# C++ program to Find the Sum of first N natural numbers

## Natural numbers

Natural number are those number  which is start from one to infinite.

A natural number is a number that occurs commonly and obviously in nature. As such, it is a whole, non-negative number.

Example: Natural number={1,2,,4,5,6,…….}.

So we will perform the calculation Operation on Natural number using C++ programming approach. ### Implementation of Sum of N natural number in C++

First of all we will create the program of Sum of N natural number in C++.

So we will initialize sum=0 and n variable.and

the for loop using the iteration and sum=sum+i is using calculate this iteration.

and finally print the sum of N natural number.  #### Code of Sum of N natural number in C++

`#include<stdio.h> //header filesusing namespace std;int main(){    int n, sum = 0;  // varaible declaration and initialization    cout << "Enter the natural number: ";    cin >> n;  // take user input           for (int i = 1; i <= n; ++i)    {        sum = sum + i;  // calculate sum using this iteration    }        cout << "Sum = " << sum;  // print the sum of N natural number    return 0;}`
##### Output
`Enter the natural number: 8Sum=36` ### 2 comments on “C++ program to Find the Sum of first N natural numbers”

• import java.util.*;
public class SumOfNumber {
public static void main(String[] args)
{
try{
Scanner sc= new Scanner(System.in);
System.out.println(“Enter Values:”);
int n=sc.nextInt();
int sum=n*(n+1)/2;
System.out.println(“Total Sum: “+sum);
}catch(Exception e)
{
System.out.print(“Enter Numbers Only”);
}
} 0
• vaishnavi Reddy k

import java.util.*;
public class Main
{
public static void main(String[] args)
{
Scanner in=new Scanner(System.in);
int n=5,sum=0;
System.out.println(“Enter the natural number”);
for(int i=1;i<=n;i++)
{
sum=sum+i;
}
System.out.println(sum);
}
} 0