TCS NQT Number System Questions Quiz 1

Question 1

Time: 00:00:00
Which of the following numbers must be added to 5678 to give a remainder of 35 when divided by 460?

980

980

955

955

797

797

618

618

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Question 2

Time: 00:00:00
A number when successively divided by 5, 3, 2 gives remainder 0, 2, 1 respectively in that order. What will be the remainder when the same number is divided successively by 2, 3, 5 in that order?

4, 3, 2

4, 3, 2

1, 0, 4

1, 0, 4

2, 1, 3

2, 1, 3

4, 1, 2

4, 1, 2

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if an number div by 5 and gives remainder 0 that means the number ends with 0 or 5 when the same number divided by 2 then it gives remainder 1 or 0 verify the options

Remainder will be 1,0,4 Let the Number is 55 . when divided by 5, quotient is 11 and remainder is zero. when 11 is divided by 2, quotient is 5 and remainder is 1. when 5 is divided by three, quotient is 1 and remainder is 2. when same operation is applied on 55 i.e. successively divided by 2,3,5.. we get remainders as 1,0,4 successively.

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Question 3

Time: 00:00:00
Find the least number which when divided by 12, 27 and 35 leaves 6 as a remainder?

3586

3586

3756

3756

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5678/460 remainder=158 the next no. divisible by 460 is 5678+302. we have to get remainder 35 then no be 302+35=337. as option is not there then the next number be 337+460=797 which is the correct option.

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Question 4

Time: 00:00:00
What will be the reminder when (1234567890123456789)24 is divided by 6561?

7

7

5

5

zero

zero

1

1

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Question 5

Time: 00:00:00
The remainder when m + n is divided by 12 is 8, and the remainder when m - n is divided by 12 is 6. If m > n, then what is the remainder when mn divided by 6?

3

3

4

4

2

2

1

1

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Question 6

Time: 00:00:00
A number 2088 by what if we divide the number it will become a perfect square?

58

58

20

20

28

28

29

29

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Question 7

Time: 00:00:00
For any two numbers we define an operation $ yielding another number, X $ Y such that following condition holds:
• X $ X = 0 for all X
• X $ (Y $ Z) = X $ Y + Z
Find the Value of 2012 $ 0 + 2012 $ 1912?

2112

2112

100

100

5936

5936

Can not be determined

Can not be determined

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Question 8

Time: 00:00:00
If A=x3y2 and B=xy3 then find the HCF of A, B?

x4y4

x4y4

xy2

xy2

xy

xy

x3

x3

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Question 9

Time: 00:00:00
In how many way possible ways can you write 1800 as a product of 3 positive integers X, Y , Z?

350

350

360

360

380

380

450

450

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2^3 * 5^2 * 3^2 = 1800 According to question (n+r-1) C(r-1) 2^3 = 10 5^2 = 6 3^2 = 6 10*6*6=360

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Question 10

Time: 00:00:00
Find the greatest number that will divide 148 246 and 623 leaving remainders 4 6 and 11 respectively?

20

20

12

12

6

6

48

48

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["0","40","60","80","100"]
["Need more practice! \r\n","Keep trying! \r\n","Not bad! \r\n","Good work! \r\n","Perfect! \r\n"]

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