Accenture Avergaes Quiz-1

If fixed cost = x and cost per invitee = y, then
x + 40y = 200*40 or x + 40y = 8000 ----(i) &
x + 50y = 180*50 or x + 50y = 9000 ----(ii)
On solving (i) & (ii),
x=4000, y=100

45 lacs
x is number of cars sold of X type
Average revenue = \frac{(3\times x\times (51) + x\times (27))}{4\times x}
= 45 lacs.

Let the 8 members be a ,b,c,d,e,f,g,h

let the total age of 8 members 3 years ago be x.

Total age of 8 members at present = a+3+b+3+c+3+d+3+e+3+f+3+g+3+h+3 = a+b+c+d+e+f+g+h + 24

Total age of 8 members at present = x+ 24

Let y be the difference in the ages of  incoming younger member and outgoing member

So, new total = x+ 24 - y

Now we are given that average of ages of 89 members after substitution is same as average it was a 3 years ago.

So,

Correct answer:  D

Solution: Let, the sum of Paul’s two Daughter\'s age = a

Then, Paul's age = a² (given, Paul’s age is square of the sum of his daughters age)

After 4years, Paul’s daughter's age = a + 8 (2 daughter’s age)

Paul's age = a² + 4

Given, the difference between his age and his daughters ages will be 26 years.

= (a² + 4) - (a +8) = 26

= a² + 4 – a – 8 = 26

= a² - a - 30 = 0

= a² - 6a + 5a - 30 = 0 (on solving the above equation we get this)

= a(a-6) + 5(a-6)

= (a +5) (a-6)

= a = -5, 6

We know that, age can\'t be in negative form,

So, the sum of two daughter’s age will be, 6

Then, Father's age =a² = 6² = 36

Correct answer: D

Solution;

Total weight of lightest and heaviest students = 60+65= 125

Average weight of four lightest students= 60/4= 15

Average weight of 4 heaviest students = 65/4= 16.25

Overall average weight = 15+16.25= 31.25

                                          = 125/31.25= 4 kgs

Correct Option: C

Solution:

Average of any series = Sum of numbers in given series/ number of items in the series.

Hence 96+24+102+45+63/5

= 330/5 = 66

Hence C is the correct Option.

The average weight of 10 students is 55 kg.
Avg. = sum of weights ÷ total number of children

55 = sum/10

Sum of weights = 550 kg

After the new admissions...

Avg. weight of 12 students = 58 kg

58 = new sum/12

New sum of weights = 696 kg

Total weight of the new students = 696-550 = 146 kg

Avg. weight of the two new admissions = 146/2 = 73 kg

Solution:

Average of any series = Sum of numbers in given series/ number of items in the series.

Hence 22+34+56+98/4

= 210/4= 52.5

let the weight of 1 student = x kg

the weight to 15 student = 15 x kg
Let the weight of new comer = y kg.

∴ According to the question
15x - 40 + y = 15 (x + 1.5)
15x - 40 + y = 15x + 22.5
y = 62.5 kg

According to the question
The average weight of 50 students was = 45 kg
when one student leaves the class the avg. reduced by 100 gm

∴Total weight reduction due to 49 students = 49×100=4900 gm=4.9 kg

∴The weight of student who left = 45 + 4.9 = 49.9 kg