Level Order Traversal Line by Line
Level Order Traversal Line by Line in Java
On his page we will discuss about level order traversal Line by Line in Java language . In level order traversal, we move level by level. Before moving to the next level, we first visit all the elements of present level.
Level Order Traversal Line by Line
Steps for Level Order Traversal
- Step 1 : Push the root i.e. 10 to the queue.
- Step 2 : Pop the element 10 from the queue and print it.
- Step 3 : Now, Add it’s left and right child i.e. add 20 and 30 to queue.
- Step 4 : Again pop the front element i.e. 20 from queue and print it .
- Step 5 : Add it’s left and right child i.e. 40 and 50 in the queue.
- Step 6 : Pop the element 30 from the queue and print it.
- Step 7 : Now pop all the elements from the queue and print them as there is no child of these elements.
Therefore the printing sequence will be 10 20 30 40 50.
Code in Java for Level Order Traversal Line by Line
Run
import java.util.*;
class Node
{
int data;
Node left, right;
public Node(int item)
{
data = item;
left = right = null;
}
public Node(){
data =0;
left = right = null;
}
}
// Binary tree Class
class Btree
{
public Node root;
void levelOrder(Node node)
{
if(root == null)
return;
// Create an empty queue for level order traversal
Queue queue =new LinkedList();
queue.add(root);
while(true)
{
int count = queue.size();
if(count == 0)
break;
while(count > 0)
{
Node temp = (Node)queue.poll();
System.out.print(temp.data + " ");
if(temp.left != null)
queue.add(temp.left);
if(temp.right != null)
queue.add(temp.right);
count--;
}
System.out.println();
}
}
}
public class Main{
public static void main(String[] args)
{
Btree tree = new Btree();
tree.root = new Node(1);
tree.root.left = new Node(5);
tree.root.right = new Node(4);
tree.root.left.left = new Node(9);
tree.root.left.right = new Node(7);
tree.root.right.left = new Node(10);
tree.root.right.right = new Node(13);
System.out.println("Level Order traversal of Binary Tree is ");
tree.levelOrder(tree.root);
}
}
Output
Level Order traversal of Binary Tree is 1 5 4 9 7 10 13
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- Construct a Binary Tree from Postorder and Inorder
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- Level Order Traversal – C | C++ | Java
- Construct Tree from given Inorder and Preorder traversals – C | C++ | Java
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- Binary Tree in Data Structures (Introduction)
- Tree Traversals: Inorder Postorder Preorder : C | C++ | Java
- Inorder Postorder PreOrder Traversals Examples
- Tree Traversal without Recursion
Binary Search Trees
Traversals
- Traversal in Trees
- Tree Traversals: Breadth-First Search (BFS) : C | C++ | Java
- Tree Traversals: Depth First Search (DFS) : C | C++ | Java
- Construct a Binary Tree from Postorder and Inorder
B – Trees
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Complete Programs for Trees
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- Level Order Traversal – C | C++ | Java
- Construct Tree from given Inorder and Preorder traversals – C | C++ | Java
- Construct Tree from given Postorder and Inorder traversals – C | C++ | Java
- Construct Tree from given Postorder and Preorder traversal – C | C++ | Java
- Find size of the Binary tree – C | C++ | Java
- Find the height of binary tree – C | C++ | Java
- Find maximum in binary tree – C | C++ | Java
- Check whether two tree are identical- C| C++| Java
- Spiral Order traversal of Tree- C | C++| Java
- Level Order Traversal LIne by Line – C | C++| Java
- Hand shaking lemma and some Impotant Tree Properties.
- Check If binary tree if Foldable or not.- C| C++| Java
- check whether tree is Symmetric C| C++| Java.
- Check for Children-Sum in Binary Tree- C|C++| Java
- Sum of all nodes in Binary Tree- C | C++ | Java
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