Check for Perfect Square in Java

April 30, 2022

Check for Perfect Square in Java

Here on this page, we will learn how to Check for Perfect Square in Java programming language. We are given an integer number and need to print “True” if it is, otherwise “False”.

Algorithm ( Method 1 )

Take the floor() value square root of the number.
Multiply the square root twice.
We use the Boolean equal operator to verify if the product of the square root is equal to the number given.

Java Code

Run

public class Main {

	static boolean isPerfectSquare(int x)
	{
		if (x >= 0) {
		
			int sr = (int)Math.sqrt(x);
		
			return ((sr * sr) == x);
		}
		return false;
	}

	public static void main(String[] args)
	{
		int x = 84;

		if (isPerfectSquare(x))
			System.out.print("True");
		else
			System.out.print("False");
	}
}

Output

False

Algorithm ( Method 2 )

In this method we use the floor and ceil function.
If they are equal that implies the number is a perfect square.

Run

import java.io.*;

public class Main{

static void checkperfectsquare(int n)
{
	
	if (Math.ceil((double)Math.sqrt(n)) == Math.floor((double)Math.sqrt(n)))
	{
		System.out.print("True");
	}
	else
	{
		System.out.print("False");
	}
}

public static void main(String[] args)
{
	int n = 49;
	
	checkperfectsquare(n);
}
}

Output

True

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