\frac{2+3\div 2\times (2-3)\times 2+3\div 2\times 3}{2-3\div 2\times (3-2)-3+2\times 3\div 2-2}=?
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Divide 300 into two parts so that half of one part is less than the other part by 48
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Let one part be x and the other part be (300 – x). It is given that half of one part is 48 less than the other
\frac{1}{2}x=(300-x)-48
x=168
Hence, one part is 168 and the other part is = 300 – 168 = 132.
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Find the value of x in \frac{1}{x-1}+\frac{1}{x-2}=\frac{3}{x-3}
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Solution:
\frac{1}{x-1}+\frac{1}{x-2}=\frac{3}{x-3}
\frac{x-2+x-1}{x^{2}-2x-x+2}=\frac{3}{x-3}
\frac{2x-3}{x^{2}-3x+2}=\frac{3}{x-3}
3x^{2}-9x+6=2x^{2}-6x-3x+9
x^{2}=3
x=\pm \sqrt{3}
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27.33\times \left ( \frac{567.33-483.79}{58.67} \right )=?
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27.33\times \left ( \frac{567.33-483.79}{58.67} \right )=27.33(\frac{128.54}{58.67})
27.33 x 2.19=59.85
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Each member in a kitty party contributed twice as many rupees as the total number of members present and the total collection was Rs. 9248. The number of members present at the party was?
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Let the number of members in the party be x.
As, per the given condition:
Each member has given twice as many rupees as number of members,
Therefore, x × 2x = 9248
2x^{2} = 9248
x^{2} = 4624
Taking square root of both the sides,
x = 68.
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If 3 times a number exceeds its 3/5 by 60, then what is the number?
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Let the required number be x.
3x-\frac{3x}{5}=60
x=25
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For what value of K is (x-5) a factor of x^{3}-3x^{2}+kx-10
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Let f(x)=x^{3}-3x^{2}+kx-10
Now, f(x) at x=5, will be zero
So 40+5k=0
k=-8
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\frac{4}{7}\times\frac{14}{4}\div 2+6\frac{1}{3} is equal to:
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Solution:
\frac{4}{7}\times\frac{14}{4}\div 2+6\frac{1}{3}=\frac{4}{7}\times \frac{14}{4}\div 2+\frac{19}{3}
\frac{4}{7}\times \frac{7}{4}+\frac{19}{3}=1+\frac{19}{3}=\frac{22}{3}
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x^{2}+\frac{1}{x^{2}}=79 then find x+\frac{1}{x}
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(x+\frac{1}{x})^{2}=x^{2}+2+\frac{1}{x^{2}}
(x+\frac{1}{x})^{2}=79+2=81
(x+\frac{1}{x})=\pm 9
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["0","40","60","80","100"]
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