ | Java | Python
Prime number within a given range: C | C++ | Java | Python
Sum of digits of a number: C | C++ | Java | Python
Reverse of a number : C | C++ | Java | Python
Palindrome number: C | C++ | Java | Python
Armstrong number : C | C++ | Java | Python
Armstrong number in a given range : C | C++ | Java | Python
Fibonacci Series upto nth term : C | C++ | Java | Python
Find the Nth Term of the Fibonacci Series : C | C++ | Java | Python
Factorial of a number : C | C++ | Java | Python
Power of a number : C | C++ | Java | Python
Factor of a number : C | C++ | Java | Python
Strong number : C | C++ | Java | Python
Perfect number : C | C++ | Java | Python
Automorphic number : C | C++ | Java | Python
Harshad number : C | C++ | Java | Python
Abundant number : C| C++ | Java | Python
Friendly pair : C | C++ | Java | Python

38 comments on “Leap Year Program in Python”

M
year = int(input(“enter the year:”))
if (year % 4 == 0 and year % 400 != 0)or(year % 400 == 0):
print(“yes {} is leap year”.format(year))
else:
print(“no {} is not a leap year”.format(year))

0

Log in to Reply
murali
import calendar
year = int(input(“enter the year”))
if (calendar.isleap(year)):
print(“{} is leap year”.format(year))
else:
print(“{} not a leap year”.format(year))

0

Log in to Reply
bhaskar
year=int(input(“Enter year”))
if(year%4==0 and year!=100) or year%400==0:
print(“leap year”)
else:
print(“not a leap year”)

0

Log in to Reply
18131a0437
year=int(input())
if year%4==0:
if year%400==0 or year%100!=0:
print(year,’is Leap Year’)
else:
print(year,’is not a Leap Year’)
else:
print(year,’is not a Leap Year’)

0

Log in to Reply
Neha
y=int(input())
if(y%4==0 and y%100==0 or y%400==0):
print(“yes {} is a leap year”.format(y))

else:
print(“no {} is not a leap year”.format(y))

0

Log in to Reply
Mancy
Can be made more simple:
year = int(input(“Enter the year: “))
if year % 4 == 0 and year % 100 != 0 or year % 400 == 0:
print(“{} is leap year”.format(year))
else:
print(“{} is not leap year”.format(year))

0

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rohith
year=int(input(“enter year”))
if(year%4==0 and year%100!=0 or year%400==0):
print(“leap year”)
else:
print(“not leap year”)

0

Log in to Reply
Samiksha
year = int(input(“enter the year: “))

if year % 4 == 0:
if year % 100 != 0:
print(“Leap Year”)
else:
if year % 400 != 0:
print(“Leap Year”)

else:
print(“Not a Leap Year”)

0

Log in to Reply
gaurav
more shorter:

year = int(input(“enter year: “))
if (year % 4) == 0:
if (year % 400):
print(“non-leap year”)
exit()
print(“leap year”)
else:
print(“Non-leap year”)

1

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premkumar
def leapyear(year):
import calendar
return (calendar.isleap(year))

year = int(input())
if (leapyear(year)):
print(“Leap Year”)
else:
print(“Not a Leap Year”)

1

Log in to Reply
pavan
easy one:
Bhavantik Correct one:
year = int(input(“Enter a Year: “))
if year%4 == 0:
if year%100==0 and year%400 !=0:
print(year,” is not a Leap Year”)
else:
print(year,” is Leap Year”)
else:
print(year,” is not a Leap Year”)

1

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pavan
year=int(input(“Enter the year”))
if(year%4==0):
print(“Leap year”)
elif(year%4==0 and year%100!=0):
print(“leap year”)
elif(year%100==0 and year%400!=0):
print(“LEap year”)
else:
print(“not a leap year”)

0

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Yashi
year = int(input(“Enter Year:”))
if year % 4 == 0:
if year % 100 == 0 and year%400 !=0:
print(“No, {} is not a Leap Year”.format(year))
else:
print(“Yes, {} is Leap Year”.format(year))
else:
print(“No, {} is not a Leap Year”.format(year))

0

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