Capgemini Aptitude Questions Paper with Solutions 2020

Solution – Option D

Explanation:
S.I. on Rs 30000
=(30000×6×1)/100
= Rs. 1800

Profit to made on Rs 50000 = 50000×10/100=Rs 5000
--> S.I.on Rs.20000 = 5000-1800 = Rs.3200
--> Rate=(S.I.* 100)/(P * T) = (3200×100)/20000
=16% per annum

Explanation:
--> The third term t3 = a + 3d
--> The ninth term t9 = a + 8d
--> t3 + t9 = 2a + 10d = 8

Sum of first 11 terms of an AP is given by
=11/2(2a+10d)
=11/2(8)
=88/2
=44

Explanation:

Let t be the time after the departure of trains till they met.let speed of train B be x
for train A,80*t is the distance traveled from starting to till it met train B
for train be distance is x*t
x*t distance is traveled by train A in 9hours
80*t is traveled by train B in 4 hours
so x*t=80*9
and 80*t=4*x
dividing equations we get
x=120, which is the speed of train BLet t be the time after the departure of trains till they met.let speed of train B be x
for train A, 80*t is the distance traveled from starting to till it met train B
for train be distance is x*t
x*t distance is traveled by train A in 9hours
80*t is traveled by train B in 4 hours
so x*t=80*9
and 80*t=4*x
dividing equations we get,
x=120, which is the speed of train B

Explanation:

P=900
T=3
SI= 900-950=50
R= 50 x 100/900 x 3 = 50/27
now rate is increased by 4% and we have rate % 50/27 ....so new rate% is =50/27 + 4= 158/27
SI = (900 x 3 x 158)/ 100 x 27 = 158
since Si 158 and P =900 so new amount is .......900+158= 1058 ans
ans 1058

Explanation:

x/6=4
28/6=4
x=28
when 28 is divided by 4 it leaves remainder 4
similarly
y/6=5
35/6=5
y=35
(28+35)/6=63/6=3

Explanation:

x + 1/x = 6 … … … (1)

=> (x + 1/x)² = 6²

=> x² + 1/x² + 2 = 36

=> x² + 1/x² = 34 … … … (2)

we know that,

x³ + 1/x³ = (x + 1/x)³ - 3(x + 1/x)

=> x³ + 1/x³ = 6³ - 3×6

=> x³ + 1/x³ = 198 … … …(3)

Now,

(x² + 1/x²)(x³ + 1/x³) = x⁵ + 1/x + x + 1/x⁵

Putting the values from (1), (2) & (3), we get

=> 34 × 198 = x⁵ + 6 + 1/x⁵

=> 6732 = x⁵ + 1/x⁵ + 6

=> x⁵ + 1/x⁵ = 6726

Explanation:

Total age = 14* 5 = 70
age of 5 student after 5 yrs = 70 + (5*5) = 95
Avg = 95/ 5 = 19

Explanation:

ratio=sum/product
=(-b/a)/(c/a)
=-b/c=2/7
hence,b=-2 and c=7.

Explanation:

1) Student attempts x questions.
2) Out of 20 questions, he answers 15 correctly and of (x – 20) questions he answered 1/3 correctly.
3) The student gets 50 % marks.
Therefore,
15 + 1/3 (x – 20) = 50% of x

15 + 1/3 (x – 20) = 50/100 × x

15 + 1 /3 (x – 20) = x/2

90+2 (x-20)= x
Solving this equation, we get
x=50
Hence, the number of question attempted by the students = 50

Explanation:
Ratio of sides 1/2 : 1/3 : 1/5 =15 : 10 : 6
Given perimeter=155 cm , so if sides are 15x, 10x & 6x, then 15x+10x+6x =155 ,x=5
So side are 15*5=75 ,10*5=50 & 6*5=30 cm and
Difference between largest & smallest side=75 -30= 45 cm