Power of a number using Java

May 18, 2022

factorial of number using java

Find the Power of a Number in Java

Given two integer inputs as number and the power, the objective is to raise the number to a power given. Therefore, we’ll write a Code to Find the Power of a Number in Java Language.

Example
Input : 2 3
Output : 8

Find the Power of a Number in Java Language

Given two integers as the number and power inputs, the objective is to raise the number input to the power input and print the value. To do so we’ll use the concepts of loops and recursion. Here are few methods to Find the Power of a Number in Java Language,

  • Method 1: Without While Loop
  • Method 2: With While Loop

We’ll discuss the above mentioned methods in depth in the upcoming sections.

Method 1: Without While Loop

Java Code

Run 
public class Main
 {
 	public static void main(String[] args) {
	    
 	double base = 1.5;
     double expo1 = 2.5;
     double expo2 = -2.5;
     double res1, res2;
    
     // calculates the power
     res1 = Math.pow(base, expo1);
     res2 = Math.pow(base, expo2);
 	System.out.println(base + " ^ " + expo1 + " = " + res1 );
 	System.out.println(base + " ^ " + expo2 + " = " + res2 );
 	}
 }

Output

2.0 ^ 2.0 = 4.0

Method 2: With While Loop

Java Code

Run 
public class Main
{
	public static void main(String[] args) {
	    
	double base = 1.5;
    // Works only when exponent is positive integer
    int expo = 2;
    double res = 1.0;
    
    while (expo != 0) {
        res *= base;
        expo--;
    }
    
    System.out.println("Result = " + res); 
	}
}

Output

Result = 2.25

13 comments on “Power of a number using Java”


  • ppal7191

    public class PowerOfNumber {
    public static void main(String[] args) {

    int num = 2;
    int power = 4;
    int ans = 1;

    if (num == 0 && power == 1) {
    System.out.println(“The power of number ” + num + ” to the power ” + power + ” is 1″);
    } else if (num >= 0 && power == 0) {
    System.out.println(“The power of number ” + num + ” to the power ” + power + ” is 1″);
    } else if (num >= 0 && power == 1) {
    System.out.println(“The power of number ” + num + ” to the power ” + power + ” is ” + num);
    } else if (num == 0 && power == 0) {
    System.out.println(“The power of number ” + num + ” to the power ” + power + ” is indeterminate”);
    } else {

    for (int i = 1; i <= power; i++) {
    ans *= num;
    }
    System.out.println("The power of number " + num + " to the power " + power + " is " + ans);
    }

    }
    }

    The above code also checks the power of number like 0 and 1 …


  • arman22shaikh

    package Numbers;

    public class PowerOfNumber {

    public static void main(String[] args) {
    int base=5;
    int pow=5;
    int result=1;

    for(int i=1;i<=pow;i++){
    result=result*base;
    }
    System.out.println(result);
    }
    }


  • arman22shaikh

    package Numbers;

    public class ArmstrongNumberInRange {

    public static void main(String[] args) {

    int a=100;
    int b=1000;
    for(int i=0;i0){
    System.out.println(“null”);
    }
    }
    }
    }


  • gonnadeharsh5

    class Main {
    public static void main(String[] args) {
    System.out.println(“Enter a number and there poewr”);
    Scanner sc = new Scanner(System.in);
    int num=sc.nextInt();
    int power=sc.nextInt();
    int result=(int)Math.pow(num,power);
    System.out.println(result);
    }
    }


  • pushparaj

    package hellopackage;
    import java.util.Scanner;
    public class power {
    static int mypower(int b,int p) {
    int result=1;
    for(int i=1;i<=p;i++) {
    result*=b;
    }
    return result;
    }

    public static void main(String[] args) {

    Scanner obj=new Scanner(System.in);
    System.out.println("enter the base number");
    int base=obj.nextInt();
    System.out.println("enter the power number");
    int power=obj.nextInt();
    System.out.println("power of the number "+mypower(base,power));
    }

    }


  • shubham1822001

    using Array
    int arr[]=new int[power];
    int mul2=1;
    int print=0;
    System.out.println(num+” “+power);
    for(int i=0;i<=arr.length-1;i++)
    {
    arr[i]=num;
    mul2=mul2*arr[i];
    print=mul2;

    }
    System.out.println("result: "+print);


  • shaneesharma33

    class I
    {
    public int power(double num,double p){
    double powValue=Math.pow(num, p);
    int result = (int) powValue;
    return result;
    }
    public static void main (String[]args){
    I ob=new I();
    int res=ob.power(3,4);
    System.out.println(res);
    }
    }


  • Shital Karek

    public class power {
    public static void main(String[] args) {
    int n = 2;
    int power = 3;
    int result =1;

    for(int i =1; i<=power;i++)
    {
    result= n * result;
    }
    System.out.println("the power of " + n + " is " + result);
    }
    }


  • iamagni45

    #using recursion
    public class powFun {
    static int pow(int a, int b){
    if(b!=0)
    return a*pow(a,b-1);
    else
    return 1;
    }
    public static void main(String args[]){
    Scanner sc=new Scanner(System.in);
    int a= sc.nextInt();
    int b=sc.nextInt();
    int res=pow(a,b);
    System.out.println(res);
    }
    }


  • Debyanshu

    public class Main {
    public static void main(String[] args) {
    Scanner in = new Scanner(System.in);
    int a=in.nextInt();
    int b=in.nextInt();
    System.out.println(power(a,b));

    }
    static int power(int x,int n){
    if(x==0){
    return 0;
    }
    if(n==0){
    return 1;
    }
    int a=power(x,n-1);
    return a*x;
    }

    }


  • drakeshkumard

    import java.util.Scanner;
    public class PowerofaNum {
    public static void main(String[] args) {
    Scanner scan= new Scanner(System.in);
    System.out.print(“Enter the base :: “);
    int base=scan.nextInt();
    System.out.print(“Enter the power :: “);
    int pow=scan.nextInt();
    // Using Loop
    int mul=base;
    for (int i=1 ; i<pow ; i++){
    mul = base * mul;
    }
    System.out.println("The powered value is :: "+mul);
    }
    }