Deloitte LCM and HCF Questions and Answers Quiz-1

Question 1

Time: 00:00:00
If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

601/55

601/55

55/601

55/601

11/120

11/120

120/11

120/11

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11/120

D

as a+b=55 and a*b=5*120=600 so reciprocal is 1/a + 1/b=a+b/(a*b)=55/600

11/120

11/120

11/120

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Question 2

Time: 00:00:00
The LCM of three different numbers is 1024. Which one of the following can never be there HCF?

8

8

124

124

32

32

256

256

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124 is the answer

124

124

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Question 3

Time: 00:00:00
The least perfect square, which is divisible by each of 21, 36 and 66 is

213414

213414

213424

213424

213444

213444

213434

213434

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Question 4

Time: 00:00:00
If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other

12

12

45

45

77

77

34

34

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77

(693*11)/99=77

(693*11)/99=77

77

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Question 5

Time: 00:00:00
Which greatest possible length can be used to measure exactly 15 meter 75 cm, 11 meter 25 cm and 7 meter 65 cm

255

255

45

45

55

55

36

36

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5 c.m.

45

5

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Question 6

Time: 00:00:00
Find the greatest number which on dividing 1661 and 2045, leaves a remainder of 10 and 13 respectively?

91

91

137

137

127

127

140

140

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Question 7

Time: 00:00:00
Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds respectively. In 60 minutes how many times they will toll together?

16

16

15

15

31

31

30

30

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Question 8

Time: 00:00:00
There are three numbers, these are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. What will be the sum of three numbers :

 

67

67

129

129

85

85

19

19

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Question 9

Time: 00:00:00
Find the smallest 4 digit number which is divisible by 18, 24, 32?

1152

1152

1512

1512

1216

1216

1680

1680

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Question 10

Time: 00:00:00
What is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6?

62

62

56

56

128

128

32

32

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LCM of 3,4,5,6 = 60 So, the smallest number that leaves remainder 2 is (60+2) =62

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