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Let the number be denoted by A.

According to the given information: A, when divided by 5, gives a remainder of 0. A, when divided by 3, gives a remainder of 2. A, when divided by 2, gives a remainder of 1.

We can use this information to find the remainder when A is successively divided by 2, 3, and 5.

Let's start with the first condition: A divided by 5 gives a remainder of 0. This implies that A is a multiple of 5.

Next, when A is divided by 3, it gives a remainder of 2. This means A leaves a remainder of 2 when divided by 3.

Now, let's consider the division by 2: Since A leaves a remainder of 1 when divided by 2, we can conclude that A is an odd number.

Now, based on the above conditions, we can determine the possible remainders when A is successively divided by 2, 3, and 5:

When an odd number is divided by 2, the remainder is always 1. When a number leaves a remainder of 2 when divided by 3, the possible remainders when the number is divided by 2 can be either 0 or 1 (as 2 divided by 3 gives a remainder of 2). When a multiple of 5 is divided by any number, the remainder is always 0.

Therefore, the possible remainders when A is successively divided by 2, 3, and 5 can be 1, 0, and 0, respectively.

To summarize, when A is divided successively by 2, 3, and 5 in that order, the remainders will be 1, 0, and 0, respectively.

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